Answers:
将此用于旧代码（PHP <5.3）。有关最新解决方案，请参见下面的jurka答案
您可以使用strtotime（）将两个日期转换为Unix时间，然后计算它们之间的秒数。由此很容易计算出不同的时间段。
$date1 = "2007-03-24";
$date2 = "2009-06-26";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);编辑：显然，执行此操作的首选方法如下面的jurka所述。通常，仅当您没有PHP 5.3或更高版本时才建议使用我的代码。
评论中的几个人指出，上面的代码只是一个近似值。我仍然认为，对于大多数目的来说，这是很好的，因为使用范围更多的是为了提供经过或保留了多少时间的感觉，而不是提供精度-如果要这样做，只需输出日期即可。
尽管如此，我还是决定解决这些投诉。如果您确实需要一个确切的范围，但无法访问PHP 5.3，请使用下面的代码（它也应在PHP 4中工作）。这是PHP内部用于计算范围的代码的直接端口，不同之处在于它不考虑夏令时。这意味着它最多可以关闭一个小时，但是除了它应该是正确的之外。
<?php
/**
* Calculate differences between two dates with precise semantics. Based on PHPs DateTime::diff()
* implementation by Derick Rethans. Ported to PHP by Emil H, 2011-05-02. No rights reserved.
*
* See here for original code:
* http://svn.php.net/viewvc/php/php-src/trunk/ext/date/lib/tm2unixtime.c?revision=302890&view=markup
* http://svn.php.net/viewvc/php/php-src/trunk/ext/date/lib/interval.c?revision=298973&view=markup
*/
function _date_range_limit($start, $end, $adj, $a, $b, $result)
{
if ($result[$a] < $start) {
$result[$b] -= intval(($start - $result[$a] - 1) / $adj) + 1;
$result[$a] += $adj * intval(($start - $result[$a] - 1) / $adj + 1);
}
if ($result[$a] >= $end) {
$result[$b] += intval($result[$a] / $adj);
$result[$a] -= $adj * intval($result[$a] / $adj);
}
return $result;
}
function _date_range_limit_days($base, $result)
{
$days_in_month_leap = array(31, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
$days_in_month = array(31, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
_date_range_limit(1, 13, 12, "m", "y", &$base);
$year = $base["y"];
$month = $base["m"];
if (!$result["invert"]) {
while ($result["d"] < 0) {
$month--;
if ($month < 1) {
$month += 12;
$year--;
}
$leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
$days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
$result["d"] += $days;
$result["m"]--;
}
} else {
while ($result["d"] < 0) {
$leapyear = $year % 400 == 0 || ($year % 100 != 0 && $year % 4 == 0);
$days = $leapyear ? $days_in_month_leap[$month] : $days_in_month[$month];
$result["d"] += $days;
$result["m"]--;
$month++;
if ($month > 12) {
$month -= 12;
$year++;
}
}
}
return $result;
}
function _date_normalize($base, $result)
{
$result = _date_range_limit(0, 60, 60, "s", "i", $result);
$result = _date_range_limit(0, 60, 60, "i", "h", $result);
$result = _date_range_limit(0, 24, 24, "h", "d", $result);
$result = _date_range_limit(0, 12, 12, "m", "y", $result);
$result = _date_range_limit_days(&$base, &$result);
$result = _date_range_limit(0, 12, 12, "m", "y", $result);
return $result;
}
/**
* Accepts two unix timestamps.
