66

任务：

创建一个混淆的程序进行打印Hello World!（完全一样）。您的程序中可能没有任何字符串。

规则：

您可以使用任何喜欢的编程语言。
让它为模糊地
这是一场人气竞赛，因此投票最多的人将获胜。

注意：

这不是这个问题的重复。那是代码高尔夫，它有不同的规则。

popularity-contest obfuscation hello-world

— 医生
source

1

谁是第一个提交BF的人？:)

— 2014年

3

@VisioN-我认为BF并没有真正被混淆...

— TheDoctor 2014年

3

angerousmouse.net/esoteric/piet/hw1-11.gif是Piet中的Hello World程序。更多信息：dangermouse.net/esoteric/piet.html

— MatrixFrog 2014年

3

“那是代码高尔夫 ” 并不能使它不再重复。该规则似乎确实排除了从较早的问题中复制答案的原因，但主要是因为它们排除了所有答案：没有一个程序可以被更多地混淆。

— 彼得·泰勒

6

我不同意它们是重复的，原因不只是“另一个是代码高尔夫球”而已。代码高尔夫球员要求源代码中一定不要使用特定的字符子集，无论是否在字符串中。这些条目中的任何条目都不应与以下正则表达式匹配：/[dehlorw01]/。另外，长度是分级的。在这种情况下，它仅不需要使用字符串（并且可能不需要使用，也无需使用char[][]）。长度没有计算在内，但创造力是主要的决定性因素，因此，人气竞赛标签也是如此。

— Isiah Meadows'3

102

Python 2

我昨天碰巧正在玩这个游戏，所以：

(lambda _, __, ___, ____, _____, ______, _______, ________: getattr(__import__(True.__class__.__name__[_] + [].__class__.__name__[__]), ().__class__.__eq__.__class__.__name__[:__] + ().__iter__().__class__.__name__[_____:________])(_, (lambda _, __, ___: _(_, __, ___))(lambda _, __, ___: chr(___ % __) + _(_, __, ___ // __) if ___ else (lambda: _).func_code.co_lnotab, _ << ________, (((_____ << ____) + _) << ((___ << _____) - ___)) + (((((___ << __) - _) << ___) + _) << ((_____ << ____) + (_ << _))) + (((_______ << __) - _) << (((((_ << ___) + _)) << ___) + (_ << _))) + (((_______ << ___) + _) << ((_ << ______) + _)) + (((_______ << ____) - _) << ((_______ << ___))) + (((_ << ____) - _) << ((((___ << __) + _) << __) - _)) - (_______ << ((((___ << __) - _) << __) + _)) + (_______ << (((((_ << ___) + _)) << __))) - ((((((_ << ___) + _)) << __) + _) << ((((___ << __) + _) << _))) + (((_______ << __) - _) << (((((_ << ___) + _)) << _))) + (((___ << ___) + _) << ((_____ << _))) + (_____ << ______) + (_ << ___))))(*(lambda _, __, ___: _(_, __, ___))((lambda _, __, ___: [__(___[(lambda: _).func_code.co_nlocals])] + _(_, __, ___[(lambda _: _).func_code.co_nlocals:]) if ___ else []), lambda _: _.func_code.co_argcount, (lambda _: _, lambda _, __: _, lambda _, __, ___: _, lambda _, __, ___, ____: _, lambda _, __, ___, ____, _____: _, lambda _, __, ___, ____, _____, ______: _, lambda _, __, ___, ____, _____, ______, _______: _, lambda _, __, ___, ____, _____, ______, _______, ________: _)))

这是一个更具可读性的版本：http : //codepad.org/UzSmoxF2

笔记：

一行，单个表达式（即没有打印语句）。
没有字符串，没有整数；仅函数，属性访问，列表，元组，基本数学，一个True和一个星型参数。
最小的内置用法（__import__，getattr和chr，每个一次）。
有效载荷可以轻松更改。这是我编写的生成程序。

编辑：我在Blog上对它的工作原理做了相当实质性的解释。

— 本·库尔托维奇（Ben Kurtovic）
source

7

真好高度可读。

— devnull 2014年

45

“更具可读性的版本”

