每个jQuery-停止循环并返回对象

Question 1

有人可以告诉我为什么循环在5进入后没有停止吗？

$(document).ready(function()
{
  someArray = new Array();
  someArray[0] = 't5';
  someArray[1] = 'z12';
  someArray[2] = 'b88';
  someArray[3] = 's55';
  someArray[4] = 'e51';
  someArray[5] = 'o322';
  someArray[6] = 'i22';
  someArray[7] = 'k954';  

  var test =  findXX('o322');   

});

function findXX(word)
{  
  $.each(someArray, function(i)
  {
    $('body').append('-> '+i+'<br />');
    if(someArray[i] == 'someArray')
    {
      return someArray[i]; //<--- did not stop the loop!
    }   
  });  
}

Question 2

因为当您return在each循环内使用语句时，“ non-false”值将充当a continue，而false将充当a break。您将需要false从each函数中返回。像这样：

function findXX(word) {
    var toReturn; 
    $.each(someArray, function(i) {
        $('body').append('-> '+i+'<br />');
        if(someArray[i] == word) {
            toReturn = someArray[i];
            return false;
        }   
    }); 
    return toReturn; 
}

从文档：

通过使回调函数返回false，可以在特定的迭代中破坏$ .each（）循环。返回非false与for循环中的continue语句相同；它将立即跳至下一个迭代。

Question 3

这里：

http://jsbin.com/ucuqot/3/edit

function findXX(word)
{  
  $.each(someArray, function(i,n)
  {
    $('body').append('-> '+i+'<br />');
    if(n == word)
    {
      return false;
    }   
  });  
}

Question 4

修改$.each功能

$.fn.eachReturn = function(arr, callback) {
   var result = null;
   $.each(arr, function(index, value){
       var test = callback(index, value);
       if (test) {
           result = test;
           return false;
       }
   });
   return result ;
}

它会中断非假/非空结果的循环并将其返回，因此在您的情况下

return $.eachReturn(someArray, function(i){
    ...

Question 5

尝试这个 ...

  someArray = new Array();
  someArray[0] = 't5';
  someArray[1] = 'z12';
  someArray[2] = 'b88';
  someArray[3] = 's55';
  someArray[4] = 'e51';
  someArray[5] = 'o322';
  someArray[6] = 'i22';
  someArray[7] = 'k954';  

  var test =  findXX('o322'); 
  console.log(test);



function findXX(word)
{  
  for(var i in someArray){


    if(someArray[i] == word)
    {
      return someArray[i]; //<---  stop the loop!
    }   
  }
}

Question 6

“通过使回调函数返回false，可以在特定的迭代中破坏$ .each（）循环。返回非false与for循环中的continue语句相同；它将立即跳至下一个迭代。”

来自http://api.jquery.com/jquery.each/

是的，这是旧的，只是要回答这个问题，这可能会更简单：

function findXX(word) {
  $.each(someArray, function(index, value) {
    $('body').append('-> ' + index + ":" + value + '<br />');
    return !(value == word);
  });
}
$(function() {
  someArray = new Array();
  someArray[0] = 't5';
  someArray[1] = 'z12';
  someArray[2] = 'b88';
  someArray[3] = 's55';
  someArray[4] = 'e51';
  someArray[5] = 'o322';
  someArray[6] = 'i22';
  someArray[7] = 'k954';
  findXX('o322');
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>

展开摘要

还有更多评论：

显示代码段

function findXX(myA, word) {
  let br = '<br />';//create once
  let myHolder = $("<div />");//get a holder to not hit DOM a lot
  let found = false;//default return
  $.each(myA, function(index, value) {
    found = (value == word);
    myHolder.append('-> ' + index + ":" + value + br);
    return !found;
  });
  $('body').append(myHolder.html());// hit DOM once
  return found;
}
$(function() {
  // no horrid global array, easier array setup;
  let someArray = ['t5', 'z12', 'b88', 's55', 'e51', 'o322', 'i22', 'k954'];
  // pass the array and the value we want to find, return back a value
  let test = findXX(someArray, 'o322');
  $('body').append("<div>Found:" + test + "</div>");
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>

Expand snippet

注意：数组.includes()可能更适合这里https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes

或者只是.find()为了获取该https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find

Question 7

与其设置标志，不如使用JavaScriptArray.prototype.find在数组中找到匹配的项，可能会更优雅。从回调返回真实值后，循环将结束，并且在迭代期间的数组值将成为.find调用的返回值：

function findXX(word) {
    return someArray.find((item, i) => {
        $('body').append('-> '+i+'<br />');
        return item === word;
    }); 
}

显示代码段

const someArray = new Array();
someArray[0] = 't5';
someArray[1] = 'z12';
someArray[2] = 'b88';
someArray[3] = 's55';
someArray[4] = 'e51';
someArray[5] = 'o322';
someArray[6] = 'i22';
someArray[7] = 'k954';

var test = findXX('o322');
console.log('found word:', test);

function findXX(word) {
  return someArray.find((item, i) => {
    $('body').append('-> ' + i + '<br />');
    return item === word;
  });
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Expand snippet