*/
function _date_diff($one, $two)
{
$invert = false;
if ($one > $two) {
list($one, $two) = array($two, $one);
$invert = true;
}
$key = array("y", "m", "d", "h", "i", "s");
$a = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $one))));
$b = array_combine($key, array_map("intval", explode(" ", date("Y m d H i s", $two))));
$result = array();
$result["y"] = $b["y"] - $a["y"];
$result["m"] = $b["m"] - $a["m"];
$result["d"] = $b["d"] - $a["d"];
$result["h"] = $b["h"] - $a["h"];
$result["i"] = $b["i"] - $a["i"];
$result["s"] = $b["s"] - $a["s"];
$result["invert"] = $invert ? 1 : 0;
$result["days"] = intval(abs(($one - $two)/86400));
if ($invert) {
_date_normalize(&$a, &$result);
} else {
_date_normalize(&$b, &$result);
}
return $result;
}
$date = "1986-11-10 19:37:22";
print_r(_date_diff(strtotime($date), time()));
print_r(_date_diff(time(), strtotime($date)));&签名。
我建议使用DateTime和DateInterval对象。
$date1 = new DateTime("2007-03-24");
$date2 = new DateTime("2009-06-26");
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";
// shows the total amount of days (not divided into years, months and days like above)
echo "difference " . $interval->days . " days ";从手册中：
从PHP 5.2.2开始，可以使用比较运算符比较DateTime对象。
$date1 = new DateTime("now");
$date2 = new DateTime("tomorrow");
var_dump($date1 == $date2); // bool(false)
var_dump($date1 < $date2); // bool(true)
var_dump($date1 > $date2); // bool(false)$date2->format('U') - $date1->format('U')。
最好的做法是使用PHP的DateTime（和DateInterval）对象。每个日期都封装在一个DateTime对象中，然后可以区分两者：
$first_date = new DateTime("2012-11-30 17:03:30");
$second_date = new DateTime("2012-12-21 00:00:00");该DateTime对象将接受任何格式strtotime()。如果需要甚至更特定的日期格式，DateTime::createFromFormat()则可以用来创建DateTime对象。
实例化两个对象之后，您可以用彼此减去一个对象DateTime::diff()。
$difference = $first_date->diff($second_date);$difference现在持有DateInterval带有差异信息的对象。一个var_dump()看起来像这样：
object(DateInterval)
public 'y' => int 0
public 'm' => int 0
public 'd' => int 20
public 'h' => int 6
public 'i' => int 56
public 's' => int 30
public 'invert' => int 0
public 'days' => int 20要格式化DateInterval对象，我们需要检查每个值，如果值为0，则将其排除：
/**
* Format an interval to show all existing components.
* If the interval doesn't have a time component (years, months, etc)
* That component won't be displayed.
*
* @param DateInterval $interval The interval
*
* @return string Formatted interval string.
*/
function format_interval(DateInterval $interval) {
$result = "";
if ($interval->y) { $result .= $interval->format("%y years "); }
if ($interval->m) { $result .= $interval->format("%m months "); }
if ($interval->d) { $result .= $interval->format("%d days "); }
if ($interval->h) { $result .= $interval->format("%h hours "); }
if ($interval->i) { $result .= $interval->format("%i minutes "); }
if ($interval->s) { $result .= $interval->format("%s seconds "); }
return $result;
}现在剩下的就是在$difference DateInterval对象上调用我们的函数了：
echo format_interval($difference);并且我们得到正确的结果：
20天6小时56分30秒
用于实现目标的完整代码：
/**
* Format an interval to show all existing components.
* If the interval doesn't have a time component (years, months, etc)
* That component won't be displayed.
*
* @param DateInterval $interval The interval
*
* @return string Formatted interval string.
*/
function format_interval(DateInterval $interval) {
$result = "";
if ($interval->y) { $result .= $interval->format("%y years "); }
if ($interval->m) { $result .= $interval->format("%m months "); }
if ($interval->d) { $result .= $interval->format("%d days "); }
if ($interval->h) { $result .= $interval->format("%h hours "); }
if ($interval->i) { $result .= $interval->format("%i minutes "); }
if ($interval->s) { $result .= $interval->format("%s seconds "); }
return $result;
}
$first_date = new DateTime("2012-11-30 17:03:30");
$second_date = new DateTime("2012-12-21 00:00:00");
$difference = $first_date->diff($second_date);
echo format_interval($difference);DateTime()不是函数，而是对象，从PHP 5.2开始就存在。确保您的服务器支持它。
查看小时，分钟和秒..
$date1 = "2008-11-01 22:45:00";
$date2 = "2009-12-04 13:44:01";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));
$minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds); 看一下以下链接。这是我到目前为止找到的最好的答案.. :)
function dateDiff ($d1, $d2) {
// Return the number of days between the two dates:
return round(abs(strtotime($d1) - strtotime($d2))/86400);
} // end function dateDiff传递date参数时，哪个日期更早或更晚并不重要。该函数使用PHP ABS（）绝对值来始终返回一个正数作为两个日期之间的天数。
请记住，两个日期之间的天数不包括两个日期。因此，如果要查找由介于输入的日期之间（包括输入的日期）的所有日期表示的天数，则需要在此函数的结果中加上一（1）。
例如，2013-02-09与2013-02-14之间的差（由上述函数返回）为5。但是，日期范围为2013-02-09-2013-02-的天数或日期数14是6。
我投票赞成jurka的答案，因为这是我的最爱，但是我有php.5.3之前的版本...