— ASKASK，2014年

2

恭喜100！

— 科纳·奥布赖恩

64

的JavaScript

([]+/H/)[1&11>>1]+(+[[]+(1-~1<<1)+(~1+1e1)+(1%11)+(1|1>>1|1)+(~1+1e1)+(.1^!1)])[[([]+!![
11])[11^11]+[[{}]+{}][1/1.1&1][1]]+([[]+111/!1][+!1][([{}]+{})[1e1>>1]+[[],[]+{}][1&11>>
1][1|[]]+([]+[][111])[1&1]+[{},1e1,!1+{}][~~(1.1+1.1)][1^1<<1]+(11/!{}+{})[1-~1<<1]+[!!{
}+[]][+(11>11)][[]+1]+(/^/[1.11]+/&/)[.1^!1]+[{},[{}]+{},1][1&11>>1][1+1e1+1]+([]+!!{})[
.1^!1]+([]+{}+[])[[]+1]+[!!{}+{}][!11+!111][[]+1]]+[])[(!/~/+{})[1|1<<1]+[/=/,[]+[][1]][
1&11>>1][1&1>>1]+([]+{})[~~(1.1+1.1)]+[1,!1+{}][1%11][1^1<<1]+(111/[]+/1/)[~1+1e1+~1]+[!
!/-/+[]][+(11>11)][1]]((1<<1^11)+((+(1<1))==([]+/-/[(!![11]+[])[+!1]+(!!/-/+{})[1-~1]+([
]+!/~/)[1-~1]+(!!/-/+{})[!111+!111]])[11%11]),-~11>>1)](~1-~1e1<<1<<1)+([]+{111:1111}+[]
)[11111.1%11.1*111e11|!11]+({}+/W/)[1+~1e1-(~11*1.1<<1)]+(+[[]+(1|1>>1)+(1|1>>1|1)+(11-1
>>1)+(1e1>>1|1)+(1e1>>1)+(1>>11)+(11>>>1)])[[(!!{}+[])[11>>>11]+[[]+{}][.1^!1][111%11]]+
([11/[]+[]][111%111][([{}]+[{}])[1e1>>1]+[[],[{}]+[{}]][1|1>>1|1][1|[]]+([][11]+[])[[]+1
]+[{},1e1,![1]+/~/][1<<!1<<1][1<<1^1]+(1/!1+{})[11+1>>1]+[!!/-/+{}][+(111>111)][111%11]+
([][11]+/&/)[1&1>>1]+[{},[]+{}+[],1][[]+1][11-~1+11>>1]+([]+!!/-/)[11>>11]+([]+{})[1|1>>
1|1]+[[]+!!{}][1>>>1][1&11]]+[])[(!{}+[])[1^1<<1]+[/=/,[]+[][1]][1<<1>>1][!111+!111]+([]
+{}+[])[1<<1^1>>1]+[1,![11]+[]][1|1>>1][1|1<<1|1]+(11/[]+/1/)[-~11>>1]+[!![111]+{}][+[]]
[1|1>>1]]((1e1-1)+((1&1>>1)==([]+/-/[(!!{}+{})[+(1>1)]+(!!/-/+{})[1|1<<1]+(!1+{})[1|1<<1
|1]+(!!/-/+{})[11.11>>11.11]])[1&1>>1]),1-~1<<1)](~1-~1e1<<1<<1)+(/^!/+[])[1+!![11%111]]

可以在StackOverflow的此答案中找到其工作方式的说明。

_{只需在浏览器控制台中运行即可（例如，在Firebug或Chrome开发工具中）。}

— 视力
source

50

C

乘法称呼：

#include <stdio.h>
main() {
  long long P = 1,
            E = 2,
            T = 5,
            A = 61,
            L = 251,
            N = 3659,
            R = 271173410,
            G = 1479296389,
            x[] = { G * R * E * E * T , P * L * A * N * E * T };
  puts((char*)x);
}

— 吱吱作响的骨
source

您不能有STRING！

— Mukul Kumar'3

19

我不认为他用过弦。他只是在打字。

— microbian

3

这很聪明-尽管有外观（甚至不应该使用'unsigned long long'），甚至不涉及未定义的行为-但仅适用于little-endian系统。

— zwol 2014年

50

的PHP

<?=${[${[${[${[${[${[${[${[${${![]}.=[]}.=${![]}{!![]}]}.=${!![${[${[
${[${[${[${[${[]}++]}++]}++]}++]}++]}++]}++]}{![]+![]+![]}]}.=${[${[$
{[${[${[]}++]}++]}++]}++]}{![]}]}.=${[${[${[${[${[${[${[${[]}++]}++]}
++]}++]}++]}++]}++]}{![]+![]}.${[]}{![]+![]}]}.=${![]}^${!![${[${[${[
]}++]}++]}++]}{![]+![]+![]}]}.=${[]}{!![]}]}.=${[${[${[${[${[${[${[${
[${[${[${[${[${[${[${[${[]}++]}++]}++]}++]}++]}++]}++]}++]}++]}++]}++
]}++]}++]}++]}++]}{![]+![]+![]+![]}.${[]}{![]+![]+![]+![]}]}.=${[${[$
{[${[]}++]}++]}++]}{![]+![]}.${![]}{![]+![]+![]}]}.=${[${![]}=${![]}{
!![]}]}{!![${!![${!![${![]}++]}++]}++]}^${!![${[${[${[]}++]}++]}++]};

我已经将其翻译成一个声明，我认为这样很难解释。此版本仅使用13个唯一字符。

原始版本

<?${[]}.=[];${![]}.=${[]}{!![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${
![]};++${![]};${![]}.=${[]}{![]+![]+![]};++${![]};++${![]};++${![]};++${![]};${![
]}.=${![]}{![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};${
![]}.=${![]}{![]+![]}.${![]}{![]+![]};++${![]};++${![]};++${![]};${![]}.=${[]}^${
[]}{![]+![]+![]};${![]}.=${![]}{!![]};++${![]};++${![]};++${![]};++${![]};++${![]
};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]
};++${![]};${![]}.=${![]}{![]+![]+![]+![]}.${![]}{![]+![]+![]+![]};++${![]};++${!
[]};++${![]};${![]}.=${![]}{![]+![]}.${[]}{![]+![]+![]};++${![]};++${![]};++${![]
};${[]}=${[]}{!![]};++${[]};++${[]};++${[]};${![]}.=${[]}^${![]}{![]}?><?=${![]};

