我只是在玩同一个主题，这是访问像素的最快方法。我目前知道执行此操作的两种方法：
- 使用
getRGB()@tskuzzy的答案中所述的BufferedImage 方法。
通过直接使用以下方式访问像素数组：
byte[] pixels = ((DataBufferByte) bufferedImage.getRaster().getDataBuffer()).getData();
如果您要处理大图像并且性能是一个问题，则第一种方法绝对不是可行的方法。该getRGB()方法将alpha，红色，绿色和蓝色的值合并为一个int，然后返回结果，在大多数情况下，您将进行相反操作以将这些值取回。
第二种方法将直接为每个像素返回红色，绿色和蓝色值，如果有alpha通道，它将添加alpha值。使用这种方法在计算指标方面比较困难，但是比第一种方法要快得多。
在我的应用程序中，只需从第一种方法切换到第二种方法，就可以将像素处理时间减少90％以上！
这是我为比较两种方法而设置的比较：
import java.awt.image.BufferedImage;
import java.awt.image.DataBufferByte;
import java.io.IOException;
import javax.imageio.ImageIO;
public class PerformanceTest {
public static void main(String[] args) throws IOException {
BufferedImage hugeImage = ImageIO.read(PerformanceTest.class.getResource("12000X12000.jpg"));
System.out.println("Testing convertTo2DUsingGetRGB:");
for (int i = 0; i < 10; i++) {
long startTime = System.nanoTime();
int[][] result = convertTo2DUsingGetRGB(hugeImage);
long endTime = System.nanoTime();
System.out.println(String.format("%-2d: %s", (i + 1), toString(endTime - startTime)));
}
System.out.println("");
System.out.println("Testing convertTo2DWithoutUsingGetRGB:");
for (int i = 0; i < 10; i++) {
long startTime = System.nanoTime();
int[][] result = convertTo2DWithoutUsingGetRGB(hugeImage);
long endTime = System.nanoTime();
System.out.println(String.format("%-2d: %s", (i + 1), toString(endTime - startTime)));
}
}
private static int[][] convertTo2DUsingGetRGB(BufferedImage image) {
int width = image.getWidth();
int height = image.getHeight();
int[][] result = new int[height][width];
for (int row = 0; row < height; row++) {
for (int col = 0; col < width; col++) {
result[row][col] = image.getRGB(col, row);
}
}
return result;
}
private static int[][] convertTo2DWithoutUsingGetRGB(BufferedImage image) {
final byte[] pixels = ((DataBufferByte) image.getRaster().getDataBuffer()).getData();
final int width = image.getWidth();
final int height = image.getHeight();
final boolean hasAlphaChannel = image.getAlphaRaster() != null;
int[][] result = new int[height][width];
if (hasAlphaChannel) {
final int pixelLength = 4;
for (int pixel = 0, row = 0, col = 0; pixel + 3 < pixels.length; pixel += pixelLength) {
int argb = 0;
argb += (((int) pixels[pixel] & 0xff) << 24); // alpha
argb += ((int) pixels[pixel + 1] & 0xff); // blue
argb += (((int) pixels[pixel + 2] & 0xff) << 8); // green
argb += (((int) pixels[pixel + 3] & 0xff) << 16); // red
result[row][col] = argb;
col++;
if (col == width) {
col = 0;
row++;
}
}
} else {
final int pixelLength = 3;
for (int pixel = 0, row = 0, col = 0; pixel + 2 < pixels.length; pixel += pixelLength) {
int argb = 0;
argb += -16777216; // 255 alpha
argb += ((int) pixels[pixel] & 0xff); // blue
argb += (((int) pixels[pixel + 1] & 0xff) << 8); // green
argb += (((int) pixels[pixel + 2] & 0xff) << 16); // red
result[row][col] = argb;
col++;
if (col == width) {
col = 0;
row++;
}
}
}
return result;
}
private static String toString(long nanoSecs) {
int minutes = (int) (nanoSecs / 60000000000.0);
int seconds = (int) (nanoSecs / 1000000000.0) - (minutes * 60);
int millisecs = (int) ( ((nanoSecs / 1000000000.0) - (seconds + minutes * 60)) * 1000);
if (minutes == 0 && seconds == 0)
return millisecs + "ms";
else if (minutes == 0 && millisecs == 0)
return seconds + "s";
else if (seconds == 0 && millisecs == 0)
return minutes + "min";
else if (minutes == 0)
return seconds + "s " + millisecs + "ms";
else if (seconds == 0)
return minutes + "min " + millisecs + "ms";
else if (millisecs == 0)
return minutes + "min " + seconds + "s";
return minutes + "min " + seconds + "s " + millisecs + "ms";
}
}
你能猜出输出吗？;）
Testing convertTo2DUsingGetRGB:
1 : 16s 911ms
2 : 16s 730ms
3 : 16s 512ms
4 : 16s 476ms
5 : 16s 503ms
6 : 16s 683ms
7 : 16s 477ms
8 : 16s 373ms
9 : 16s 367ms
10: 16s 446ms
Testing convertTo2DWithoutUsingGetRGB:
1 : 1s 487ms
2 : 1s 940ms
3 : 1s 785ms
4 : 1s 848ms
5 : 1s 624ms
6 : 2s 13ms
7 : 1s 968ms
8 : 1s 864ms
9 : 1s 673ms
10: 2s 86ms
BUILD SUCCESSFUL (total time: 3 minutes 10 seconds)
getRGB和setRGB直接复制？