我试图以编程方式随时检索我的iPhone应用程序正在使用的内存量。是的,我知道ObjectAlloc / Leaks。我对这些内容不感兴趣,只是想知道是否有可能编写一些代码并获取正在使用的字节数并通过NSLog报告它。
谢谢。
我试图以编程方式随时检索我的iPhone应用程序正在使用的内存量。是的,我知道ObjectAlloc / Leaks。我对这些内容不感兴趣,只是想知道是否有可能编写一些代码并获取正在使用的字节数并通过NSLog报告它。
谢谢。
Answers:
要获取应用程序正在使用的实际内存字节,可以执行以下示例。但是,您确实应该熟悉各种分析工具,并且它们的设计目的是使您全面了解使用情况。
#import <mach/mach.h>
// ...
void report_memory(void) {
struct task_basic_info info;
mach_msg_type_number_t size = TASK_BASIC_INFO_COUNT;
kern_return_t kerr = task_info(mach_task_self(),
TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
NSLog(@"Memory in use (in bytes): %lu", info.resident_size);
NSLog(@"Memory in use (in MiB): %f", ((CGFloat)info.resident_size / 1048576));
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
}
结构info.virtual_size中还有一个字段,该字段将为您提供可用虚拟内存(或在任何情况下都作为潜在虚拟内存分配给您的应用程序的内存)的字节数。pgb链接到的代码将为您提供设备可用的内存量以及它是什么类型的内存。
标头TASK_BASIC_INFO
说:
/* Don't use this, use MACH_TASK_BASIC_INFO instead */
这是使用的版本MACH_TASK_BASIC_INFO
:
void report_memory(void)
{
struct mach_task_basic_info info;
mach_msg_type_number_t size = MACH_TASK_BASIC_INFO_COUNT;
kern_return_t kerr = task_info(mach_task_self(),
MACH_TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
NSLog(@"Memory in use (in bytes): %u", info.resident_size);
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
}
这是report_memory()的增强功能,可以在NSLog()中快速显示泄漏状态。
void report_memory(void) {
static unsigned last_resident_size=0;
static unsigned greatest = 0;
static unsigned last_greatest = 0;
struct task_basic_info info;
mach_msg_type_number_t size = sizeof(info);
kern_return_t kerr = task_info(mach_task_self(),
TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
int diff = (int)info.resident_size - (int)last_resident_size;
unsigned latest = info.resident_size;
if( latest > greatest ) greatest = latest; // track greatest mem usage
int greatest_diff = greatest - last_greatest;
int latest_greatest_diff = latest - greatest;
NSLog(@"Mem: %10u (%10d) : %10d : greatest: %10u (%d)", info.resident_size, diff,
latest_greatest_diff,
greatest, greatest_diff );
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
last_resident_size = info.resident_size;
last_greatest = greatest;
}
已在07/01/2019在Mojave 10.4.6的Xcode 11上进行了测试。
先前的所有答案均返回错误的结果。
这是如何获得苹果公司的奎因(Quinn)“爱斯基摩人”(The Eskimo!)所写的期望值的方法。
它使用phys_footprint
var中的var Darwin > Mach > task_info
并与Xcode的Debug导航器中的内存量表中的值紧密匹配。
返回的值以字节为单位。
https://forums.developer.apple.com/thread/105088#357415
原始代码如下。
func memoryFootprint() -> mach_vm_size_t? {
// The `TASK_VM_INFO_COUNT` and `TASK_VM_INFO_REV1_COUNT` macros are too
// complex for the Swift C importer, so we have to define them ourselves.
let TASK_VM_INFO_COUNT = mach_msg_type_number_t(MemoryLayout<task_vm_info_data_t>.size / MemoryLayout<integer_t>.size)
let TASK_VM_INFO_REV1_COUNT = mach_msg_type_number_t(MemoryLayout.offset(of: \task_vm_info_data_t.min_address)! / MemoryLayout<integer_t>.size)
var info = task_vm_info_data_t()
var count = TASK_VM_INFO_COUNT
let kr = withUnsafeMutablePointer(to: &info) { infoPtr in
infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { intPtr in
task_info(mach_task_self_, task_flavor_t(TASK_VM_INFO), intPtr, &count)
}
}
guard
kr == KERN_SUCCESS,
count >= TASK_VM_INFO_REV1_COUNT
else { return nil }
return info.phys_footprint
}
稍加修改即可创建一个类级别的Swift方法集,从而可以轻松返回实际字节并以MB为单位显示格式化输出。我将其用作自动化UITest套件的一部分,以记录在同一测试的多次迭代之前和之后使用的内存,以查看是否有任何潜在的泄漏或需要我们研究的分配。
// Created by Alex Zavatone on 8/1/19.
//
class Memory: NSObject {
// From Quinn the Eskimo at Apple.