14个独特字符。我可以编写一个脚本来生成这些文件并将其复制为“ PHPFuck”，但是我认为它不会非常有用。

这个怎么运作

当将一个数组（包括空数组）强制转换为字符串时，结果始终是非常有用的字符串“ Array”。我不确定谁认为这是个好主意。PHP支持字符串的递增运算符（但不递减），例如“ ++ A”→“ B”。原始字符串同时包含“ A”和“ a”，因此所有拉丁字符都可以被生成，即为混蛋风格。用“ A” ^“ a”产生空间，用“ D” ^“ e”惊叹号。

— 原始
source

我对如何创建脚本来生成这种混淆感到非常好奇，如果您有5分钟的讨论时间，我将不胜感激=]我将在chat.stackexchange.com/rooms/13342/weirdest中

— 杰弗里·罗伯茨

我只是看了看jsfuck的源代码，有趣的是……我期待的是比char map更动态的东西=] ...如果有人要加入，我会在那个房间里感到很冷=]

— Jeffrey L. Roberts

2

这比其中包含/H/和的Javascript答案要好得多/W/。

— durron597 2014年

39

的PHP

这是一个简单的PHP脚本，输出Hello World!：

<?php
function SGVsbG8gV29ybGQh($_ = 0) {(
    $___=__FUNCTION__
    )&&
    !$_ and list($_,$__) = array_values(array_filter($___(42), $___)) and
    !$_($__($___)) and
    $___($___); return
    $_
    &42
    ?current(get_defined_functions()):(
    !((
    $_=md5($_))-42*2)or
    !(md5($_ = md5($_))-42/2
    *3)
);};

SGVsbG8gV29ybGQh();

单击此处进行演示。

— 拉兹万
source

11

我仍然不知道为什么会打印任何内容。

— 2014年

1

@primo函数名称是关键;)

— VisioN

Base64解码？

— Linuxios 2014年

也可以，但还多一点。

— 拉兹万2014年

1

@Razvan您是否尝试过所有内置函数，检查是否只有两个散列以84和63开头？那太好了！

— 2014年

34

空格

维基百科：空白（编程语言）
在线口译测试题

该程序通过以下步骤推送ASCII字符代码（从解释器调试侧栏中获取）：

推72
印刷品
推101
印刷品
推108
印刷品
推108
印刷品
推111
印刷品
推32
印刷品
推87
印刷品
推111
印刷品
推114
印刷品
推108
印刷品
推100
印刷品
推33
印刷品
结束

— 格罗夫斯NL
source

8

要获得额外的积分，也可以将其与非空白字符结合使用。

— zebediah49 2014年

33

Bash（在Linux下）

希望您的Shell脚本看起来不是这样：

:; ______=$? __=${#______} ____=$[__+__] ________=$[__+____] _____=$[____+____]
     __________=$[____+_____] _________=$[__+__________] ______________=(
            /????/$$/????) ____________=${______________[$______]} 
   _____________=${____________##*/} _______________=(${____________//\// })
          ________________=${_______________: -$__:$__}$_____________
           ___________________=${________________:$______:$________}
   ___________=${_____________:$______:$__} _________________=${___________^}
     . <($___________________<<<__________________=\({$_________________..\
${___________}}\))&&_______=(${__________________[@]:$______:$____$__________})
  ___=(${_______[@],,})&&${___[$_____]}${___[$____]}${___[$_________]}${___[
$__$_____]} -${___[$_____]} ${_______[ $_________]}${___[${_____}]}${___[$__$__
]}${___[$__$__]}${___[$__$_____]} ${_______[$____$____]}${___[$__$_____]}${___[
$__$_________]}${___[ $__$__]}${___[$________]}\\$______$[$_____#$____$____$__]

不是一个字母数字字符-考虑到这一限制，似乎很难进行进一步的混淆
没有字符串（始终没有引号）
对Linux有依赖性-特别是该attr文件是文件名中第/proc/$PID一个包含4个字符的文件

看看是否可以发现隐藏的对象eval。

— 数字创伤
source

SO渲染似乎存在一些限制：我说最后一行可以以${__[${____}]}${__[${__________}]}${__[${_______}]}${__[${___}${____}]} -${__[${____}]} （echo -e）开头，并! 以\\${_________}${____}${___}

— F

或更糟糕的是：\\${_________}$[${______}${____}#${_____[${___________}+${__________}]}]也要有一个感叹号；-)

— F. Hauri 2014年

这很漂亮。但是有两个问题：（1）它不太可移植，我无法像在BSD上那样运行它。（2）脚本假定_________将其设置为0（如果在source错误后替换为d ，会发生什么情况？）。

— devnull 2014年

@devnull 2）易于修复-只需运行:命令以清除中报告的任何先前的错误情况$?。

— Digital Trauma 2014年

3

@devnull对不起，除了自鸣得意的自我满足感之外，没有奖品;-)