我发现自己正在研究类似的问题-首先就是如何解决这个问题-但只需要几个小时即可。但是我的函数也很好地解决了这个问题，并且我自己的库中没有任何地方可以将其保存在不会丢失和遗忘的地方，所以...希望这对某人有用。
/**
*
* @param DateTime $oDate1
* @param DateTime $oDate2
* @return array
*/
function date_diff_array(DateTime $oDate1, DateTime $oDate2) {
$aIntervals = array(
'year' => 0,
'month' => 0,
'week' => 0,
'day' => 0,
'hour' => 0,
'minute' => 0,
'second' => 0,
);
foreach($aIntervals as $sInterval => &$iInterval) {
while($oDate1 <= $oDate2){
$oDate1->modify('+1 ' . $sInterval);
if ($oDate1 > $oDate2) {
$oDate1->modify('-1 ' . $sInterval);
break;
} else {
$iInterval++;
}
}
}
return $aIntervals;
}和测试：
$oDate = new DateTime();
$oDate->modify('+111402189 seconds');
var_dump($oDate);
var_dump(date_diff_array(new DateTime(), $oDate));结果：
object(DateTime)[2]
public 'date' => string '2014-04-29 18:52:51' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'America/New_York' (length=16)
array
'year' => int 3
'month' => int 6
'week' => int 1
'day' => int 4
'hour' => int 9
'minute' => int 3
'second' => int 8我从这里得到了最初的想法，并对其进行了修改以供使用（我希望我的修改也将显示在该页面上）。
您可以通过从$aIntervals数组中删除不需要的间隔（例如“周”），或者添加一个$aExclude参数，或者在输出字符串时将其过滤掉，来轻松删除它们。
week索引$aIntervals（因为DateDiff从不使用该索引）。
我不知道您是否正在使用PHP框架，但是许多PHP框架具有日期/时间库和帮助程序，以帮助您避免重新发明轮子。
例如，CodeIgniter具有此timespan()功能。只需输入两个Unix时间戳，它将自动生成如下结果：
1 Year, 10 Months, 2 Weeks, 5 Days, 10 Hours, 16 Minutesecho time_diff_string('2013-05-01 00:22:35', 'now');
echo time_diff_string('2013-05-01 00:22:35', 'now', true);4 months ago
4 months, 2 weeks, 3 days, 1 hour, 49 minutes, 15 seconds agofunction time_diff_string($from, $to, $full = false) {
$from = new DateTime($from);
$to = new DateTime($to);
$diff = $to->diff($from);
$diff->w = floor($diff->d / 7);
$diff->d -= $diff->w * 7;
$string = array(
'y' => 'year',
'm' => 'month',
'w' => 'week',
'd' => 'day',
'h' => 'hour',
'i' => 'minute',
's' => 'second',
);
foreach ($string as $k => &$v) {
if ($diff->$k) {
$v = $diff->$k . ' ' . $v . ($diff->$k > 1 ? 's' : '');
} else {
unset($string[$k]);
}
}
if (!$full) $string = array_slice($string, 0, 1);
return $string ? implode(', ', $string) . ' ago' : 'just now';
}我对此有一些简单的逻辑：
<?php
per_days_diff('2011-12-12','2011-12-29')
function per_days_diff($start_date, $end_date) {
$per_days = 0;
$noOfWeek = 0;
$noOfWeekEnd = 0;
$highSeason=array("7", "8");
$current_date = strtotime($start_date);
$current_date += (24 * 3600);
$end_date = strtotime($end_date);
$seassion = (in_array(date('m', $current_date), $highSeason))?"2":"1";
$noOfdays = array('');
while ($current_date <= $end_date) {
if ($current_date <= $end_date) {
$date = date('N', $current_date);
array_push($noOfdays,$date);
$current_date = strtotime('+1 day', $current_date);
}
}
$finalDays = array_shift($noOfdays);
//print_r($noOfdays);
$weekFirst = array("week"=>array(),"weekEnd"=>array());
for($i = 0; $i < count($noOfdays); $i++)
{
if ($noOfdays[$i] == 1)
{
//echo "This is week";
//echo "<br/>";
if($noOfdays[$i+6]==7)
{
$noOfWeek++;
$i=$i+6;
}
else
{
$per_days++;
}
//array_push($weekFirst["week"],$day);
}
else if($noOfdays[$i]==5)
{
//echo "This is weekend";
//echo "<br/>";
if($noOfdays[$i+2] ==7)
{
$noOfWeekEnd++;
$i = $i+2;
}
else
{
$per_days++;
}
//echo "After weekend value:- ".$i;
//echo "<br/>";
}
else
{
$per_days++;
}
}
/*echo $noOfWeek;
echo "<br/>";
echo $noOfWeekEnd;
