Answers:
传递正则表达式作为参数:
js> "Hello awesome, world!".split(/[\s,]+/)
Hello,awesome,world!
编辑添加:
您可以通过选择数组的长度减去1来获得最后一个元素:
>>> bits = "Hello awesome, world!".split(/[\s,]+/)
["Hello", "awesome", "world!"]
>>> bit = bits[bits.length - 1]
"world!"
...,如果模式不匹配:
>>> bits = "Hello awesome, world!".split(/foo/)
["Hello awesome, world!"]
>>> bits[bits.length - 1]
"Hello awesome, world!"
              (hello world)|\|还没有奏效。有任何想法吗?
                    您可以将正则表达式传递给Javascript的split运算符。例如:
"1,2 3".split(/,| /) 
["1", "2", "3"]
或者,如果您希望允许多个分隔符一起仅充当一个分隔符:
"1, 2, , 3".split(/(?:,| )+/) 
["1", "2", "3"]
(您必须使用非捕获(?:)括号,因为否则它会被拼接回结果中。或者您可以像Aaron一样聪明,并使用字符类。)
(示例在Safari + FF中测试)
|如Jesse所示,将它们分开。
                    另一个简单但有效的方法是重复使用split + join。
"a=b,c:d".split('=').join(',').split(':').join(',').split(',')
本质上,先进行拆分再进行联接,就像全局替换一样,因此这将每个分隔符替换为逗号,然后在替换所有分隔符后对逗号进行最终拆分
上面表达式的结果是:
['a', 'b', 'c', 'd']
对此进行扩展,您还可以将其放置在函数中:
function splitMulti(str, tokens){
        var tempChar = tokens[0]; // We can use the first token as a temporary join character
        for(var i = 1; i < tokens.length; i++){
            str = str.split(tokens[i]).join(tempChar);
        }
        str = str.split(tempChar);
        return str;
}
用法:
splitMulti('a=b,c:d', ['=', ',', ':']) // ["a", "b", "c", "d"]
如果您经常使用此功能,甚至可能值得考虑包装     String.prototype.split以方便使用(我认为我的功能相当安全-唯一的考虑是条件(较小)的额外开销,以及它缺少limit参数实现的事实如果传递了数组)。
splitMulti如果对下面使用此方法只是将其包装起来,请确保包括该函数:)。还值得一提的是,有些人不愿扩展内置函数(因为很多人做错了,可能会发生冲突),因此如果有疑问,请在使用此函数之前先与更高级的人交谈或提出要求:)
    var splitOrig = String.prototype.split; // Maintain a reference to inbuilt fn
    String.prototype.split = function (){
        if(arguments[0].length > 0){
            if(Object.prototype.toString.call(arguments[0]) == "[object Array]" ) { // Check if our separator is an array
                return splitMulti(this, arguments[0]);  // Call splitMulti
            }
        }
        return splitOrig.apply(this, arguments); // Call original split maintaining context
    };
用法:
var a = "a=b,c:d";
    a.split(['=', ',', ':']); // ["a", "b", "c", "d"]
// Test to check that the built-in split still works (although our wrapper wouldn't work if it didn't as it depends on it :P)
        a.split('='); // ["a", "b,c:d"] 
请享用!
for(var i = 0; i < tokens.length; i++),而不是for(var i = 1; i < tokens.length; i++)?