— Digital Trauma

29

高尔夫脚本

[' '(..4/++][' '(3*)))))][6`(2*.]['1'..++~][8 2?2/][' '(4/.(`\`\+~]['1'.+~2?10-][13(1)?8((0)))))*-][6`(1)*]['('(4/2?][' '()]+++++++++++

创建和调试它非常具有挑战性。它不包含字符串，仅包含字符。

它输出：

你好，世界！

在线测试

说明

工作原理：

[' '(..4/++]
1. ' '(将空格转换为其ASCII代码：32。
2. ..重复32两次。现在你有三遍了32。
3. 4/将顶部32除以4。现在您有两次32，一次8。
4. ++加起来的32，32和8。您将得到72，这是的ASCII码H。
[' '(3*)))))]
1. ' '(将空格转换为32。
2. 3*乘以32具有3：96
3. )))))增加965，得到101，这是的ASCII码e。
[6`(2*.]
1. 6`(给出char的ASCII代码6：54
2. 2*将其乘以2，得到108，这是的ASCII码l。
3. . 复制 l
['1'..++~]
1. '1'..将char 1放在堆栈上，并重复两次。
2. ++ 连接三个字符并返回字符串 111
3. ~将其转换为整数111，即的ASCII码o
[8 2?2/]
1. 8 2?计算8 ²，你得到64
2. 2/将其除以2，得到32，这是空格的ASCII码。
[' '(4/.(`\`\+~]
1. ' '(将空格转换为32。
2. 4/.将其除以4，得到8。在.重复它。
3. (`递减第二个8并将其转换为字符串。
4. \交换前两个元素。在8成为顶部元件。
5. `将转换8为字符串。
6. \交换前两个元素。在7成为顶部元件。
7. +连接两个字符串。您得到87（作为字符串）。
8. ~将字符串87转换为整数87，即的ASCII码W。
['1'.+~2?10-]
1. '1'.将char 1放在堆栈上并复制它。
2. +~将两个字符连接到字符串11并将其转换为整数。
3. 2?计算11 ²，你得到121。
4. 10-减少12110，您将获得的ASCII码o：111。
[13(1)?8((0)))))*-]
1. 13(放在12堆栈上。
2. 1)放在2堆栈上。
3. ?算出12 ²，你得到144。
4. 8((放在6堆栈上。
5. 0)))))放在5堆栈上。
6. *乘法6和5，你会得到30。
7. -substracts 144用30，你得到114，这是ASCII码r
[6`(1)*]
1. 6`(转换6为char并采用其ASCII码：54
2. 1)*乘54用2，你得到108的ASCII码l
['('(4/2?]
1. '('(转换(为其ASCII码40。
2. 4/分40通过4，你会得到10。
3. 2?计算10 ²，得到100，它是的ASCII码d
[' '()]
1. ' '( 将空格转换为其ASCII代码： 32
2. )递增32，您得到33，这是的ASCII码!
+++++++++++ 将所有ASCII代码连接为一个字符串。

— 程序FOX
source

11

+1是一个很好的解释。由于某些原因，这对于golfscript答案是不寻常的。

— Digital Trauma'3

@DigitalTrauma我敢肯定有一个很好的理由

— qwr

2

这是我第一次看到GolfScript针对通常不容易解决的问题的解答。

— 维克多·斯塔夫萨

20

Brainf ***

不知道这是否算作模糊处理，但它永远不会在一行中使用四个以上的加号或减号。就是这样。

>>+++[<+++>-]<+[>+++>>+++[<+++>-]<+[<]>-]<+++[>+++<-]>+[>++++<-]>++.>+.>+++
[<++>-]<+..+++.<<<+++[>+++<-]>+[>----<-]>.>[>+>+<<-]++++[>++<-]>.>.+++.>++[
<--->-]<.>++[<---->-]<.<<<+.

— 乔沃斯蒂
source

14

+1可以说任何话Brainfuck可能不会算作混淆。

— RubberDuck

同时，早在1992年...“每个程序都可能被混淆！并且每个程序都被混淆...” <UrbanMüller邪恶地笑着>“ 没有程序会...”

— 骑师赛马

19

Mathematica

简单的代数我数学。

a=+x+8x^2+8(x^3+x^9);
b=11(x^4+x^7)-68x^5-13x^6;
c=-28+14x^8-67x^11;
w=ToExpression[Names[__][[1571]]];  
v=ToExpression[Names[__][[604]]]; 
y=Solve[a+b+c,{x},Reals];  
w[v[y[[1]],x]+100]

你好，世界！

— 戴维
source

2

FromCharacterCode打破了所有的阴谋……

— VisioN

1

VisionN，FromCharacterCode现在变得模糊。也是如此CoefficientList。

— DavidC 2014年

17

C

#define u unsigned char
#define v while(*x)
#define z(x) putchar(*x);
#define y(x) ++*x;
#define p(x) ++x;
#define e(x) --*x;
#define d(x) --x;
#define w(x) x x
main(){u *x=calloc(12,1);u *l=x;w(w(w(y(x))))w(y(x))v{p(x)w(w(y(x)))w(y(x))y(x)p
(x)w(w(w(y(x))))w(y(x))p(x)w(y(x))y(x)p(x)w(w(w(y(x))))y(x)w(w(d(x)))e(x)}p(x)w(
y(x))z(x)p(x)y(x)z(x)w(w(y(x)))w(y(x))y(x)w(z(x))w(y(x))y(x)z(x)p(x)w(y(x))z(x)p
(x)w(e(x))e(x)z(x)w(d(x))z(x)w(y(x))y(x)z(x)w(w(e(x)))w(e(x))z(x)w(w(w(e(x))))z(
x)p(x)y(x)z(x)free(l);}

