我想找到所有包含具有相同名称（和扩展名.md）的markdown文件的子文件夹。
例如：我要查找以下子文件夹：
Apple/Banana/Orange #Apple/Banana/Orange/Orange.md exists
Apple/Banana #Apple/Banana/Banana.md exists
Apple/Banana/Papaya #Apple/Banana/Papaya/Papaya.md exists- 注意：目录中可以有其他文件或子目录。
有什么建议么？
可以使用以下代码测试问题的解决方案：
#!/usr/bin/env bash
# - goal: "Test"
# - author: Nikhil Agarwal
# - date: Wednesday, August 07, 2019
# - status: P T' (P: Prototyping, T: Tested)
# - usage: ./Test.sh
# - include:
# 1.
# - refer:
# 1. [directory - Find only those folders that contain a File with the same name as the Folder - Unix & Linux Stack Exchange](/unix/534190/find-only-those-folders-that-contain-a-file-with-the-same-name-as-the-folder)
# - formatting:
# shellcheck disable=
#clear
main() {
TestData
ExpectedOutput
TestFunction "${1:?"Please enter a test number, as the first argument, to be executed!"}"
}
TestFunction() {
echo "Test Function"
echo "============="
"Test${1}"
echo ""
}
Test1() {
echo "Description: Thor"
find . -type f -regextype egrep -regex '.*/([^/]+)/\1\.md$' | sort
echo "Observation: ${Green:=}Pass, but shows filepath instead of directory path${Normal:=}"
}
Test2() {
echo "Description: Kusalananda1"
find . -type d -exec sh -c '
dirpath=$1
set -- "$dirpath"/*.md
[ -f "$dirpath/${dirpath##*/}.md" ] && [ "$#" -eq 1 ]' sh {} \; -print | sort
echo "Observation: ${Red:=}Fails as it ignores B.md${Normal:=}"
}
Test3() {
echo "Description: Kusalananda2"
find . -type d -exec sh -c '
for dirpath do
set -- "$dirpath"/*.md
if [ -f "$dirpath/${dirpath##*/}.md" ] && [ "$#" -eq 1 ]
then
printf "%s\n" "$dirpath"
fi
done' sh {} + | sort
echo "Observation: ${Red:=}Fails as it ignores B.md${Normal:=}"
}
Test4() {
echo "Description: steeldriver1"
find . -type d -exec sh -c '[ -f "$1/${1##*/}.md" ]' find-sh {} \; -print | sort
echo "Observation: ${Green:=}Pass${Normal:=}"
}
Test5() {
echo "Description: steeldriver2"
find . -type d -exec sh -c '
for d do
[ -f "$d/${d##*/}.md" ] && printf "%s\n" "$d"
done' find-sh {} + | sort
echo "Observation: ${Green:=}Pass${Normal:=}"
}
Test6() {
echo "Description: Stéphane Chazelas"
find . -name '*.md' -print0 \
| gawk -v RS='\0' -F/ -v OFS=/ '
{filename = $NF; NF--
if ($(NF)".md" == filename) include[$0]
else exclude[$0]
}
END {for (i in include) if (!(i in exclude)) print i}'
echo "Observation: ${Red:=}Fails as it ignores B.md${Normal:=}"
}
Test7() {
echo "Description: Zach"
#shellcheck disable=2044
for fd in $(find . -type d); do
dir=${fd##*/}
if [ -f "${fd}/${dir}.md" ]; then
ls "${fd}/${dir}.md"
fi
done
echo "Observation: ${Green:=}Pass but shows filepath instead of directory${Normal:=}"
}
ExpectedOutput() {
echo "Expected Output"
echo "==============="
cat << EOT
./GeneratedTest/A
./GeneratedTest/A/AA
./GeneratedTest/B
./GeneratedTest/C/CC1
./GeneratedTest/C/CC2
EOT
}
TestData() {
rm -rf GeneratedTest
mkdir -p GeneratedTest/A/AA
touch GeneratedTest/index.md
touch GeneratedTest/A/A.md
touch GeneratedTest/A/AA/AA.md
mkdir -p GeneratedTest/B
touch GeneratedTest/B/B.md
touch GeneratedTest/B/index.md
mkdir -p GeneratedTest/C/CC1
touch GeneratedTest/C/index.md
touch GeneratedTest/C/CC1/CC1.md
mkdir -p GeneratedTest/C/CC2
touch GeneratedTest/C/CC2/CC2.md
mkdir -p GeneratedTest/C/CC3
touch GeneratedTest/C/CC3/CC.md
mkdir -p GeneratedTest/C/CC4
}
main "$@"
1
关于你的最后发言。请注意，某些答案的作用与其他答案不同。矿山和斯特凡的，例如，您的解释第一个“注”为“是否有其他的降价目录中的文件无论如何，不要返回目录”，而有的则没有（据我可以看到）。除此之外，只有您可以选择对您最有帮助的答案。您接受答案后，此处的答案将继续获得上下投票，具体取决于其他读者认为最有用的内容。
—
库萨兰达
当您说“找不到包含名称不同的markdown文件的文件夹”时，您是要排除两个目录吗？例如，如果您有
—
凯文
foo/foo.md并且foo/bar.md应该foo被包括或排除在外？
@Kevin在您提供的示例中，我打算包含foo。但是不幸的是，许多人用另一种方式解释了，并证明了这一点。所以，我以为我不清楚沟通。因此，我接受了不包含foo的答案。
—
Nikhil
如果
—
托尔（Thor）
-printf与find配合使用，则可以获取匹配项的任意部分，请参阅我的编辑