echo "<br/>";
print_r($per_days);
echo "<br/>";
print_r($weekFirst);
*/
$duration = array("weeks"=>$noOfWeek, "weekends"=>$noOfWeekEnd, "perDay"=>$per_days, "seassion"=>$seassion);
return $duration;
?>您可以使用
getdate()该函数返回一个数组，其中包含提供的日期/时间的所有元素：
$diff = abs($endDate - $startDate);
$my_t=getdate($diff);
print("$my_t[year] years, $my_t[month] months and $my_t[mday] days");如果您的开始日期和结束日期为字符串格式，请使用
$startDate = strtotime($startDateStr);
$endDate = strtotime($endDateStr);以上代码之前
$my_t["year"] -= 1970以获得正确的年数。您还需要从格林尼治标准时间中减去您的时差，以正确计算小时数。您还需要从月份和日期中减去1。
// If you just want to see the year difference then use this function.
// Using the logic I've created you may also create month and day difference
// which I did not provide here so you may have the efforts to use your brain.
// :)
$date1='2009-01-01';
$date2='2010-01-01';
echo getYearDifference ($date1,$date2);
function getYearDifference($date1=strtotime($date1),$date2=strtotime($date2)){
$year = 0;
while($date2 > $date1 = strtotime('+1 year', $date1)){
++$year;
}
return $year;
}这是我的职责 必需的PHP> = 5.3.4。它使用DateTime类。速度非常快，而且可以在两个日期之间，甚至在所谓的“自此之后的时间”之间进行区别。
if(function_exists('grk_Datetime_Since') === FALSE){
function grk_Datetime_Since($From, $To='', $Prefix='', $Suffix=' ago', $Words=array()){
# Est-ce qu'on calcul jusqu'à un moment précis ? Probablement pas, on utilise maintenant
if(empty($To) === TRUE){
$To = time();
}
# On va s'assurer que $From est numérique
if(is_int($From) === FALSE){
$From = strtotime($From);
};
# On va s'assurer que $To est numérique
if(is_int($To) === FALSE){
$To = strtotime($To);
}
# On a une erreur ?
if($From === FALSE OR $From === -1 OR $To === FALSE OR $To === -1){
return FALSE;
}
# On va créer deux objets de date
$From = new DateTime(@date('Y-m-d H:i:s', $From), new DateTimeZone('GMT'));
$To = new DateTime(@date('Y-m-d H:i:s', $To), new DateTimeZone('GMT'));
# On va calculer la différence entre $From et $To
if(($Diff = $From->diff($To)) === FALSE){
return FALSE;
}
# On va merger le tableau des noms (par défaut, anglais)
$Words = array_merge(array(
'year' => 'year',
'years' => 'years',
'month' => 'month',
'months' => 'months',
'week' => 'week',
'weeks' => 'weeks',
'day' => 'day',
'days' => 'days',
'hour' => 'hour',
'hours' => 'hours',
'minute' => 'minute',
'minutes' => 'minutes',
'second' => 'second',
'seconds' => 'seconds'
), $Words);
# On va créer la chaîne maintenant
if($Diff->y > 1){
$Text = $Diff->y.' '.$Words['years'];
} elseif($Diff->y == 1){
$Text = '1 '.$Words['year'];
} elseif($Diff->m > 1){
$Text = $Diff->m.' '.$Words['months'];
} elseif($Diff->m == 1){
$Text = '1 '.$Words['month'];
} elseif($Diff->d > 7){
$Text = ceil($Diff->d/7).' '.$Words['weeks'];
} elseif($Diff->d == 7){
$Text = '1 '.$Words['week'];
} elseif($Diff->d > 1){
$Text = $Diff->d.' '.$Words['days'];
} elseif($Diff->d == 1){
$Text = '1 '.$Words['day'];
} elseif($Diff->h > 1){
$Text = $Diff->h.' '.$Words['hours'];
} elseif($Diff->h == 1){
$Text = '1 '.$Words['hour'];
} elseif($Diff->i > 1){
$Text = $Diff->i.' '.$Words['minutes'];
} elseif($Diff->i == 1){
$Text = '1 '.$Words['minute'];
} elseif($Diff->s > 1){
$Text = $Diff->s.' '.$Words['seconds'];
} else {
$Text = '1 '.$Words['second'];
}
return $Prefix.$Text.$Suffix;
}
}我更喜欢使用date_create和date_diff对象。
码：
