与PCA中完成的步骤相比,因素分析中完成的步骤


12

我知道如何执行PCA(主要成分分析),但是我想知道应该用于因子分析的步骤。

为了执行PCA,让我们考虑一些矩阵,例如:A

         3     1    -1
         2     4     0
         4    -2    -5
        11    22    20

我已经计算出其相关矩阵B = corr(A)

        1.0000    0.9087    0.9250
        0.9087    1.0000    0.9970
        0.9250    0.9970    1.0000

然后,我完成了特征值分解[V,D] = eig(B),生成了特征向量:

        0.5662    0.8209   -0.0740
        0.5812   -0.4613   -0.6703
        0.5844   -0.3366    0.7383

和特征值:

        2.8877         0         0
             0    0.1101         0
             0         0    0.0022

PCA背后的总体思路是选择重要的分量,形成具有列特征向量的新矩阵,然后我们需要投影原始矩阵(在PCA中,它是零中心的)。但是在因子分析中,例如,我们应该选择具有大于奇异值的组件,然后我们还要使用因子旋转,请告诉我它是如何完成的?例如在这种情况下。1

请帮助我了解与PCA步骤相比的因素分析步骤。

Answers:


24

这个答案是要显示PCA和因素分析之间具体的计算相似之处和不同之处。用于在它们之间一般的理论的差异,见的问题/答案12345

下面,我将逐步进行虹膜数据(仅“ setosa”物种主成分分析(PCA),然后将对同一数据进行因子分析。因子分析(FA)将通过基于PCA方法的迭代主轴PAF)方法进行,因此可以逐步比较PCA和FA。

虹膜数据(仅setosa):

  id  SLength   SWidth  PLength   PWidth species 

   1      5.1      3.5      1.4       .2 setosa 
   2      4.9      3.0      1.4       .2 setosa 
   3      4.7      3.2      1.3       .2 setosa 
   4      4.6      3.1      1.5       .2 setosa 
   5      5.0      3.6      1.4       .2 setosa 
   6      5.4      3.9      1.7       .4 setosa 
   7      4.6      3.4      1.4       .3 setosa 
   8      5.0      3.4      1.5       .2 setosa 
   9      4.4      2.9      1.4       .2 setosa 
  10      4.9      3.1      1.5       .1 setosa 
  11      5.4      3.7      1.5       .2 setosa 
  12      4.8      3.4      1.6       .2 setosa 
  13      4.8      3.0      1.4       .1 setosa 
  14      4.3      3.0      1.1       .1 setosa 
  15      5.8      4.0      1.2       .2 setosa 
  16      5.7      4.4      1.5       .4 setosa 
  17      5.4      3.9      1.3       .4 setosa 
  18      5.1      3.5      1.4       .3 setosa 
  19      5.7      3.8      1.7       .3 setosa 
  20      5.1      3.8      1.5       .3 setosa 
  21      5.4      3.4      1.7       .2 setosa 
  22      5.1      3.7      1.5       .4 setosa 
  23      4.6      3.6      1.0       .2 setosa 
  24      5.1      3.3      1.7       .5 setosa 
  25      4.8      3.4      1.9       .2 setosa 
  26      5.0      3.0      1.6       .2 setosa 
  27      5.0      3.4      1.6       .4 setosa 
  28      5.2      3.5      1.5       .2 setosa 
  29      5.2      3.4      1.4       .2 setosa 
  30      4.7      3.2      1.6       .2 setosa 
  31      4.8      3.1      1.6       .2 setosa 
  32      5.4      3.4      1.5       .4 setosa 
  33      5.2      4.1      1.5       .1 setosa 
  34      5.5      4.2      1.4       .2 setosa 
  35      4.9      3.1      1.5       .2 setosa 
  36      5.0      3.2      1.2       .2 setosa 
  37      5.5      3.5      1.3       .2 setosa 
  38      4.9      3.6      1.4       .1 setosa 
  39      4.4      3.0      1.3       .2 setosa 
  40      5.1      3.4      1.5       .2 setosa 
  41      5.0      3.5      1.3       .3 setosa 
  42      4.5      2.3      1.3       .3 setosa 
  43      4.4      3.2      1.3       .2 setosa 
  44      5.0      3.5      1.6       .6 setosa 
  45      5.1      3.8      1.9       .4 setosa 
  46      4.8      3.0      1.4       .3 setosa 
  47      5.1      3.8      1.6       .2 setosa 
  48      4.6      3.2      1.4       .2 setosa 
  49      5.3      3.7      1.5       .2 setosa 
  50      5.0      3.3      1.4       .2 setosa 

我们在分析中包含4个数值变量:SLength SWidth PLength PWidth,并且分析将基于协方差,这与说我们分析中心变量相同。(如果我们选择分析将用于分析标准变量的相关性。基于相关性的分析将产生与基于协方差的分析不同的结果。)我将不会显示居中的数据。让我们称这些数据矩阵X

PCA步骤:

Step 0. Compute centered variables X and covariance matrix S.