元混淆。通过预处理器运行此代码，您可以：

main(){unsigned char *x=calloc(12,1);unsigned char *l=x;++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x;++*x; ++*x;while(*x){++x;++*x; ++*x; ++*x; ++*x;++*x; ++*x;++*x;++x;
   ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x;++*x; ++*x;++x;++*x; ++*x;++*x;++x;++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x;++*x;--x; --x; --x; --x;--*x;}++x;++*x; ++*x;
     putchar(*x);++x;++*x;putchar(*x);++*x; ++*x; ++*x; ++*x;++*x; ++*x;++*x;putchar(*x); putchar(*x);++*x; ++*x;++*x;putchar(*x);++x;++*x; ++*x;putchar(*x);++x;
   --*x; --*x;--*x;putchar(*x);--x; --x;putchar(*x);++*x; ++*x;++*x;putchar(*x);--*x; --*x; --*x; --*x;--*x; --*x;putchar(*x);--*x; --*x; --*x; --*x; --*x; --*x; --*x; --*x;putchar(*x);
  ++x;++*x;putchar(*x);free(l);}

输出：

你好，世界！

编辑：添加了语法突出显示以便清楚。:-P

— 共产国际
source

3

真好以前从未见过C中使用过BF逻辑。

— Isiah Meadows'3

@OP删除u *l=x;并free(l);给我相同的结果。

— Lucas Henrique 2015年

@IsiahMeadows什么是BF逻辑？

— YoTengoUnLCD '16

@YoTengoUnLCD Brainfuck

— Isiah Meadows

15

智者

for i in 5105882569598991528047304.digits(1+sum(2**j for j in 11382954456.digits(42))):
    sys.stdout.write(chr(i))

说明：

11382954456.digits(42) 将11382954456转换为基数42，并给出其数字的数组，即 [6, 1, 0, 5, 4, 3, 2]

所以sum实际给出的总和是1 + 2 + 4 + ... + 32 + 64，即127

然后5105882569598991528047304.digits(...)将数字转换为以128为底的基数[72, 101, 108, 108, 111, 32, 87, 111, 114, 108, 100, 33]

这些是要打印的字符串的ASCII码。

— ace_香港独立
source

3

之前从未听说过圣人

— TheDoctor 2014年

@TheDoctor编辑为在Sage网页上添加超链接。

— ace_HongKong独立2014年

它看起来很像python

— TheDoctor 2014年

@TheDoctor，因为Sage基于python

— ace_HongKongIndependence 2014年

15

Javascript（28187个字符）

可能不是向这个世界打招呼的最短方法。

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用JSFuck生成

— 迈克尔·M
source

3

+1我也愿意发布JSFuck答案，但是您首先这样做。

— Victor Stafusa 2014年

5

可能您应该提到您已经使用JSFuck生成了此代码。

— 2014年

3

重复的codegolf.stackexchange.com/q/17950/3103。是的，有更短的方法可以做到这一点。

— Konrad Borowski

12

C：

#include <stdio.h>
#define BING(x,y) ((x)<<y)
#define BANG(x)   (1<<x)
#define BOOM      1
int main () {
  int x,y,z,w;
  int V[3] = {BING(x=227380393,BANG(BOOM)+BOOM), x+(w=BOOM+BANG(BANG(BOOM)),
              BING(47*y=17453197,BOOM)), x+y+BING(w*w*17*185527,BANG(BOOM))};
  char *p=V;
  while(*(p-BOOM)!=BOOM+BING(BOOM,w)) putchar(*p++);
  return 0;
} /* Mind the comma operator! */

输出：

Hello World!

— 递归忍者
source

有一些移位的整数数组...玩得很好。我也喜欢最后一个右移很大的数字。

— Isiah Meadows'3

12

马尔博格

('&%:9]!~}|z2Vxwv-,POqponl$Hjig%eB@@>}=<M:9wv6WsU2T|nm-,jcL(I&%$#"
`CB]V?Tx<uVtT`Rpo3NlF.Jh++FdbCBA@?]!~|4XzyTT43Qsqq(Lnmkj"Fhg${z@>

要么

(=<`#9]~6ZY32Vx/4Rs+0No-&Jk)"Fh}|Bcy?`=*z]Kw%oG4UUS0/@-ejc(:'8dc

我不知道这是如何工作的。

^{资料来源：http : //en.wikipedia.org/wiki/Malbolge#.22Hello_World.21.22_in_Malbolge}

— 帽子的家伙
source

8

我很确定Malbolge的要点是没有人知道它是如何工作的。

— Edmund Schweppe 2014年

@EdmundSchweppe是的，但并非所有人都知道。

— 帽子的家伙

您击败了我（+1）。

— arshajii 2014年

1

但是有人以某种方式使用Malbolge完成了99瓶挑战：99-bottles-of-beer.net/language-malbolge-995.html 实际上，其他人也做到了：99-bottles-of-beer.net /language-malbolge-375.html