$date1 = date_create("2007-03-24");
$date2 = date_create("2009-06-26");
$dateDifference = date_diff($date1, $date2)->format('%y years, %m months and %d days');
echo $dateDifference;输出：
2 years, 3 months and 2 days有关更多信息，请阅读PHP date_diff手册。
根据手册
date_diff是DateTime :: diff（）的别名
这将尝试检测是否已提供时间戳记，并将将来的日期/时间作为负值返回：
<?php
function time_diff($start, $end = NULL, $convert_to_timestamp = FALSE) {
// If $convert_to_timestamp is not explicitly set to TRUE,
// check to see if it was accidental:
if ($convert_to_timestamp || !is_numeric($start)) {
// If $convert_to_timestamp is TRUE, convert to timestamp:
$timestamp_start = strtotime($start);
}
else {
// Otherwise, leave it as a timestamp:
$timestamp_start = $start;
}
// Same as above, but make sure $end has actually been overridden with a non-null,
// non-empty, non-numeric value:
if (!is_null($end) && (!empty($end) && !is_numeric($end))) {
$timestamp_end = strtotime($end);
}
else {
// If $end is NULL or empty and non-numeric value, assume the end time desired
// is the current time (useful for age, etc):
$timestamp_end = time();
}
// Regardless, set the start and end times to an integer:
$start_time = (int) $timestamp_start;
$end_time = (int) $timestamp_end;
// Assign these values as the params for $then and $now:
$start_time_var = 'start_time';
$end_time_var = 'end_time';
// Use this to determine if the output is positive (time passed) or negative (future):
$pos_neg = 1;
// If the end time is at a later time than the start time, do the opposite:
if ($end_time <= $start_time) {
$start_time_var = 'end_time';
$end_time_var = 'start_time';
$pos_neg = -1;
}
// Convert everything to the proper format, and do some math:
$then = new DateTime(date('Y-m-d H:i:s', $$start_time_var));
$now = new DateTime(date('Y-m-d H:i:s', $$end_time_var));
$years_then = $then->format('Y');
$years_now = $now->format('Y');
$years = $years_now - $years_then;
$months_then = $then->format('m');
$months_now = $now->format('m');
$months = $months_now - $months_then;
$days_then = $then->format('d');
$days_now = $now->format('d');
$days = $days_now - $days_then;
$hours_then = $then->format('H');
$hours_now = $now->format('H');
$hours = $hours_now - $hours_then;
$minutes_then = $then->format('i');
$minutes_now = $now->format('i');
$minutes = $minutes_now - $minutes_then;
$seconds_then = $then->format('s');
$seconds_now = $now->format('s');
$seconds = $seconds_now - $seconds_then;
if ($seconds < 0) {
$minutes -= 1;
$seconds += 60;
}
if ($minutes < 0) {
$hours -= 1;
$minutes += 60;
}
if ($hours < 0) {
$days -= 1;
$hours += 24;
}
$months_last = $months_now - 1;
if ($months_now == 1) {
$years_now -= 1;
$months_last = 12;
}
// "Thirty days hath September, April, June, and November" ;)
if ($months_last == 9 || $months_last == 4 || $months_last == 6 || $months_last == 11) {
$days_last_month = 30;
}
else if ($months_last == 2) {
// Factor in leap years:
if (($years_now % 4) == 0) {
$days_last_month = 29;
}
else {
$days_last_month = 28;
}
}
else {
$days_last_month = 31;
}
if ($days < 0) {
$months -= 1;
$days += $days_last_month;
}
if ($months < 0) {
$years -= 1;
$months += 12;
}
// Finally, multiply each value by either 1 (in which case it will stay the same),
// or by -1 (in which case it will become negative, for future dates).
