Answers:
SELECT (
SELECT COUNT(*)
FROM tab1
) AS count1,
(
SELECT COUNT(*)
FROM tab2
) AS count2
FROM dual
FROM dual
。
作为附加信息,要在SQL Server中完成相同的操作,您只需删除查询的“ FROM dual”部分。
只是因为它略有不同:
SELECT 'table_1' AS table_name, COUNT(*) FROM table_1
UNION
SELECT 'table_2' AS table_name, COUNT(*) FROM table_2
UNION
SELECT 'table_3' AS table_name, COUNT(*) FROM table_3
它给出了换位的答案(每张表一行而不是一列),否则我认为这没有太大不同。我认为在性能方面,它们应该是等效的。
我看不到任何其他答案。
如果您不喜欢子查询并且在每个表中都有主键,则可以执行以下操作:
select count(distinct tab1.id) as count_t1,
count(distinct tab2.id) as count_t2
from tab1, tab2
但是从性能角度来看,我相信Quassnoi的解决方案更好,而且我会使用。
这是我分享的
选项1-从不同表中的同一域计数
select distinct(select count(*) from domain1.table1) "count1", (select count(*) from domain1.table2) "count2"
from domain1.table1, domain1.table2;
选项2-从同一表的不同域计数
select distinct(select count(*) from domain1.table1) "count1", (select count(*) from domain2.table1) "count2"
from domain1.table1, domain2.table1;
选项3-使用“全部合并”从同一表的不同域进行计数以具有计数行
select 'domain 1'"domain", count(*)
from domain1.table1
union all
select 'domain 2', count(*)
from domain2.table1;
享受SQL,我总是做:)
select
t1.Count_1,t2.Count_2
from
(SELECT count(1) as Count_1 FROM tab1) as t1,
(SELECT count(1) as Count_2 FROM tab2) as t2
select (select count(*) from tab1) count_1, (select count(*) from tab2) count_2 from dual;
出于完整性考虑,该查询将创建一个查询,以向您提供给定所有者的所有表的计数。
select
DECODE(rownum, 1, '', ' UNION ALL ') ||
'SELECT ''' || table_name || ''' AS TABLE_NAME, COUNT(*) ' ||
' FROM ' || table_name as query_string
from all_tables
where owner = :owner;
输出是这样的
SELECT 'TAB1' AS TABLE_NAME, COUNT(*) FROM TAB1
UNION ALL SELECT 'TAB2' AS TABLE_NAME, COUNT(*) FROM TAB2
UNION ALL SELECT 'TAB3' AS TABLE_NAME, COUNT(*) FROM TAB3
UNION ALL SELECT 'TAB4' AS TABLE_NAME, COUNT(*) FROM TAB4
然后可以运行以获取计数。有时只是一个方便的脚本。
如果表(或至少一个键列)的类型相同,则首先进行并集,然后进行计数。
select count(*)
from (select tab1key as key from schema.tab1
union all
select tab2key as key from schema.tab2
)
或坐下,再加上一个sum()。
select sum(amount) from
(
select count(*) amount from schema.tab1 union all select count(*) amount from schema.tab2
)
--============= FIRST WAY (Shows as Multiple Row) ===============
SELECT 'tblProducts' [TableName], COUNT(P.Id) [RowCount] FROM tblProducts P
UNION ALL
SELECT 'tblProductSales' [TableName], COUNT(S.Id) [RowCount] FROM tblProductSales S
--============== SECOND WAY (Shows in a Single Row) =============
SELECT
(SELECT COUNT(Id) FROM tblProducts) AS ProductCount,
(SELECT COUNT(Id) FROM tblProductSales) AS SalesCount
select @count = sum(data) from
(
select count(*) as data from #tempregion
union
select count(*) as data from #tempmetro
union
select count(*) as data from #tempcity
union
select count(*) as data from #tempzips
) a