Answers:
using System.Diagnostics;
class Program
{
static void Main()
{
Process.Start("C:\\");
}
}
如果您的应用程序需要cmd参数,请使用以下命令:
using System.Diagnostics;
class Program
{
static void Main()
{
LaunchCommandLineApp();
}
/// <summary>
/// Launch the application with some options set.
/// </summary>
static void LaunchCommandLineApp()
{
// For the example
const string ex1 = "C:\\";
const string ex2 = "C:\\Dir";
// Use ProcessStartInfo class
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = "dcm2jpg.exe";
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.Arguments = "-f j -o \"" + ex1 + "\" -z 1.0 -s y " + ex2;
try
{
// Start the process with the info we specified.
// Call WaitForExit and then the using statement will close.
using (Process exeProcess = Process.Start(startInfo))
{
exeProcess.WaitForExit();
}
}
catch
{
// Log error.
}
}
}
例:
System.Diagnostics.Process.Start("mspaint.exe");
编译代码
复制代码并将其粘贴到控制台应用程序的Main方法中。用您要运行的应用程序的路径替换“ mspaint.exe”。
Process.Start()
我知道这个答案很好,但是如果您有兴趣,我写了一个库,使执行命令更加容易。
在这里查看:https : //github.com/twitchax/Sheller。
startInfo.UseShellExecute = false
真是一件了不起的事情...对我来说就像是魅力!谢谢!:)