// Note: 0 * 1 == 0 * -1 == 0
$out = new stdClass;
$out->years = (int) $years * $pos_neg;
$out->months = (int) $months * $pos_neg;
$out->days = (int) $days * $pos_neg;
$out->hours = (int) $hours * $pos_neg;
$out->minutes = (int) $minutes * $pos_neg;
$out->seconds = (int) $seconds * $pos_neg;
return $out;
}用法示例：
<?php
$birthday = 'June 2, 1971';
$check_age_for_this_date = 'June 3, 1999 8:53pm';
$age = time_diff($birthday, $check_age_for_this_date)->years;
print $age;// 28要么：
<?php
$christmas_2020 = 'December 25, 2020';
$countdown = time_diff($christmas_2020);
print_r($countdown);“如果”日期存储在MySQL中，我发现在数据库级别更容易进行差值计算...然后根据日，时，分，秒输出，适当地解析和显示结果...
mysql> select firstName, convert_tz(loginDate, '+00:00', '-04:00') as loginDate, TIMESTAMPDIFF(DAY, loginDate, now()) as 'Day', TIMESTAMPDIFF(HOUR, loginDate, now())+4 as 'Hour', TIMESTAMPDIFF(MINUTE, loginDate, now())+(60*4) as 'Min', TIMESTAMPDIFF(SECOND, loginDate, now())+(60*60*4) as 'Sec' from User_ where userId != '10158' AND userId != '10198' group by emailAddress order by loginDate desc;
+-----------+---------------------+------+------+------+--------+
| firstName | loginDate | Day | Hour | Min | Sec |
+-----------+---------------------+------+------+------+--------+
| Peter | 2014-03-30 18:54:40 | 0 | 4 | 244 | 14644 |
| Keith | 2014-03-30 18:54:11 | 0 | 4 | 244 | 14673 |
| Andres | 2014-03-28 09:20:10 | 2 | 61 | 3698 | 221914 |
| Nadeem | 2014-03-26 09:33:43 | 4 | 109 | 6565 | 393901 |
+-----------+---------------------+------+------+------+--------+
4 rows in set (0.00 sec)我在下一页找到了您的文章，其中包含许多有关PHP日期时间计算的参考。
使用PHP计算两个日期（和时间）之间的时差。下一页提供了一系列不同的方法（总共7种），用于使用PHP执行日期/时间计算，以确定两个日期之间的时间（小时，小时），天，月或年之间的时差。
您还可以使用以下代码按$ date1 = $ duedate的舍入分数返回日期差异。//指定到期日echo $ date2 = date（“ Ymd”）; //当前日期$ ts1 = strtotime（$ date1）; $ ts2 = strtotime（$ date2）; $ seconds_diff = $ ts1-$ ts2; echo $ datediff = ceil（（$ seconds_diff / 3600）/ 24）; //几天后返回
如果您使用php的floor方法而不是ceil，它将使您的舍入分数降低。如果您的登台服务器时区与实时站点时区不同，请有时在此处检查差异，在这种情况下，您可能会得到不同的结果，因此请相应地更改条件。
您可以始终使用以下函数来返回以年和月为单位的年龄（即1年4个月）
function getAge($dob, $age_at_date)
{
$d1 = new DateTime($dob);
$d2 = new DateTime($age_at_date);
$age = $d2->diff($d1);
$years = $age->y;
$months = $age->m;
return $years.'.'.months;
}或者，如果您希望在当前日期计算年龄，则可以使用
function getAge($dob)
{
$d1 = new DateTime($dob);
$d2 = new DateTime(date());
$age = $d2->diff($d1);
$years = $age->y;
$months = $age->m;
return $years.'.'.months;
}对于PHP版本> = 5.3：创建两个日期对象，然后使用date_diff()function。它将返回php DateInterval对象。参见文档
$date1=date_create("2007-03-24");
$date2=date_create("2009-06-26");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");我在PHP 5.2中遇到了同样的问题，并在MySQL中解决了。可能不完全是您要查找的内容，但这可以解决问题并返回天数：
$datediff_q = $dbh->prepare("SELECT DATEDIFF(:date2, :date1)");
$datediff_q->bindValue(':date1', '2007-03-24', PDO::PARAM_STR);
$datediff_q->bindValue(':date2', '2009-06-26', PDO::PARAM_STR);
$datediff = ($datediff_q->execute()) ? $datediff_q->fetchColumn(0) : false;此处的更多信息http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_datediff
由于每个人都在发布代码示例，因此这里是另一个版本。
我想要一个函数来显示从几秒到几年的差异（仅一个单位）。对于超过1天的时间段，我希望它在午夜滚动（星期一10am从星期三9am开始是2天，而不是1天）。对于一个月以上的时间段，我希望将过渡时间设置在每月的同一天（包括30/31天的月份和＆年）。
这是我想出的：
/**
* Returns how long ago something happened in the past, showing it
* as n seconds / minutes / hours / days / weeks / months / years ago.
