在Nim语言中，用于区分标识符的规则比大多数其他语言稍微宽松一些。如果两个标识符遵循以下规则，则它们是等效的或寻址相同的变量：

• 两者的第一个字符相同 （区分大小写）
• 两个字符串相同（壳体在敏感）除去后的所有实例的字符-和_

挑战

编写一个程序/函数，该程序/函数接受两个表示Nim标识符的字符串，并根据上述规则是否等效来输出真值或假值。

技术指标

• 适用标准I / O规则。
• 标准的漏洞被禁止。
• 字符串将仅包含ASCII可打印内容。你并不需要检查它是否是一个有效的标识符。
• 字符串可以作为两个单独的输入，字符串列表等（您知道练习）
• 空字符串无需处理。
• 真值和假值的输出必须一致。
• 挑战不是要找到所有语言中最短的方法，而是要找到每种语言中最短的方法。
• 除非另有说明，否则您的代码通常以UTF-8编码形式以字节计分。
• 允许执行此任务的内置函数，但鼓励使用不依赖内置函数的解决方案。
• 鼓励甚至对“实用”语言进行解释。

测试用例

Input                                    Output

count, Count                             falsey
lookMaNoSeparator, answer                falsey
_test, test                              falsey
test, tset                               falsey
aVariableName, a_variable_name           truthy
numbers_are_cool123, numbersAreCool123   truthy
symbolsAre_too>_>, symbols_areTOO>>      truthy

未引用的参考实现

这是用Nim编写的。

import strutils, re

proc sameIdentifier(a, b: string): bool =
  a[0] == b[0] and
    a.replace(re"_|–", "").toLower == b.replace(re"_|–", "").toLower

JavaScript（ES6），62 61字节

@JohanKarlsson节省了1个字节

以currying语法接受输入(a)(b)。返回一个布尔值。

a=>b=>(r=s=>s[0]+s.replace(/-|_/g,'').toUpperCase())(b)==r(a)

测试用例

let f =

a=>b=>(r=s=>s[0]+s.replace(/-|_/g,'').toUpperCase())(b)==r(a)

console.log(f("count")("Count"))                           // falsey
console.log(f("lookMaNoSeparator")("answer"))              // falsey
console.log(f("_test")("test"))                            // falsey
console.log(f("aVariableName")("a_variable_name"))         // truthy
console.log(f("numbers_are_cool123")("numbersAreCool123")) // truthy

Python 3，76个字节

lambda a,b:f(*a)==f(*b)
f=lambda f,*r:[f+k.lower()for k in r if~-(k in'-_')]

在线尝试！

-1字节归功于notjagan
-3字节归功于Wheat Wizard

实际上，15个字节

⌠p"-_"(-Σùo⌡M═Y

在线尝试！

有趣的事实：这适用于任意数量的输入（对于少于2个输入，它总是返回true）。

说明：

⌠p"-_"(-Σùo⌡M═Y
⌠p"-_"(-Σùo⌡M    for each input:
 p                 separate the first character
  "-_"(-           remove all dashes and underscores from the rest of the string
        Σù         concatenate the list from the last operation and lowercase the string
          o        append it to the first character
             ═Y  are none of the elements unique?

Pyth，13个字节

qFm[hd-r0d"-_

在线尝试！

说明

qFm[hd-r0d"-_
  m              For each value in the input (which is a list of two strings):
   [             Create a list consisting of
    hd               the first character of each value
      -r0d"-_        and the lowercase version of the value without "-" or "_"
qF               Fold over equivalence; checks to see if both lists are the same

05AB1E，12个字节

εćs„-_SKl«}Ë

在线尝试！

-1感谢Adnan。

从理论上讲，εćs„-_-«}Ë应该已经使用了10个字节，但是不幸的是，现在不建议使用此行为。

果冻，11字节

ḟ⁾-_Œl,Ḣµ€E

在线尝试！

-2个字节感谢Outgolfer的Erik
-1个字节感谢Jonathan Allan

Ruby，86 64 63 61 51字节

f=->x{x[0]+x.upcase.delete("-_")}
->x,y{f[x]==f[y]}

在线尝试！

这感觉真的很长，仍然感觉有点长。我将感谢任何Ruby专家的帮助，使它至少短一些。

C ++，288个 248字节

-5个字节，感谢Zacharý

#include<string>
#include<algorithm>
#define E(a,v)a.erase(std::remove(a.begin(),a.end(),v),a.end());
#define F(a)for(auto&c:a)c=toupper(c);
int e(std::string&a,std::string&b){if(a[0]!=b[0])return 0;E(a,45)E(b,45)E(a,95)E(b,95)F(a)F(b)return a==b;}

Thanks you, Preprocessor. Also, this code takes advantage of the fact that in C++ the rule to cast int to bool is int_var!=0

CJam, 20 bytes

{_"-_"f-:el:=\:c:=*}

Takes input in the form of ["string1","string2"].

