使用BeautifulSoup查找包含某些文本的HTML标签

我正在尝试获取HTML文档中包含以下文本模式的元素：＃\ S {11}

<h2> this is cool #12345678901 </h2>

因此，前者将通过使用以下内容进行匹配：

soup('h2',text=re.compile(r' #\S{11}'))

结果将是这样的：

[u'blahblah #223409823523', u'thisisinteresting #293845023984']

我可以获取所有匹配的文本（请参见上面的行）。但是我希望文本的父元素匹配，因此我可以将其用作遍历文档树的起点。在这种情况下，我希望所有h2元素都返回，而不是文本匹配。

有想法吗？

from BeautifulSoup import BeautifulSoup
import re

html_text = """
<h2>this is cool #12345678901</h2>
<h2>this is nothing</h2>
<h1>foo #126666678901</h1>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>
"""

soup = BeautifulSoup(html_text)


for elem in soup(text=re.compile(r' #\S{11}')):
    print elem.parent

印刷品：

<h2>this is cool #12345678901</h2>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>

与其他情况相反，BeautifulSoup搜索操作BeautifulSoup.NavigableString在text=用作标准时会提供[对象列表] BeautifulSoup.Tag。检查对象的__dict__属性以查看对您可用的属性。在这些属性中，由于BS4的变化parent而受到青睐。previous

from BeautifulSoup import BeautifulSoup
from pprint import pprint
import re

html_text = """
<h2>this is cool #12345678901</h2>
<h2>this is nothing</h2>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>
"""

soup = BeautifulSoup(html_text)

# Even though the OP was not looking for 'cool', it's more understandable to work with item zero.
pattern = re.compile(r'cool')

pprint(soup.find(text=pattern).__dict__)
#>> {'next': u'\n',
#>>  'nextSibling': None,
#>>  'parent': <h2>this is cool #12345678901</h2>,
#>>  'previous': <h2>this is cool #12345678901</h2>,
#>>  'previousSibling': None}

print soup.find('h2')
#>> <h2>this is cool #12345678901</h2>
print soup.find('h2', text=pattern)
#>> this is cool #12345678901
print soup.find('h2', text=pattern).parent
#>> <h2>this is cool #12345678901</h2>
print soup.find('h2', text=pattern) == soup.find('h2')
#>> False
print soup.find('h2', text=pattern) == soup.find('h2').text
#>> True
print soup.find('h2', text=pattern).parent == soup.find('h2')
#>> True

使用bs4（Beautiful Soup 4），OP的尝试与预期完全一样：

from bs4 import BeautifulSoup
soup = BeautifulSoup("<h2> this is cool #12345678901 </h2>")
soup('h2',text=re.compile(r' #\S{11}'))

返回[<h2> this is cool #12345678901 </h2>]。