*
* For periods over a day, it rolls over at midnight (so doesn't depend
* on current time of day), and it correctly accounts for month-lengths
* and leap-years (months and years rollover on current day of month).
*
* $param string $timestamp in DateTime format
* $return string description of interval
*/
function ago($timestamp)
{
$then = date_create($timestamp);
// for anything over 1 day, make it rollover on midnight
$today = date_create('tomorrow'); // ie end of today
$diff = date_diff($then, $today);
if ($diff->y > 0) return $diff->y.' year'.($diff->y>1?'s':'').' ago';
if ($diff->m > 0) return $diff->m.' month'.($diff->m>1?'s':'').' ago';
$diffW = floor($diff->d / 7);
if ($diffW > 0) return $diffW.' week'.($diffW>1?'s':'').' ago';
if ($diff->d > 1) return $diff->d.' day'.($diff->d>1?'s':'').' ago';
// for anything less than 1 day, base it off 'now'
$now = date_create();
$diff = date_diff($then, $now);
if ($diff->d > 0) return 'yesterday';
if ($diff->h > 0) return $diff->h.' hour'.($diff->h>1?'s':'').' ago';
if ($diff->i > 0) return $diff->i.' minute'.($diff->i>1?'s':'').' ago';
return $diff->s.' second'.($diff->s==1?'':'s').' ago';
}前段时间我写了一个format_date函数，因为它为您提供了多种约会方式：
function format_date($date, $type, $seperator="-")
{
if($date)
{
$day = date("j", strtotime($date));
$month = date("n", strtotime($date));
$year = date("Y", strtotime($date));
$hour = date("H", strtotime($date));
$min = date("i", strtotime($date));
$sec = date("s", strtotime($date));
switch($type)
{
case 0: $date = date("Y".$seperator."m".$seperator."d",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 1: $date = date("D, F j, Y",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 2: $date = date("d".$seperator."m".$seperator."Y",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 3: $date = date("d".$seperator."M".$seperator."Y",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 4: $date = date("d".$seperator."M".$seperator."Y h:i A",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 5: $date = date("m".$seperator."d".$seperator."Y",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 6: $date = date("M",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 7: $date = date("Y",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 8: $date = date("j",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 9: $date = date("n",mktime($hour, $min, $sec, $month, $day, $year)); break;
case 10:
$diff = abs(strtotime($date) - strtotime(date("Y-m-d h:i:s")));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$date = $years . " years, " . $months . " months, " . $days . "days";
}
}
return($date);
} 很简单：
<?php
$date1 = date_create("2007-03-24");
echo "Start date: ".$date1->format("Y-m-d")."<br>";
$date2 = date_create("2009-06-26");
echo "End date: ".$date2->format("Y-m-d")."<br>";
$diff = date_diff($date1,$date2);
echo "Difference between start date and end date: ".$diff->format("%y years, %m months and %d days")."<br>";
?>请查看以下链接以获取详细信息：
请注意，它适用于PHP 5.3.0或更高版本。
一个简单的功能
function time_difference($time_1, $time_2, $limit = null)
{
$val_1 = new DateTime($time_1);
$val_2 = new DateTime($time_2);
$interval = $val_1->diff($val_2);
$output = array(
"year" => $interval->y,
"month" => $interval->m,
"day" => $interval->d,
"hour" => $interval->h,
