Android使用键盘上的“完成”按钮单击按钮


131

好的,在我的应用程序中,我有一个供用户输入数字的字段。我将字段设置为仅接受数字。当用户单击该字段时,它会弹出键盘。在键盘上(在ICS上)有一个完成按钮。我希望键盘上的完成按钮触发我的应用程序中的提交按钮。我的代码如下。

package com.michaelpeerman.probability;

import android.app.Activity;
import android.app.ProgressDialog;
import android.content.DialogInterface;
import android.content.DialogInterface.OnCancelListener;
import android.os.Bundle;
import android.os.Handler;
import android.os.Message;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import java.util.Random;

public class ProbabilityActivity extends Activity implements OnClickListener {

private Button submit;
ProgressDialog dialog;
int increment;
Thread background;
int heads = 0;
int tails = 0;

public void onCreate(Bundle paramBundle) {
    super.onCreate(paramBundle);
    setContentView(R.layout.main);
    submit = ((Button) findViewById(R.id.submit));
    submit.setOnClickListener(this);
}

public void onClick(View view) {
    increment = 1;
    dialog = new ProgressDialog(this);
    dialog.setCancelable(true);
    dialog.setMessage("Flipping Coin...");
    dialog.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL);
    dialog.setProgress(0);
    EditText max = (EditText) findViewById(R.id.number);
    int maximum = Integer.parseInt(max.getText().toString());
    dialog.setMax(maximum);
    dialog.show();
    dialog.setOnCancelListener(new OnCancelListener(){

          public void onCancel(DialogInterface dialog) {

              background.interrupt();
              TextView result = (TextView) findViewById(R.id.result);
                result.setText("heads : " + heads + "\ntails : " + tails);


          }});


    background = new Thread(new Runnable() {
        public void run() {
            heads=0;
            tails=0;
            for (int j = 0; !Thread.interrupted() && j < dialog.getMax(); j++) {
                int i = 1 + new Random().nextInt(2);
                if (i == 1)
                    heads++;
                if (i == 2)
                    tails++;
                progressHandler.sendMessage(progressHandler.obtainMessage());
            }
        }
    });
    background.start();
}

Handler progressHandler = new Handler() {
    public void handleMessage(Message msg) {

        dialog.incrementProgressBy(increment);
        if (dialog.getProgress() == dialog.getMax()) {
            dialog.dismiss();
            TextView result = (TextView) findViewById(R.id.result);
            result.setText("heads : " + heads + "\ntails : " + tails);


        }
    }

};

}


那是指文本框更新。
mpeerman'3

我想做的是也触发我已经拥有的按钮。我不想摆脱按钮,因为有些人可能正在使用没有完成按钮的键盘。
mpeerman'3

Answers:


313

您也可以使用它(设置在EditText上执行操作时调用的特殊侦听器),它既适用于DONE也适用于RETURN:

max.setOnEditorActionListener(new OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            if ((event != null && (event.getKeyCode() == KeyEvent.KEYCODE_ENTER)) || (actionId == EditorInfo.IME_ACTION_DONE)) {
                Log.i(TAG,"Enter pressed");
            }    
            return false;
        }
    });

1
我如何设置它以触发我已经
用完

3
您可以将所有代码移入单个函数中然后进行调用,也可以使用performClick()
vladexologija 2012年

6
按下“完成”按钮时,这对我不起作用,KeyEvent始终为null。但是将actionId设置为EditorInfo.IME_ACTION_DONE,而我可以使用它。(这是在android 4.2.2中,目前甚至与android sdk文档都不匹配)
詹姆斯

28

您可以尝试使用IME_ACTION_DONE

此操作将执行“完成”操作,无任何输入,IME将关闭。

 Your_EditTextObj.setOnEditorActionListener(new TextView.OnEditorActionListener() {
            @Override
            public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
                boolean handled = false;
                if (actionId == EditorInfo.IME_ACTION_DONE) {
                  /* Write your logic here that will be executed when user taps next button */


                    handled = true;
                }
                return handled;
            }
        });

8
这对我来说很完美。注意返回TRUE。键盘保持显示状态。如果要隐藏键盘,请返回FALSE。
Matwosk '16

1
像宝石一样工作!
sam,

16

试试这个:

max.setOnKeyListener(new OnKeyListener(){
    @Override
    public boolean onKey(View v, int keyCode, KeyEvent event){
        if(keyCode == event.KEYCODE_ENTER){
            //do what you want
        }
    }
});

当您按下任何按钮时,视图都会生成事件onKey,并且keyCode与右按钮匹配时,它会执行您想要的操作
Roman Black

1
按钮必须具有焦点
Jeffrey Blattman,2015年

8

尝试使用Xamarin.Android(跨平台)

edittext.EditorAction += (object sender, TextView.EditorActionEventArgs e) {
       if (e.ActionId.Equals (global::Android.Views.InputMethods.ImeAction.Done)) {
           //TODO Something
       }
};

7

Kotlin解决方案

在Kotlin中处理已完成操作的基本方法是:

edittext.setOnEditorActionListener { _, actionId, _ ->
    if (actionId == EditorInfo.IME_ACTION_DONE) {
        // Call your code here
        true
    }
    false
}

Kotlin扩展

使用它来调用edittext.onDone {/*action*/}您的主代码。使其更具可读性和可维护性

edittext.onDone { submitForm() }

fun EditText.onDone(callback: () -> Unit) {
    setOnEditorActionListener { _, actionId, _ ->
        if (actionId == EditorInfo.IME_ACTION_DONE) {
            callback.invoke()
            true
        }
        false
    }
}