— KBKarma 2014年

11

爪哇

这里是。你能理解它的工作原理吗？

警告：非常易挥发。将来可能会自然中断。

import java.io.ByteArrayOutputStream;

public class MysteryCode {
    public static void main(String[] unused) throws Exception {
        ByteArrayOutputStream stoned = new ByteArrayOutputStream(20480);
        int[] magic = {104, 116, 116, 112, 58, 47, 47, 98, 105, 116, 46, 108, 121, 47, 49, 98, 87, 119, 51, 75, 111};
        for (int weird : magic) stoned.write(weird);
        int crazy, unknown = 0;
        java.io.InputStream wtf = new java.net.URL(stoned.toString()).openStream();
        while((crazy = wtf.read()) != -1) stoned.write(crazy);
        for (int strange : stoned.toByteArray()) {
            if (unknown == 2) {
                if (strange == 38) break;
                System.out.print((char) strange);
            } else if (17 + (unknown + 1) * 21 == strange) {
                unknown++;
            }
        }
    }
}

— 维克多·斯塔夫萨（Victor Stafusa）
source

1

有趣的是，您为此页面构建了一个解析器。做得很好

— Cruncher 2014年

4

我想您不介意有人为这个问题更改标题吗？;）

— Cruncher 2014年

2

@Cruncher我认为问题的标题是完美的，并且绝对没有理由对其进行更改。;)

— 维克多·斯塔夫萨

5

有趣的是，与使用x，y，z相比，使用诸如crazy，unknown和奇怪的变量名更难以阅读。区分x，y和z很容易，但是（psuedo-）同义词可能会使您失望。

— Cruncher

4

while((crazy = wtf.read()) != -1) stoned.write(crazy);xD

— Cruncher

10

Befunge

上面写着“ Hello，World！”的代码：

>55+7*2+,  v >4*4+v
              ,
v,+1*+55+55< +v55<>55+3*2+,v
>55+55+*8+,v 5+  +v,+7*8+55<
v,+8*+55+55< 5*  5>55+55+*56++,v
>55+55+*56++,^8  5v,++59*+55+55<
v+55,*+55+55,+<  ^<
>3*3+,@

显示“ Hello World！”的代码：

>55+7*2+,  v >    v

v,+1*+55+55<  v55<>55+3*2+,v
>55+55+*8+,v  +  +v,+7*8+55<
v,+8*+55+55<  *  5>55+55+*56++,v
>55+55+*56++,^8  5v,++59*+55+55<
v+55,*+55+55,+<  ^<
>3*3+,@

— Misteriggy
source

嗯，一开始它说的是“ Hello，World”（带逗号），而新的人说的是“ Hello World”（不带逗号）。

— Misteriggy 2014年

现在，我对其进行了重新编辑。

— Misteriggy 2014年

哦。现在，修订版2更有意义。我只在编辑时看到修订版1（不知道为什么）。抱歉造成混乱。

— 约翰·德沃夏克

没问题...很高兴，这很有意义:)

— Misteriggy 2014年

10

Befunge 98-7610个字符

'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,  '/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,@

根据我在这里的答案：https：//codegolf.stackexchange.com/a/15736/9498

另外，此答案不使用任何数字，也不包含多余的字符（也就是说，不存在可以删除的字符组合，从而产生相同的输出）。

尝试一下这里（粘贴代码，更换的每个实例'/'[有"/["）：http://www.quirkster.com/iano/js/befunge.html

这个怎么运作：

'/'[\/ 等于1，所以所有这些操作就是递增到相应的ASCII值，然后打印。

额外的好处：这篇文章很长，以至于需要大约1秒钟的时间，stackexchange才能认识到撰写本文的变化。

— 贾斯汀
source

尽管您仍在使用字符串...甚至“ / [”是一个字符串。

— Misteriggy

@Misteriggy Whoops错过了该要求。正在修复...

— 贾斯汀

@Misteriggy在那里。现在，它不使用字符串。

— 贾斯汀

10

Brainf ** k

它很模糊，但是再简单不过了。

+   +  +++++  +      [         >++
+   +  [      >      +        +   >
+++>+  ++>+<  <      <        <   -       
]   >  +      >      +        >   -    >
>   +  >+[<]  <-]>>  .>---     .++    +

+   +   ++.   .+++   .        >>.<     -
W . <  .   +  +   +  .        -   -    -
- - -  .   -  ----   -        -   -    .
 > >   +   .  > +    +        .   <
        >>>   <  <   >>><<    <><>     >

因为当您仔细观察时：

H   H  EEEEE  L      L         OOO
H   H  E      L      L        O   O
HHHHH  EEEEE  L      L        O   O       
H   H  E      L      L        O   O     ,
H   H  EEEEE  LLLLL  LLLLL     OOO     ,

W   W   OOO   RRRR   L        DDDD     !
W W W  O   O  R   R  L        D   D    !
W W W  O   O  RRRR   L        D   D    !
 W W   O   O  R R    L        D   D
        OOO   R  R   LLLLL    DDDD     !