Try it Online (testing version)

{
_      e# make copy of input
"-_"f- e# remove all "-" and "_" from both words in copy
:el    e# convert words in copy to lowercase
:=     e# 1 if both words in copy are equal, 0 if not
\      e# move original version of input to top of stack
:c     e# convert each word in original input to only 1st character
:=     e# 1 if both characters from original input are equal, 0 if not
*      e# multply the two numbers we obtained. If and only if both are 1 (true) we return 1 (true)
}

Haskell, 85 78 76 71 68 bytes

2 bytes saved thanks to Ørjan Johansen

import Data.Char
s(a:x)=a:[toLower a|a<-x,all(/=a)"-_"]
x!y=s x==s y

Try it online!

Errors on the empty string.

Python 2, 72 bytes

lambda x,y:r(x)==r(y)
r=lambda x:x[0]+x[1:].lower().translate(None,"-_")

Try it online!

Won't work with Python 3 because of the new translate syntax.

Excel, 105 bytes

=AND(CODE(A1)=CODE(B1),SUBSTITUTE(SUBSTITUTE(A1,"_",""),"-","")=SUBSTITUTE(SUBSTITUTE(B1,"_",""),"-",""))

CODE() returns numeric code of first character.

String comparison in Excel is case insensitive.

Husk, 13 bytes

¤=§,←(m_ω-"-_

Try it online!

Builds for each string a pair consisting of the first character of the string and the whole string lowercased and with all occurrences of -/_ removed. Then checks if the two pairs are equal.

A particularity is that - in Husk is set difference (i.e. it removes only the first occurrence found): in order to remove all occurrences, the fixed point of -"-_ is found with ω-"-_.

Japt, 14 25 bytes

g ¥Vg ©Uu k"_-" ¥Vu k"_-"

Checks case-insensitive string equality by removing all characters in word 2 from word 1, and removing the -_ characters; that results in an empty string ("") if the words are equal.
Thanks Ørjan Johansen for pointing out the problem with this.

Checks first-char equality and if the uppercased inputs are equal after removing _-.

Try it online!

Explanation

Implicit input: U and V are input strings

g ¥Vg

Check if first letter of U (implicit) equals (¥) the first char of V.

©Uu k"_-" ¥Vu k"_-"

And (©) check if U, uppercased (u) and with _- removed (k), equals (¥) the same for V. Implicitly return the boolean result.

Python 2, 79 73 bytes

-6 bytes thanks to @notjagan: check the length of set of all reduced names is 1 or not.

lambda*l:len({x[0]+re.sub('-|_','',x[1:].lower())for x in l})<2
import re

Try it online!

Perl 5, 67 bytes

s/.//,push@a,$&,y/_-//dr for<>;say($a[0]eq$a[2]&&lc$a[3]eq lc$a[1])

Try it online!

Takes the identifiers as input on separate lines.

Explanation:

s/.//,             # remove the first character
push@a,            # storage space, even positions are first character
                   # odd positions are remainder
$&,                # implicit variable holding last matched pattern (first char)
y/_-//dr           # Remove _ and - from remainder of input
for<>;             # iterate over all input lines
say                # output
($a[0]eq$a[2]&&    # check that first character is identical and
lc$a[3]eq lc$a[1]) # so is the lowercase version of the rest

Retina, 28 bytes

T`L\_-`l_`(?<=.).+
^(.*)¶\1$

Try it online!

Charcoal, 29 bytes

∧⁼§θ⁰§η⁰⁼↧⪫⪪⪫⪪θ_ω-ω↧⪫⪪⪫⪪η_ω-ω

Try it online!

This prints a - for truthy and nothing for falsey.

Link to the verbose version. It first compares the first character of both input strings (⁼§θ⁰§η⁰) and then compares the rest of both strings after removing the underscores and the hyphens (⪫⪪⪫⪪θ_ω-ω) and converting to lowercase (↧).

C#, 101 89 bytes

string g(string s)=>string.Concat(s.ToUpper().Split('-','_'));f=>s=>f[0]==s[0]&g(f)==g(s)

Saved 12 bytes thanks to @kusi581.

Java (OpenJDK 8), 95 bytes

a->b->a.charAt(0)==b.charAt(0)&&a.replaceAll("_|-","").equalsIgnoreCase(b.replaceAll("_|-",""))

Try it online! Pretty straight forward.