不要忘记将这些选项添加到您的edittext

<EditText ...
    android:imeOptions="actionDone"
    android:inputType="text"/>

如果您需要inputType="textMultiLine"支持,请阅读这篇文章


4

创建LoginActivity时,我从AndroidStudio复制了以下代码。我使用ime属性

在您的布局中

<EditText android:id="@+id/unidades" android:layout_width="match_parent"
                    android:layout_height="wrap_content" android:hint="@string/prompt_unidades"
                    android:inputType="number" android:maxLines="1"
                    android:singleLine="true"
                    android:textAppearance="?android:textAppearanceSmall"
                    android:enabled="true" android:focusable="true"
                    android:gravity="right"
                    android:imeActionId="@+id/cantidad"
                    android:imeActionLabel="@string/add"
                    android:imeOptions="actionUnspecified"/>

在您的活动中

editTextUnidades.setOnEditorActionListener(new TextView.OnEditorActionListener() {
        @Override
        public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
            if (actionId == R.id.cantidad || actionId == EditorInfo.IME_NULL) {
                addDetalle(null);
                return true;
            }
            return false;
        }
    });

2

您可以在关键侦听器上实现:

public class ProbabilityActivity extends Activity implements OnClickListener, View.OnKeyListener {

在onCreate中:

max.setOnKeyListener(this);

...

@Override
public boolean onKey(View v, int keyCode, KeyEvent event){
    if(keyCode == event.KEYCODE_ENTER){
        //call your button method here
    }
    return true;
}

1

如果您想通过任何事件(例如单击按钮)抓住键盘上的Enter键来完成工作,则可以为该文本视图编写以下简单代码

Edittext ed= (EditText) findViewById(R.id.edit_text);

ed.setOnEditorActionListener(new TextView.OnEditorActionListener() {
@Override
public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
    if (actionId == EditorInfo.IME_ACTION_DONE) {
        // Do you job here which you want to done through event
    }
    return false;
}
});

1

Kotlin和数字键盘

如果您使用的是数字键盘,则必须关闭键盘,就像:

editText.setOnEditorActionListener { v, actionId, event ->
  if (action == EditorInfo.IME_ACTION_DONE || action == EditorInfo.IME_ACTION_NEXT || action == EditorInfo.IME_ACTION_UNSPECIFIED) {
      //hide the keyboard
      val imm = context.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
      imm.hideSoftInputFromWindow(windowToken, 0)
      //Take action
      editValue.clearFocus()
      return true
  } else {
      return false
  }
}

0

在您的布局中使用此类:

public class ActionEditText extends EditText
{
    public ActionEditText(Context context)
    {
        super(context);
    }

    public ActionEditText(Context context, AttributeSet attrs)
    {
        super(context, attrs);
    }

    public ActionEditText(Context context, AttributeSet attrs, int defStyle)
    {
        super(context, attrs, defStyle);
    }

    @Override
    public InputConnection onCreateInputConnection(EditorInfo outAttrs)
    {
        InputConnection conn = super.onCreateInputConnection(outAttrs);
        outAttrs.imeOptions &= ~EditorInfo.IME_FLAG_NO_ENTER_ACTION;
        return conn;
    }

}

在xml中:

<com.test.custom.ActionEditText
                android:id="@+id/postED"
                android:layout_width="match_parent"
                android:layout_height="wrap_content"
                android:layout_weight="1"
                android:background="@android:color/transparent"
                android:gravity="top|left"
                android:hint="@string/msg_type_message_here"
                android:imeOptions="actionSend"
                android:inputType="textMultiLine"
                android:maxLines="5"
                android:padding="5dip"
                android:scrollbarAlwaysDrawVerticalTrack="true"
                android:textColor="@color/white"
                android:textSize="20sp" />

0
max.setOnKeyListener(new OnKeyListener(){
  @Override
  public boolean onKey(View v, int keyCode, KeyEvent event){
    if(keyCode == event.KEYCODE_ENTER){
        //do what you want
    }
  }
});

1
对您的代码进行注释始终可以提高答案的可读性...
jAC 2015年

尽管此代码可以回答问题,但提供有关如何和/或为什么解决问题的其他上下文将提高答案的长期价值。请记住,您将来会为读者回答问题,而不仅仅是现在问的人!请编辑您的答案以添加说明,并指出适用的限制和假设。提一下为什么这个答案比其他答案更合适,这也没有什么坏处。
Dev-iL

0

您的最后一个Edittext .setOnEditorActionListener调用此方法自动命中api

我在et_password的LoginActivity中打电话

 et_Pass.setOnEditorActionListener(new TextView.OnEditorActionListener() {
            public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
                if ((event != null && (event.getKeyCode() == KeyEvent.KEYCODE_ENTER)) || (actionId == EditorInfo.IME_ACTION_DONE)) {

                    Log.i(TAG,"Enter pressed");
                    Log.i(Check Internet," and Connect To Server");

                }
                return false;
            }
        });

工作正常


0

这是Kotlin版本:

editText.setOnEditorActionListener { v, actionId, event ->
  if(actionId == EditorInfo.IME_ACTION_DONE){
      //Put your action there
      true
  } else {
      false
  }
}
By using our site, you acknowledge that you have read and understand our Cookie Policy and Privacy Policy.
Licensed under cc by-sa 3.0 with attribution required.