Covariances S (= X'*X/(n-1) matrix: see /stats//a/22520/3277)
.12424898   .09921633   .01635510   .01033061
.09921633   .14368980   .01169796   .00929796
.01635510   .01169796   .03015918   .00606939
.01033061   .00929796   .00606939   .01110612

Step 1.1. Decompose data X or matrix S to get eigenvalues and right eigenvectors.
          You may use svd or eigen decomposition (see /stats//q/79043/3277)

Eigenvalues L (component variances) and the proportion of overall variance explained
           L            Prop
PC1   .2364556901   .7647237023 
PC2   .0369187324   .1193992401 
PC3   .0267963986   .0866624997 
PC4   .0090332606   .0292145579    

Eigenvectors V (cosines of rotation of variables into components)
              PC1           PC2           PC3           PC4
SLength   .6690784044   .5978840102  -.4399627716  -.0360771206 
SWidth    .7341478283  -.6206734170   .2746074698  -.0195502716 
PLength   .0965438987   .4900555922   .8324494972  -.2399012853 
PWidth    .0635635941   .1309379098   .1950675055   .9699296890 

Step 1.2. Decide on the number M of first PCs you want to retain.
          You may decide it now or later on - no difference, because in PCA values of components do not depend on M.
          Let's M=2. So, leave only 2 first eigenvalues and 2 first eigenvector columns.

Step 2. Compute loadings A. May skip if you don't need to interpret PCs anyhow.
Loadings are eigenvectors normalized to respective eigenvalues: A value = V value * sqrt(L value)
Loadings are the covariances between variables and components.

Loadings A
              PC1           PC2           
SLength    .32535081     .11487892
SWidth     .35699193    -.11925773
PLength    .04694612     .09416050
PWidth     .03090888     .02515873

Sums of squares in columns of A are components' variances, the eigenvalues

Standardized (rescaled) loadings.
St. loading is Loading / sqrt(Variable's variance);
these loadings are computed if you analyse covariances, and are suitable for interpretation of PCs
(if you analyse correlations, A are already standardized).
              PC1           PC2      
SLength    .92300804     .32590717
SWidth     .94177127    -.31461076
PLength    .27032731     .54219930
PWidth     .29329327     .23873031

Step 3. Compute component scores (values of PCs).

Regression coefficients B to compute Standardized component scores are: B = A*diag(1/L) = inv(S)*A
B
              PC1           PC2  
SLength   1.375948338   3.111670112 
SWidth    1.509762499  -3.230276923 
PLength    .198540883   2.550480216 
PWidth     .130717448    .681462580 

Standardized component scores (having variances 1) = X*B
      PC1           PC2
  .219719506   -.129560000 
 -.810351411    .863244439 
 -.803442667   -.660192989 
-1.052305574   -.138236265 
  .233100923   -.763754703 
 1.322114762    .413266845 
 -.606159168  -1.294221106 
 -.048997489    .137348703 
  ...

Raw component scores (having variances = eigenvalues) can of course be computed from standardized ones.
In PCA, they are also computed directly as X*V
      PC1           PC2
  .106842367   -.024893980 
 -.394047228    .165865927 
 -.390687734   -.126851118 
 -.511701577   -.026561059 
  .113349309   -.146749722 
  .642900908    .079406116 
 -.294755259   -.248674852 
 -.023825867    .026390520 
  ...

FA(迭代主轴提取方法)步骤:

Step 0.1. Compute centered variables X and covariance matrix S.

Step 0.2. Decide on the number of factors M to extract.
          (There exist several well-known methods in help to decide, let's omit mentioning them. Most of them require that you do PCA first.)
          Note that you have to select M before you proceed further because, unlike in PCA, in FA loadings and factor values depend on M.
          Let's M=2.

Step 0.3. Set initial communalities on the diagonal of S.
          Most often quantities called "images" are used as initial communalities (see /stats//a/43224/3277).
          Images are diagonal elements of matrix S-D, where D is diagonal matrix with diagonal = 1 / diagonal of inv(S).
          (If S is correlation matrix, images are the squared multiple correlation coefficients.)