— ASCII然后是ANSI
source

7

的JavaScript

没有数字文字，没有字符串文字，只有一个函数（不包括console.log）！

var ________________ = [] + []; var _ = +[]; _++; var _____ = _ + _;
var ___ = _____ + _____; var __ = ___ + ___; var ____ = __ + __; var ______ = ____ + ____;
var _______ = ______ + _; var ___________ = ______ + ______ + __;
var ______________ = ___________ + ____ -  _; var ____________ = _ + _____;
var ________ = _______ * ____________ + _; var _________ = ________ + _;
var _____________ = ______________ + ______ - ___ - _; var __________ = _____________ -
____________; var _______________ = __________ - ____________; console.log(________________ +
String.fromCharCode(___________, _________, _______________, _______________, __________,
______, ______________, __________, _____________, _______________, ________, _______));

这里的示范。

— 戴帽子的家伙
source

但这不是[]文字吗？

— Ismael Miguel 2015年

@IsmaelMiguel可能是正确的，但这不是数字或字符串文字。

— 戴帽子的家伙

1

对不起，我听错了你在说什么。您说了No number literals，但我跳过了这个号码。如果需要，可以Array()改用。那不是字面意思。这会使它更加混乱。或者，你可以使用+false的+[]。甚至Array()-Array()。

— Ismael Miguel 2015年

7

Python 2.6以上

p = lambda x: ( -13214 * x**11 + 956318 * x**10 - 30516585 * x**9 + 564961485 * x**8
                - 6717043212 * x**7 + 53614486464 * x**6 - 291627605005 * x**5
                + 1074222731065 * x**4 - 2606048429424 * x**3 + 3927289106268 * x**2
                - 3265905357360 * x + 1116073728000 ) / 19958400

print bytearray(map(p, range(1, 13)))

没有字符串，只有一个简单的多项式函数。

— 伊尔马里·卡洛宁（Ilmari Karonen）
source

6

这种编程语言

            'Alice'++++7/4+v
v     -9/3++'was'          <
>           'beginning'++++++++9/3+v
v      -5/2+'to'                   <
>           'get'++3/5+v
v  -&81/9+++'very'     <
>           'tired'++++6/2-v
v      +5/2+'of'           <
>           'sitting'++++++7/4+v
v      -1/2+'by'               <
>           'her'++3/6-v
v-&14/9+++++'sister'   <
>           'on'~~v
v        ~~~'the' <
>           'bank.'~~~~~s;

你能猜出它做什么吗？
也许您必须更深入地研究发现。

免责声明：编程语言比挑战要新。

— 鲍勃·真棒
source

这是一个值得免责的声明。

— 2015年

口译员被可汗学院的新规范所破坏，我需要找到一种解决方法。我想我可以通过嵌入HTML页面来绕过规范。

— BobTheAwesome

5

C

int main() {
    // Some floating point numbers for testing
    float b[] = {1.1431391224375825e+27, 6.6578486920496456e+28, 7.7392930965627798e-19, 3.2512161851627752e-9};
    // Print all numbers in array b[]
    puts(b);

    return 0;
}

这些评论只是在误导不了解情况的读者。

构造常量以使它在内存中的表示（对于Little-endian系统）与string相同"Hello World!"。然后将数组（对指针的衰减）传递给puts，在其中puts盲目将其视为a char*并打印所有内容，直到命中为止NUL（该代码编码在最后一个数字中）。

该代码将编译（带有警告）并使用gcc 4.7.0（Windows 7 32位）输出预期输出。

— n̴̖̋h̷͉̃a̷̭̿h̸̡̅ẗ̵̨́d̷̰̀ĥ̷̳
source

5

爪哇

class M‮{public static void main(String[]a‭){System.out.print(new char[]{'H','e','l','l','o',' ','W','o','r','l','d','!'});}}

在这里测试。

我知道，使用字符而不是字符串有点me脚。奇怪它运行正常。是不是

— 第一名
source

2

等等...什么？！这背后的机制是什么？

— 马修·塞恩斯伯里

2

M后面有一个Unicode 字符“ RIGHT-TO-LEFT OVERRIDE ”，而M前面有一个相反的字符（从左到右）a[]。

— 史蒂夫·本内特

3

C（老实说，90％的C预处理器）：

#if __COUNTER__ == 0
#define Y
#define X(a) a##ng a##ng
#define values(a,b,c,d) _ d c = b 5237610348992605899, -8965656808041882953, -3202399561689361469, -7073034487879198273, -7020069900579512688, -33906882022564967 a
#define W(a) (){
#define _Q(a,b,c,d,e) e##a##d##e##c 0; b
#define Q(a,b,c,d) _Q(a,b,c,d,r)
#define K (char
main W(lo) X(lo) values(},{,],[);
#endif
#ifndef T
#undef W
#define W _-
#define Z 35
#define T Y+0
#endif
putchar((*_=(X(lo))(K*)(_+((*W 1)&-(*W 0)|!T))+__COUNTER__),~*K*)(*W 1)));
#if __COUNTER__ <= Z
#include "main.c"
#else
Q(e,},n,tu)
#endif

仅适用于gcc或支持该__COUNTER__宏的其他编译器。

— 接近黑暗鱼
source

3

（我知道这不是很奇怪。）

直流电

dc<<<"8 9*P101P108P108P111P4 8*P81 6+P111P114P108P100P33P"

输出：

Hello World!

