MYSQL更新语句内部联接表


201

我不知道是什么问题。使用MySQL 5.0尝试运行以下MYSQL更新语句时出现编译错误

  UPDATE  b
SET b.mapx = g.latitude,
  b.mapy = g.longitude
FROM business AS b
INNER JOIN business_geocode g ON b.business_id = g.business_id
WHERE  (b.mapx = '' or b.mapx = 0) and
  g.latitude > 0

所有字段名称都是正确的。有什么想法吗?


当我将其更改为SELECT b时,我什至删除了别名。*从企业b内部联接开始工作
生命的振动

Answers:


433

试试这个:

UPDATE business AS b
INNER JOIN business_geocode AS g ON b.business_id = g.business_id
SET b.mapx = g.latitude,
  b.mapy = g.longitude
WHERE  (b.mapx = '' or b.mapx = 0) and
  g.latitude > 0

更新:

既然您说查询产生了语法错误,所以我创建了一些可以对其进行测试的表,并确认查询中没有语法错误:

mysql> create table business (business_id int unsigned primary key auto_increment, mapx varchar(255), mapy varchar(255)) engine=innodb;
Query OK, 0 rows affected (0.01 sec)

mysql> create table business_geocode (business_geocode_id int unsigned primary key auto_increment, business_id int unsigned not null, latitude varchar(255) not null, longitude varchar(255) not null, foreign key (business_id) references business(business_id)) engine=innodb;
Query OK, 0 rows affected (0.01 sec)

mysql> UPDATE business AS b
    -> INNER JOIN business_geocode AS g ON b.business_id = g.business_id
    -> SET b.mapx = g.latitude,
    ->   b.mapy = g.longitude
    -> WHERE  (b.mapx = '' or b.mapx = 0) and
    ->   g.latitude > 0;
Query OK, 0 rows affected (0.00 sec)
Rows matched: 0  Changed: 0  Warnings: 0

看到?没有语法错误。我针对MySQL 5.5.8进行了测试。


我试过了,并且遇到了同样的错误。-获取执行计划时出错:您的SQL语法有错误;检查与您的MySQL服务器版本相对应的手册以获取正确的语法,以在“更新业务为b INNER JOIN business_geocode g ON b.business_id = g.busines”附近使用第1行
生活的振动

请后的结果show create table business;show create table business_geocode;这样我就可以好一点测试我的查询。谢谢。
Asaph

没有语法错误。我刚刚确认并更新了答案。
Asaph

4
@ user719316:该查询之前有一些麻烦……您是否缺少分号?
鲍比(Bobby)

2
@Joakim AS关键字是可选的。但是自从您提到它以来,为了保持一致性,我将其添加到了答案中,因为我确实在同一查询的第一个别名上使用了它。
Asaph 2012年

15

SET子句应表规范之后。

UPDATE business AS b
INNER JOIN business_geocode g ON b.business_id = g.business_id
SET b.mapx = g.latitude,
  b.mapy = g.longitude
WHERE  (b.mapx = '' or b.mapx = 0) and
  g.latitude > 0

-2

对于MySql WorkBench,请在下面使用:

update emp as a
inner join department b on a.department_id=b.id
set a.department_name=b.name
where a.emp_id in (10,11,12); 
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