                    tokens[1]保存一个迭代开始,tokens[0] == tempchar然后tempchar在迭代tokens完成后继续进行。我会相应地更新答案,谢谢@tic :)。
                    让我们保持简单:(在RegEx中添加“ [] +”表示“ 1或更多”)
这意味着“ +”和“ {1,}”相同。
var words = text.split(/[ .:;?!~,`"&|()<>{}\[\]\r\n/\\]+/); // note ' and - are kept
              棘手的方法:
var s = "dasdnk asd, (naks) :d skldma";
var a = s.replace('(',' ').replace(')',' ').replace(',',' ').split(' ');
console.log(a);//["dasdnk", "asd", "naks", ":d", "skldma"]
              '('的/(/g,以取代所有(元素- g是全球性的正则表达式标志-因此它搜索的所有事件(不是一个第一
                    对于那些想要在拆分功能中进行更多自定义的人,我编写了一个递归算法,该算法将给定的字符串与要拆分的字符列表进行拆分。我在看到以上帖子之前就写了这篇文章。我希望它可以帮助一些沮丧的程序员。
splitString = function(string, splitters) {
    var list = [string];
    for(var i=0, len=splitters.length; i<len; i++) {
        traverseList(list, splitters[i], 0);
    }
    return flatten(list);
}
traverseList = function(list, splitter, index) {
    if(list[index]) {
        if((list.constructor !== String) && (list[index].constructor === String))
            (list[index] != list[index].split(splitter)) ? list[index] = list[index].split(splitter) : null;
        (list[index].constructor === Array) ? traverseList(list[index], splitter, 0) : null;
        (list.constructor === Array) ? traverseList(list, splitter, index+1) : null;    
    }
}
flatten = function(arr) {
    return arr.reduce(function(acc, val) {
        return acc.concat(val.constructor === Array ? flatten(val) : val);
    },[]);
}
var stringToSplit = "people and_other/things";
var splitList = [" ", "_", "/"];
splitString(stringToSplit, splitList);
上面的示例返回: ["people", "and", "other", "things"]
注意:此flatten功能取自Rosetta Code 
这是在ES6中实现相同目标的新方法:
function SplitByString(source, splitBy) {
  var splitter = splitBy.split('');
  splitter.push([source]); //Push initial value
  return splitter.reduceRight(function(accumulator, curValue) {
    var k = [];
    accumulator.forEach(v => k = [...k, ...v.split(curValue)]);
    return k;
  });
}
var source = "abc,def#hijk*lmn,opq#rst*uvw,xyz";
var splitBy = ",*#";
console.log(SplitByString(source, splitBy));
请注意此功能:
source以上代码的结果将是:
我对@Brian答案的重构
var string = 'and this is some kind of information and another text and simple and some egample or red or text';
var separators = ['and', 'or'];
function splitMulti(str, separators){
            var tempChar = 't3mp'; //prevent short text separator in split down
            
            //split by regex e.g. \b(or|and)\b
            var re = new RegExp('\\b(' + separators.join('|') + ')\\b' , "g");
            str = str.replace(re, tempChar).split(tempChar);
            
            // trim & remove empty
            return str.map(el => el.trim()).filter(el => el.length > 0);
}
console.log(splitMulti(string, separators))
我认为,如果您指定要离开的内容,而不是要删除的内容,会更容易。
如果您只想使用英语单词,则可以使用以下内容:
text.match(/[a-z'\-]+/gi);
示例(运行摘要):
var R=[/[a-z'\-]+/gi,/[a-z'\-\s]+/gi];
var s=document.getElementById('s');
for(var i=0;i<R.length;i++)
 {
  var o=document.createElement('option');
  o.innerText=R[i]+'';
  o.value=i;
  s.appendChild(o);
 }
var t=document.getElementById('t');
var r=document.getElementById('r');
s.onchange=function()
 {
  r.innerHTML='';
  var x=s.value;
  if((x>=0)&&(x<R.length))
   x=t.value.match(R[x]);
  for(i=0;i<x.length;i++)
   {
    var li=document.createElement('li');
    li.innerText=x[i];
    r.appendChild(li);
   }
 }
<textarea id="t" style="width:70%;height:12em">even, test; spider-man
But saying o'er what I have said before:
My child is yet a stranger in the world;
She hath not seen the change of fourteen years,
Let two more summers wither in their pride,
Ere we may think her ripe to be a bride.
—Shakespeare, William. The Tragedy of Romeo and Juliet</textarea>
<p><select id="s">
 <option selected>Select a regular expression</option>
 <!-- option value="1">/[a-z'\-]+/gi</option>
 <option value="2">/[a-z'\-\s]+/gi</option -->
</select></p>
 <ol id="r" style="display:block;width:auto;border:1px inner;overflow:scroll;height:8em;max-height:10em;"></ol>
</div>
从@ stephen-sweriduk解决方案(对我来说更有趣!)开始,我对其进行了少许修改,以使其更加通用和可重用:
/**
 * Adapted from: http://stackoverflow.com/questions/650022/how-do-i-split-a-string-with-multiple-separators-in-javascript
*/
var StringUtils = {
  /**
   * Flatten a list of strings
   * http://rosettacode.org/wiki/Flatten_a_list
   */
  flatten : function(arr) {
    var self=this;
    return arr.reduce(function(acc, val) {
        return acc.concat(val.constructor === Array ? self.flatten(val) : val);
    },[]);
  },
  /**
   * Recursively Traverse a list and apply a function to each item
   * @param list array
   * @param expression Expression to use in func