With covariance matrix, image is the squared multiple correlation multiplied by the variable variance.
S with images as initial communalities on the diagonal
.07146025  .09921633  .01635510  .01033061
.09921633  .07946595  .01169796  .00929796
.01635510  .01169796  .00437017  .00606939
.01033061  .00929796  .00606939  .00167624

Step 1. Decompose that modified S to get eigenvalues and right eigenvectors.
        Use eigen decomposition, not svd. (Usually some last eigenvalues will be negative.)

Eigenvalues L
F1   .1782099114
F2   .0062074477
    -.0030958623
    -.0243488794

Eigenvectors V
               F1            F2 
SLength   .6875564132   .0145988554   .0466389510   .7244845480
SWidth    .7122191394   .1808121121  -.0560070806  -.6759542030
PLength   .1154657746  -.7640573143   .6203992617  -.1341224497
PWidth    .0817173855  -.6191205651  -.7808922917  -.0148062006

Leave the first M=2 values in L and columns in V.

Step 2.1. Compute loadings A.
Loadings are eigenvectors normalized to respective eigenvalues: A value = V value * sqrt(L value)
               F1            F2 
SLength   .2902513607   .0011502052
SWidth    .3006627098   .0142457085
PLength   .0487437795  -.0601980567
PWidth    .0344969255  -.0487788732

Step 2.2. Compute row sums of squared loadings. These are updated communalities.
          Reset the diagonal of S to them

S with updated communalities on the diagonal
.08424718  .09921633  .01635510  .01033061
.09921633  .09060101  .01169796  .00929796
.01635510  .01169796  .00599976  .00606939
.01033061  .00929796  .00606939  .00356942

REPEAT Steps 1-2 many times (iterations, say, 25)

Extraction of factors is done.

Final loadings A and communalities (row sums of squares in A).
Loadings are the covariances between variables and factors.
Communality is the degree to what the factors load a variable, it is the "common variance" in the variable.
               F1            F2                        Comm
SLength   .3125767362   .0128306509                .0978688416
SWidth    .3187577564  -.0323523347                .1026531808
PLength   .0476237419   .1034495601                .0129698323
PWidth    .0324478281   .0423861795                .0028494498

Sums of squares in columns of A are factors' variances.

Standardized (rescaled) loadings and communalities.
St. loading is Loading / sqrt(Variable's variance);
these loadings are computed if you analyse covariances, and are suitable for interpretation of Fs
(if you analyse correlations, A are already standardized).
               F1            F2                        Comm
SLength   .8867684574   .0364000747                .7876832626
SWidth    .8409066701  -.0853478652                .7144082859
PLength   .2742292179   .5956880078                .4300458666
PWidth    .3078962532   .4022009053                .2565656710

Step 3. Compute factor scores (values of Fs).
        Unlike component scores in PCA, factor scores are not exact, they are reasonable approximations.
        Several methods of computation exist (/stats//q/126885/3277).
        Here is regressional method which is the same as the one used in PCA.

Regression coefficients B to compute Standardized factor scores are: B = inv(S)*A (original S is used)
B
              F1           F2  
SLength  1.597852081   -.023604439
SWidth   1.070410719   -.637149341
PLength   .212220217   3.157497050
PWidth    .423222047   2.646300951

Standardized factor scores = X*B
These "Standardized factor scores" have variance not 1; the variance of a factor is SSregression of the factor by variables / (n-1).
      F1           F2
  .194641800   -.365588231
 -.660133976   -.042292672
 -.786844270   -.480751358
-1.011226507    .216823430
  .141897664   -.426942721
 1.250472186    .848980006
 -.669003108   -.025440982
 -.050962459    .016236852
  ...

Factors are extracted as orthogonal. And they are.
However, regressionally computed factor scores are not fully uncorrelated.
Covariance matrix between computed factor scores.
      F1      F2
F1   .864   .026
F2   .026   .459

Factor variances are their squared loadings.
You can easily recompute the above "standardized" factor scores to "raw" factor scores having those variances:
raw score = st. score * sqrt(factor variance / st. scores variance).

提取后(如上所示),可以进行可选的旋转。旋转通常在FA中进行。有时,它在PCA中完全相同。旋转将加载矩阵A旋转为某种形式的“简单结构”,极大地方便了对因子的解释(然后可以重新计算旋转的分数)。由于轮换并不是从数学上将FA与PCA区别开的原因,并且因为它是一个单独的大话题,所以我不会去谈它。


当您谈论“图像”作为初始社区时,您会链接到您的另一个答案(该讨论讨论了选择初始社区的各种方法),但并未提及“图像”。听起来很有趣,您可能想扩大以前的答案吗?
变形虫说恢复莫妮卡2014年

但是因子分析对我来说似乎有点奇怪,现在我正在考虑并且无法猜测
dato datuashvili 2014年
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