Pyke, 13 bytes

F'hl1"-_"-)Xq

Try it online!

F         )   -  for i in input():
 'hl1         -   i[0], i.lower()
     "-_"-    -         ^.remove("-_")
           Xq - equal(^)

C (gcc), 126 114 bytes

#define p(s)do++s;while(*s==45||*s==95);*s>95?*s-=32:0;
f(char*a,char*b){while(*a&&*a==*b){p(a)p(b)}return*a==*b;}

Try it online!

With whitespace and comments:

#define p(s)                   // Define helper macro p           \
    do ++s;                    // Increment pointer at least once \
    while (*s==45 | *s==95);   // and past any '-' or '_'         \
    *s>95 ? *s -= 32 : 0;      // If lowercase letter, convert to upper

f(char* a, char* b) {          // Define main function f
    while (*a && *a == *b) {   // Loop until end of either string
                               // or a difference found
        p(a)                   // Transform pointer and one char
        p(b)                   // via helper p above
    }
    return *a==*b;             // Test chars equal (on success, both '\0')
}

Dyalog APL, 47 32 28 27 26 22 bytes

-4 bytes thanks to Kritixi Lithos

{(=/⊃¨⍵)∧≡/819⌶⍵~'-_'}   

Takes input as a list of the strings.

Try it online!

How?

{(=/⊃¨⍵)∧≡/819⌶⍵~'-_'}
               ⍵~'-_'   Remove '-' and '_'
           819⌶         Lowercase
         ≡/             Equality between elements
        ∧               And
 (=/⊃¨⍵)                The first element of each element is equal

Common Lisp, 98 bytes

(lambda(x y)(and(eql(elt x 0)(elt y 0))(string-equal(#1=remove #\-(#1##\_ y))(#1##\-(#1##\_ x)))))

Try it online!

Ungolfed (super straightforward!) version:

(defun f(x y)
  (and (eql (elt x 0) (elt y 0))         ; check if initial characters are identical
       (string-equal                     ; string comparison (case insensitive)
         (remove #\- (remove #\_ y))     ; remove from both strings the unwanted chars
         (remove #\- (remove #\_ x)))))

R, 76 bytes

function(l)(g=substr(l,1,1))[1]==g[2]&(h=tolower(gsub('-|_','',l)))[1]==h[2]

Anonymous function that takes input as a list of two strings. Takes advantage of the fact that R's string operations, while quite long in # of characters, are vectorized. Additionally wrapping an assignment in parentheses will bind the variable, so (g=substr(l,1,1)) retains a variable to be reused later in the line and similarly for h.

R returns the last evaluated expression as function output.

Ungolfed:

function(l){
  g <- substr(l,1,1)
  h <- tolower(gsub("_|-","",l))
  (g[1]==g[2])&(h[1]==h[2])
}

Try it online! (all test cases)

Brachylog, 17 bytes

hᵛ&{{¬∈"_-"&ụ}ˢ}ᵛ

Try it online!

Outputs through predicate success/failure.

h                    The first element
 ᵛ                   is the same for each element of the input,
  &                  and
   {           }ᵛ    for each element of the input the following are the same:
    {      &ụ}ˢ      every element uppercased which satisfies the condition that
     ¬∈              it is not an element of
       "_-"          the string "_-".

Erlang 113 bytes

A=fun(L)->string:to_lower(lists:flatten(string:tokens(L,"-_")))end,fun([C|D],[C|E])->A(D)==A(E);(_,_)->a==b end.

a pair of anonymous functions that compare the two lists. meant to be pasted in the erlang shell.

more readable:

A=fun(L) ->
    string:to_lower( % case insensitive
        lists:flatten( % squash all characters back into one list
            string:tokens(L,"-_") % return a list of list of characters
        )
    )
end.
fun([C|D],[C|E]) -> % are the first characters exactly the same?
    A(D)==A(E); % does the rest compare correctly?
   (_,_) -> % first chars not the same
    a==b % shorter than 'false'
end.

Clip, 25 bytes

&=(x(y=AxAy[Aa--m.L`a'-'_

Explanation:

x, y and z may be referenced in a Clip program to implicitly take up to three inputs. Since this program only references x and y, it takes two inputs which are assigned to x and y.

 =(x(y                    First characters of x and y are equal
&                         And
      =AxAy               A(x) == A(y)
           [Aa            Function A, takes parameter a
                m.L`a     Map all elements of a to lower case
              --     '-'_ Remove all occurrences of '-' and '_'

Takes two strings from standard input, outputs 1 and 0 for true and false respectively.