如何将日期时间对象转换为自epoch（unix时间）以来的毫秒数？

我有一个Python datetime对象，我想将其转换为Unix时间，即自1970年以来的秒/毫秒。

我该怎么做呢？

在我看来，最简单的方法是

import datetime

epoch = datetime.datetime.utcfromtimestamp(0)

def unix_time_millis(dt):
    return (dt - epoch).total_seconds() * 1000.0

在Python 3.3中，添加了新方法timestamp：

import datetime
seconds_since_epoch = datetime.datetime.now().timestamp()

您的问题表明您需要毫秒，您可以这样获得：

milliseconds_since_epoch = datetime.datetime.now().timestamp() * 1000

如果您使用 timestamp在朴素的datetime对象上使用，则假定它在本地时区中。如果这不是您打算发生的事情，请使用可识别时区的日期时间对象。

>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000 
1312908481000

或时间模块的帮助（不带日期格式）：

>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0

在以下网站的帮助下回答：http：//pleac.sourceforge.net/pleac_python/datesandtimes.html

说明文件：

• time.mktime
• datetime.timetuple

您可以使用Delorean来时空旅行！

import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch

http://delorean.readthedocs.org/en/latest/quickstart.html  

这是我的方法：

from datetime import datetime
from time import mktime

dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0

millis_since_epoch = sec_since_epoch * 1000

从Recommendedations 的Python 2.7文档的time模块

from datetime import datetime
from calendar import timegm

# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
    if dttm is None:
       dttm = datetime.utcnow()

    return timegm(dttm.utctimetuple())

print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))

>>> import datetime
>>> import time
>>> import calendar

>>> #your datetime object
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2013, 3, 19, 13, 0, 9, 351812)

>>> #use datetime module's timetuple method to get a `time.struct_time` object.[1]
>>> tt = datetime.datetime.timetuple(now)
>>> tt
time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9,     tm_wday=1, tm_yday=78, tm_isdst=-1)

>>> #If your datetime object is in utc you do this way. [2](see the first table on docs)
>>> sec_epoch_utc = calendar.timegm(tt) * 1000
>>> sec_epoch_utc
1363698009

>>> #If your datetime object is in local timeformat you do this way
>>> sec_epoch_loc = time.mktime(tt) * 1000
>>> sec_epoch_loc
1363678209.0

[1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple

[2] http://docs.python.org/2/library/time.html

这是时间对象标准化的另一种解决方案形式：

def to_unix_time(timestamp):
    epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
    my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
    delta = my_time - epoch
    return delta.total_seconds() * 1000.0

一点熊猫代码：

import pandas

def to_millis(dt):
    return int(pandas.to_datetime(dt).value / 1000000)

import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000

这是我根据以上答案做出的功能

def getDateToEpoch(myDateTime):
    res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
    return res

您可以像这样包装返回的值：str（int（res））要返回它而没有用作字符串的十进制值或仅用作int（不带str）

这是unixtimestampmillis的秘密日期时间的另一种解决方案。

private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);

    public static long GetCurrentUnixTimestampMillis()
    {
        DateTime localDateTime, univDateTime;
        localDateTime = DateTime.Now;          
        univDateTime = localDateTime.ToUniversalTime();
        return (long)(univDateTime - UnixEpoch).TotalMilliseconds;
    }