我需要从单个文件中提取文本字符串,该文件包含一行很长的文本,没有定界符。使用下面的示例行,这些是以下已知事实: ??????? A1XXXXXXXXXX ??????? B1XXXX ??????? A1XXXXXXXXXX ??????? C1XXXXXXX 1. It contains 38 fixed width record types 2. The record marker is a 7 alphanumeric character followed by, for example, ‘A1’. 3. Each record type has varying widths, for example, A1 record type will have 10 characters following it, if …
我有三个文件,行数为n,如下所示 sample1.txt ------------------------------ Date Time Name ------------------------------ 2013/10/12 12:09:09 Krish 2013/10/12 13:12:01 Ramb 2013/10/12 15:28:39 Likha 2013/10/12 15:56:12 Mat . . . Sample2.txt ------------------------------ Date Time Name ------------------------------ 2013/10/12 11:19:21 Jack 2013/10/12 12:11:09 Rob 2013/10/12 15:45:12 Rick 2013/10/12 22:11:10 Phil . . . Sample3.txt ------------------------------ Date Time Name ------------------------------ 2013/10/12 …
zzzzzzzzz aaaaaaaaa bbbbbbbbb & ccccccccc & ddddddddd hhhhhhhhh eeeeeeeee fffffffff & ggggggggg & 在上面的行中,我想要的是grep/ sed/ awk(任何方法都可以)行上有&符号加一行的符号。因此,例如,所需的输出将如下所示: aaaaaaaaa bbbbbbbbb & ccccccccc & eeeeeeeee fffffffff & ggggggggg & 以下是我没有运气尝试过的。 egrep "&" | -b 1 file.txt
如何修剪文件(良好的输入流),以便仅获得从第一次出现foo到最后一次出现的行bar? 例如,考虑以下输入: A line like foo this foo bar something something else foo bar and the rest 我期望这个输出: foo this foo bar something something else foo bar