   * @param func function of (item,expression) to apply expression to item
   *
   */
  traverseListFunc : function(list, expression, index, func) {
    var self=this;
    if(list[index]) {
        if((list.constructor !== String) && (list[index].constructor === String))
            (list[index] != func(list[index], expression)) ? list[index] = func(list[index], expression) : null;
        (list[index].constructor === Array) ? self.traverseListFunc(list[index], expression, 0, func) : null;
        (list.constructor === Array) ? self.traverseListFunc(list, expression, index+1, func) : null;
    }
  },
  /**
   * Recursively map function to string
   * @param string
   * @param expression Expression to apply to func
   * @param function of (item, expressions[i])
   */
  mapFuncToString : function(string, expressions, func) {
    var self=this;
    var list = [string];
    for(var i=0, len=expressions.length; i<len; i++) {
        self.traverseListFunc(list, expressions[i], 0, func);
    }
    return self.flatten(list);
  },
  /**
   * Split a string
   * @param splitters Array of characters to apply the split
   */
  splitString : function(string, splitters) {
    return this.mapFuncToString(string, splitters, function(item, expression) {
      return item.split(expression);
    })
  },
}
然后
var stringToSplit = "people and_other/things";
var splitList = [" ", "_", "/"];
var splittedString=StringUtils.splitString(stringToSplit, splitList);
console.log(splitList, stringToSplit, splittedString);
返回原样:
[ ' ', '_', '/' ] 'people and_other/things' [ 'people', 'and', 'other', 'things' ]
              一种简单的方法是使用每个定界符处理字符串的每个字符并构建拆分数组:
splix = function ()
{
  u = [].slice.call(arguments); v = u.slice(1); u = u[0]; w = [u]; x = 0;
  for (i = 0; i < u.length; ++i)
  {
    for (j = 0; j < v.length; ++j)
    {
      if (u.slice(i, i + v[j].length) == v[j])
      {
        y = w[x].split(v[j]); w[x] = y[0]; w[++x] = y[1];
      };
    };
  };
  return w;
};
用法:
splix(string, delimiters...)例:
splix("1.23--4", ".", "--")返回值:
["1", "23", "4"]
我将提供此类功能的经典实现。该代码几乎可以在所有JavaScript版本中使用,并且在某种程度上是最佳的。
只是纯代码:
var text = "Create a function, that will return an array (of string), with the words inside the text";
println(getWords(text));
function getWords(text)
{
    let startWord = -1;
    let ar = [];
    for(let i = 0; i <= text.length; i++)
    {
        let c = i < text.length ? text[i] : " ";
        if (!isSeparator(c) && startWord < 0)
        {
            startWord = i;
        }
        if (isSeparator(c) && startWord >= 0)
        {
            let word = text.substring(startWord, i);
            ar.push(word);
            startWord = -1;
        }
    }
    return ar;
}
function isSeparator(c)
{
    var separators = [" ", "\t", "\n", "\r", ",", ";", ".", "!", "?", "(", ")"];
    return separators.includes(c);
}
您可以看到在操场上运行的代码:https : //codeguppy.com/code.html?IJI0E4OGnkyTZnoszAzf
我不知道RegEx的性能,但是这是RegEx的另一种选择,它利用本机HashSet并以O(max(str.length,delimeter.length))复杂性工作:
var multiSplit = function(str,delimiter){
    if (!(delimiter instanceof Array))
        return str.split(delimiter);
    if (!delimiter || delimiter.length == 0)
        return [str];
    var hashSet = new Set(delimiter);
    if (hashSet.has(""))
        return str.split("");
    var lastIndex = 0;
    var result = [];
    for(var i = 0;i<str.length;i++){
        if (hashSet.has(str[i])){
            result.push(str.substring(lastIndex,i));
            lastIndex = i+1;
        }
    }
    result.push(str.substring(lastIndex));
    return result;
}
multiSplit('1,2,3.4.5.6 7 8 9',[',','.',' ']);
// Output: ["1", "2", "3", "4", "5", "6", "7", "8", "9"]
multiSplit('1,2,3.4.5.6 7 8 9',' ');
// Output: ["1,2,3.4.5.6", "7", "8", "9"]
              这不是最佳方法,但是可以使用多个不同的分隔符/分隔符进行拆分
html
<button onclick="myFunction()">Split with Multiple and Different seperators/delimiters</button>
<p id="demo"></p>
javascript
<script>
function myFunction() {
var str = "How : are | you doing : today?";
var res = str.split(' | ');
var str2 = '';
var i;
for (i = 0; i < res.length; i++) { 
    str2 += res[i];
    if (i != res.length-1) {
      str2 += ",";
    }
}
var res2 = str2.split(' : ');
//you can add countless options (with or without space)
document.getElementById("demo").innerHTML = res2;
</script>
              我使用regexp:
str =  'Write a program that extracts from a given text all palindromes, e.g. "ABBA", "lamal", "exe".';
var strNew = str.match(/\w+/g);
// Output: ["Write", "a", "program", "that", "extracts", "from", "a", "given", "text", "all", "palindromes", "e", "g", "ABBA", "lamal", "exe"]