提取三个单引号之间的文本

我的档案中有以下内容

description: '''
        This rule forbids throwing string literals or interpolations. While
        JavaScript (and CoffeeScript by extension) allow any expression to
        be thrown, it is best to only throw <a
        href="https://developer.mozilla.org
        /en/JavaScript/Reference/Global_Objects/Error"> Error</a> objects,
        because they contain valuable debugging information like the stack
        trace. Because of JavaScript's dynamic nature, CoffeeLint cannot
        ensure you are always throwing instances of <tt>Error</tt>. It will
        only catch the simple but real case of throwing literal strings.
        <pre>
        <code># CoffeeLint will catch this:
        throw "i made a boo boo"

        # ... but not this:
        throw getSomeString()
        </code>
        </pre>
        This rule is enabled by default.
        '''

与此文件中的其他几件事。

我通过sed -n "/'''/,/'''/p" $1（$1文件在哪里）将这部分提取到我的shell脚本中。

这给了我一个变量，内容为一个衬里

description: ''' This rule forbids throwing string literals or interpolations. While JavaScript (and CoffeeScript by extension) allow any expression to be thrown, it is best to only throw <a href="https://developer.mozilla.org /en/JavaScript/Reference/Global_Objects/Error"> Error</a> objects, because they contain valuable debugging information like the stack trace. Because of JavaScript's dynamic nature, CoffeeLint cannot ensure you are always throwing instances of <tt>Error</tt>. It will only catch the simple but real case of throwing literal strings. <pre> <code># CoffeeLint will catch this: throw "i made a boo boo" # ... but not this: throw getSomeString() </code> </pre> This rule is enabled by default. '''

现在如何提取之间的部分'''？

还是有更好的方法从多行文件中检索它？

我使用的是Mac El Captain 10.11.2和GNU bash版本3.2.57（1）-发行版（x86_64-apple-darwin15）

perl -l -0777 -ne "print for /'''(.*?)'''/gs" file

将提取（并打印换行符）每对“''之间的部分。

请注意perl在开始处理整个文件之前先将其保存在内存中，这样解决方案可能不适用于非常大的文件。

如果有gawk或mawk可以处置，请尝试以下方法：

gawk -v "RS='''" 'FNR%2==0' file

假设'''文件中没有其他-s。

说明：它将记录分隔符设置为三个单引号，并在记录号为偶数时打印。

不幸的是，它不能用于所有awk实现，因为多字符记录分隔符不是的一部分POSIX awk。

不像awk的答案那么好，但是就像您最初使用sed一样

/'''/{
   s/.*'''//
   :1
   N
   /'''/!b1
   s/'''.*//
   p
}
d

或更短，如glenn jackman在评论中指出的（略有变化）

/'''/,//{
//!p
}
d

运行为

sed -f script file

输出量

    This rule forbids throwing string literals or interpolations. While
    JavaScript (and CoffeeScript by extension) allow any expression to
    be thrown, it is best to only throw <a
    href="https://developer.mozilla.org
    /en/JavaScript/Reference/Global_Objects/Error"> Error</a> objects,
    because they contain valuable debugging information like the stack
    trace. Because of JavaScript's dynamic nature, CoffeeLint cannot
    ensure you are always throwing instances of <tt>Error</tt>. It will
    only catch the simple but real case of throwing literal strings.
    <pre>
    <code># CoffeeLint will catch this:
    throw "i made a boo boo"

    # ... but not this:
    throw getSomeString()
    </code>
    </pre>
    This rule is enabled by default.