是否有任何默认功能/实用程序在Bash脚本中提示用户输入是/否？

有时我需要问用户是/否来确认某些内容。

通常我使用这样的东西：

# Yes/no dialog. The first argument is the message that the user will see.
# If the user enters n/N, send exit 1.
check_yes_no(){
    while true; do
        read -p "$1" yn
        if [ "$yn" = "" ]; then
            yn='Y'
        fi
        case "$yn" in
            [Yy] )
                break;;
            [Nn] )
                echo "Aborting..."
                exit 1;;
            * )
                echo "Please answer y or n for yes or no.";;
        esac
    done;
}

有更好的方法吗？该实用程序可能已经在我的/bin文件夹中了吗？

啊，内置了一些东西：zenity一个图形对话框程序：

if zenity --question --text="Is this OK?" --ok-label=Yes --cancel-label=No
then
    # user clicked "Yes"
else
    # user clicked "No"
fi

除了zenity，您还可以使用以下之一：

if dialog --yesno "Is this OK?" 0 0; then ...
if whiptail --yesno "Is this OK?" 0 0; then ...

对我来说很好。我只是减少它的“执行或死亡”：

• 如果是“ Y” return 0
• 如果“ N” return 1

这样，您可以执行以下操作：

if check_yes_no "Do important stuff? [Y/n] "; then
    # do the important stuff
else
    # do something else
fi
# continue with the rest of your script

根据@muru的select建议，该函数可能非常简洁：

check_yes_no () { 
    echo "$1"
    local ans PS3="> "
    select ans in Yes No; do 
        [[ $ans == Yes ]] && return 0
        [[ $ans == No ]] && return 1
    done
}

作为结论，我写了这个脚本：

#!/bin/bash

usage() { 
    echo "Show yes/no dialog, returns 0 or 1 depending on user answer"
    echo "Usage: $0 [OPTIONS]
    -x      force to use GUI dialog
    -m <string> message that user will see" 1>&2
    exit 1;
}

while getopts m:xh opts; do
    case ${opts} in
        x) FORCE_GUI=true;
            ;;
        m) MSG=${OPTARG}
            ;;
        h) usage
            ;;
    esac
done

if [ -z "$MSG" ];then
    usage
fi

# Yes/no dialog.
# If the user enters n/N, return 1.
while true; do
    if [ -z $FORCE_GUI ]; then
        read -p "$MSG" yn
        case "$yn" in
            [Yy] )
                exit 0;;
            [Nn] )
                echo "Aborting..." >&1
                exit 1;;
            * )
                echo "Please answer y or n for yes or no.";;
        esac
    else
        if [ -z $DISPLAY ]; then echo "DISPLAY variable is not set" >&1 ; exit 1; fi
        if zenity --question --text="$MSG" --ok-label=Yes --cancel-label=No; then
            exit 0
        else
            echo "Aborting..." >&1
            exit 1
        fi
    fi
done;

最新版本的脚本可以在这里找到。免费填写以进行更改/编辑

我正在使用以下内容：

• 默认为no：

    read -p "??? Are You sure [y/N]? " -n 1
    if [[ ! $REPLY =~ ^[Yy]$ ]]; then
        echo "!!! Canceled by user."
        exit 1
    fi

• 默认为是：

    read -p "??? Are You sure [Y/n]" -n 1
    if [[ $REPLY =~ ^[Nn]$ ]]; then
        echo "!!! Canceled by user."
        exit 1
    fi

 read -p 'Are you sure you want to continue? (y/n) ' -n 1 confirmation
 echo ''                                                                                                   
 if [[ $confirmation != 'y' && $confirmation != 'Y' ]]; then                                               
   exit 3                                                                                                
 fi
 # Code to execute if user wants to continue here.