— 恶魔
source

1

我得到“ Hello World！$”，其中$是我的提示。最后添加10P以获得换行符。

— Glenn Randers-Pehrson 2014年

或者dc<<<5735816763073005734600101863690P

— Digital Trauma 2015年

3

C＃

没有字符串或字符文字，但字符串函数的使用。通过腐烂进行混淆13。

using System;
using System.IO;

namespace CodeGolf
{
    /// <summary>
    /// Jevgrf "Uryyb Jbeyq!" gb gur pbafbyr.
    /// </summary>
    /// <remarks>
    /// <para>Guvf cebtenz vf n cebcbfrq fbyhgvba gb dhrfgvba 
    /// ahzore 22533 ng pbqrtbys.fgnpxrkpunatr.pbz:</para>
    /// <para>Perngr na boshfpngrq cebtenz gung cevagf Uryyb 
    /// Jbeyq! (rknpgyl yvxr gung). Lbhe cebtenz znl abg unir 
    /// nal fgevatf va vg.</para>
    /// <para>Fnyhgba Zbaqb vf Rfcrenagb sbe Uryyb Jbeyq.</para>
    /// </remarks>
    class FnyhgbaZbaqb
    {
        class Genafyngbe
        {
            int bssfrg = 0;
            public char Genafyngr(string vachg)
            {
                return vachg.Length < 6
                    ? (char)(37 + (bssfrg -= bssfrg) - vachg.Length)
                    : vachg.ToCharArray()[bssfrg++];
            }
        }
        enum UryybJbeyq
        {
            Hoover,
            Denver,
            WillowPrimus,
            WillowSecundus,
            WillowTertius,
            Fnord,
            Wintergreen,
            Copacetic,
            Pursuing,
            Follicle,
            Remedies,
            Bang
        }
        void Terrg(TextWriter tw)
        {
            Genafyngbe gf = new Genafyngbe();
            foreach (var enumVal in Enum.GetNames(typeof(UryybJbeyq)))
            {
                tw.Write(gf.Genafyngr(enumVal));
            }
            tw.WriteLine();
            tw.Flush();
        }
        static void Main(string[] args)
        {
            FnyhgbaZbaqb urryb = new FnyhgbaZbaqb();
            urryb.Terrg(Console.Out);
            Console.ReadLine();
        }
    }
}

— 埃德蒙·史威普（Edmund Schweppe）
source

如何对

— 4byte

@ masterX244非常好，谢谢:-)

— Edmund Schweppe

@ masterX244提示：它遍历UryybJbeyq枚举的名称，并根据名称的长度增加从名称中抓取哪个字母的索引或重置索引。

— Edmund Schweppe 2014年

好的:)现在我看到了

— masterX244 2014年

3

C

#include <stdio.h>
#define o stdout
#define p fputs
int main(_){int*I=&_,_I=2113,l1=3271;_=14557;_I*=503;_<<=3;_*='=';_I<<=0==0;_I=7*'Y'*853<<2;
p(I,o);I=&_I;p(I,o);I=&_;

    _+= l1*11*11;

_I += 0xF5<<8;p(I,o);I=&_I;p(I,o);}

没有字符串，没有数组，没有字符，很少有明显的“数据存储大常量”。

— vsz
source

3

> <> （鱼）

我为> <>中的指令指针做了一个迷宫

>v ^3::+7:\v-<  /8<
v>6c*aa*1+/>!^:!/3 \
>l?\;| !:6!+-!3:!<^>,r
\ o/+:&84*:3*9-&:^

在线> <>此处的口译员

— 蒂斯·哈尔
source

3

C ++

#include<iostream>
int main()
{
    char    g=16777288,
            r=16777317,
            e=16777324,
            t=16777327,
           sp=16777248,
            w=16777303,
            o=16777327,
            R=16777330,
            l=16777324,
            d=16777316,
           ex=16777249;
    std::cout
            <<g
            <<r
            <<e
            <<e
            <<t
                <<sp//space
                    <<w
                    <<o
                    <<R
                    <<l
                    <<d
                        <<ex;//exclamatory
    return 0;
}

输出量

Hello World!

— 穆库尔·库马尔（Mukul Kumar）
source

1

如果您摆脱了常数o和l，我会更愿意支持您。您不需要它们，而是使用r和t。

— 级圣河

2

@steveverrill不会显示我想要的演示文稿...“迎接世界”我仍然会尝试

— Mukul Kumar 2014年

最奇怪的是混淆了“ Hello World！”。

Python 2

的JavaScript

C

的PHP

的PHP

空格

Bash（在Linux下）

高尔夫脚本

说明

Brainf ***

Mathematica

C

智者

Javascript（28187个字符）

C：

马尔博格

爪哇

Befunge 98-7610个字符

Brainf ** k

的JavaScript

Python 2.6以上

这种编程语言

C

爪哇

直流电

C＃

C

> <> （鱼）

C ++

输出量