"minute" => $interval->i,
"second" => $interval->s
);
$return = "";
foreach ($output AS $key => $value) {
if ($value == 1)
$return .= $value . " " . $key . " ";
elseif ($value >= 1)
$return .= $value . " " . $key . "s ";
if ($key == $limit)
return trim($return);
}
return trim($return);
}使用方式
echo time_difference ($time_1, $time_2, "day");
会像 2 years 8 months 2 days
使用date_diff（）尝试这个非常简单的答案，这已经过测试。
$date1 = date_create("2017-11-27");
$date2 = date_create("2018-12-29");
$diff=date_diff($date1,$date2);
$months = $diff->format("%m months");
$years = $diff->format("%y years");
$days = $diff->format("%d days");
echo $years .' '.$months.' '.$days;输出为：
1 years 1 months 2 days当PHP 5.3（分别为date_diff（））不可用时，我使用的是我编写的以下函数：
function dateDifference($startDate, $endDate)
{
$startDate = strtotime($startDate);
$endDate = strtotime($endDate);
if ($startDate === false || $startDate < 0 || $endDate === false || $endDate < 0 || $startDate > $endDate)
return false;
$years = date('Y', $endDate) - date('Y', $startDate);
$endMonth = date('m', $endDate);
$startMonth = date('m', $startDate);
// Calculate months
$months = $endMonth - $startMonth;
if ($months <= 0) {
$months += 12;
$years--;
}
if ($years < 0)
return false;
// Calculate the days
$measure = ($months == 1) ? 'month' : 'months';
$days = $endDate - strtotime('+' . $months . ' ' . $measure, $startDate);
$days = date('z', $days);
return array($years, $months, $days);
}DateInterval 很棒，但有一些警告：
为了克服这个问题，我编写了以下代码（从@enobrev answer改进）：
function date_dif($since, $until, $keys = 'year|month|week|day|hour|minute|second')
{
$date = array_map('strtotime', array($since, $until));
if ((count($date = array_filter($date, 'is_int')) == 2) && (sort($date) === true))
{
$result = array_fill_keys(explode('|', $keys), 0);
foreach (preg_grep('~^(?:year|month)~i', $result) as $key => $value)
{
while ($date[1] >= strtotime(sprintf('+%u %s', $value + 1, $key), $date[0]))
{
++$value;
}
$date[0] = strtotime(sprintf('+%u %s', $result[$key] = $value, $key), $date[0]);
}
foreach (preg_grep('~^(?:year|month)~i', $result, PREG_GREP_INVERT) as $key => $value)
{
if (($value = intval(abs($date[0] - $date[1]) / strtotime(sprintf('%u %s', 1, $key), 0))) > 0)
{
$date[0] = strtotime(sprintf('+%u %s', $result[$key] = $value, $key), $date[0]);
}
}
return $result;
}
return false;
}它运行两个循环。第一个通过蛮力处理相对间隔（年和月），第二个通过简单的算术计算额外的绝对间隔（因此更快）：
echo humanize(date_dif('2007-03-24', '2009-07-31', 'second')); // 74300400 seconds
echo humanize(date_dif('2007-03-24', '2009-07-31', 'minute|second')); // 1238400 minutes, 0 seconds
echo humanize(date_dif('2007-03-24', '2009-07-31', 'hour|minute|second')); // 20640 hours, 0 minutes, 0 seconds
echo humanize(date_dif('2007-03-24', '2009-07-31', 'year|day')); // 2 years, 129 days
echo humanize(date_dif('2007-03-24', '2009-07-31', 'year|week')); // 2 years, 18 weeks
echo humanize(date_dif('2007-03-24', '2009-07-31', 'year|week|day')); // 2 years, 18 weeks, 3 days
echo humanize(date_dif('2007-03-24', '2009-07-31')); // 2 years, 4 months, 1 week, 0 days, 0 hours, 0 minutes, 0 seconds
function humanize($array)
{
$result = array();
foreach ($array as $key => $value)
{
$result[$key] = $value . ' ' . $key;
if ($value != 1)
{
$result[$key] .= 's';
}
}
return implode(', ', $result);
}