// https://forums.developer.apple.com/thread/105088#357415
class func memoryFootprint() -> Float? {
// The `TASK_VM_INFO_COUNT` and `TASK_VM_INFO_REV1_COUNT` macros are too
// complex for the Swift C importer, so we have to define them ourselves.
let TASK_VM_INFO_COUNT = mach_msg_type_number_t(MemoryLayout<task_vm_info_data_t>.size / MemoryLayout<integer_t>.size)
let TASK_VM_INFO_REV1_COUNT = mach_msg_type_number_t(MemoryLayout.offset(of: \task_vm_info_data_t.min_address)! / MemoryLayout<integer_t>.size)
var info = task_vm_info_data_t()
var count = TASK_VM_INFO_COUNT
let kr = withUnsafeMutablePointer(to: &info) { infoPtr in
infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { intPtr in
task_info(mach_task_self_, task_flavor_t(TASK_VM_INFO), intPtr, &count)
}
}
guard
kr == KERN_SUCCESS,
count >= TASK_VM_INFO_REV1_COUNT
else { return nil }
let usedBytes = Float(info.phys_footprint)
return usedBytes
}
class func formattedMemoryFootprint() -> String
{
let usedBytes: UInt64? = UInt64(self.memoryFootprint() ?? 0)
let usedMB = Double(usedBytes ?? 0) / 1024 / 1024
let usedMBAsString: String = "\(usedMB)MB"
return usedMBAsString
}
}
请享用!
注意:进取的编码人员可能想要向该类添加静态格式化程序,以便usedMBAsString
仅返回2个有效的小数位。
Jason Coco的答案的Swift解决方案:
func reportMemory() {
let name = mach_task_self_
let flavor = task_flavor_t(TASK_BASIC_INFO)
let basicInfo = task_basic_info()
var size: mach_msg_type_number_t = mach_msg_type_number_t(sizeofValue(basicInfo))
let pointerOfBasicInfo = UnsafeMutablePointer<task_basic_info>.alloc(1)
let kerr: kern_return_t = task_info(name, flavor, UnsafeMutablePointer(pointerOfBasicInfo), &size)
let info = pointerOfBasicInfo.move()
pointerOfBasicInfo.dealloc(1)
if kerr == KERN_SUCCESS {
print("Memory in use (in bytes): \(info.resident_size)")
} else {
print("error with task info(): \(mach_error_string(kerr))")
}
}
Swift 3.1 (截至2017年8月8日)
func getMemory() {
var taskInfo = mach_task_basic_info()
var count = mach_msg_type_number_t(MemoryLayout<mach_task_basic_info>.size)/4
let kerr: kern_return_t = withUnsafeMutablePointer(to: &taskInfo) {
$0.withMemoryRebound(to: integer_t.self, capacity: 1) {
task_info(mach_task_self_, task_flavor_t(MACH_TASK_BASIC_INFO), $0, &count)
}
}
if kerr == KERN_SUCCESS {
let usedMegabytes = taskInfo.resident_size/(1024*1024)
print("used megabytes: \(usedMegabytes)")
} else {
print("Error with task_info(): " +
(String(cString: mach_error_string(kerr), encoding: String.Encoding.ascii) ?? "unknown error"))
}
}
(1024*1024)
不是除以1000000
从字节中获取兆字节。
这是Swift 3版本:
func mach_task_self() -> task_t {
return mach_task_self_
}
func getMegabytesUsed() -> Float? {
var info = mach_task_basic_info()
var count = mach_msg_type_number_t(MemoryLayout.size(ofValue: info) / MemoryLayout<integer_t>.size)
let kerr = withUnsafeMutablePointer(to: &info) { infoPtr in
return infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { (machPtr: UnsafeMutablePointer<integer_t>) in
return task_info(
mach_task_self(),
task_flavor_t(MACH_TASK_BASIC_INFO),
machPtr,
&count
)
}
}
guard kerr == KERN_SUCCESS else {
return nil
}
return Float(info.resident_size) / (1024 * 1024)
}
size_t memoryFootprint()
{
task_vm_info_data_t vmInfo;
mach_msg_type_number_t count = TASK_VM_INFO_COUNT;
kern_return_t result = task_info(mach_task_self(), TASK_VM_INFO, (task_info_t) &vmInfo, &count);
if (result != KERN_SUCCESS)
return 0;
return static_cast<size_t>(vmInfo.phys_footprint);
}
以下是正确答案:
```
float GetTotalPhysicsMemory()
{
struct task_basic_info info;
mach_msg_type_number_t size = sizeof(info);
kern_return_t kr;
kr = task_info(mach_task_self(), TASK_BASIC_INFO, (task_info_t)&info, &size);
if (kr == KERN_SUCCESS)
return (float)(info.resident_size) / 1024.0 / 1024.0;
else
return 0;
}
```