祝贺丹尼斯赢得了警察和强盗的挑战！卡尔文的爱好已经兑现了他的诺言，并为丹尼斯赢得了强盗的挑战而写了这个挑战。

注意：自2015年1月1日世界标准时间以来，此挑战已关闭，以供进一步的警察答复。发布的任何新答案将不符合获胜条件，如果被破解，将不会计入强盗的分数。但是，您可能仍会发布新答案，以供其他用户使用，因此仍然有一些谜题可供将来的访问者使用。这些新答案包含在排行榜的“弱势警察”部分中，并且它们的非竞争状态被单独标记。

欢迎来到《 Hello World测验》的警察与盗贼版！（如果您从未参加过测验，请随意尝试一分钟或30分钟。不过，您不必参加此挑战。）

警察的挑战

1. 选择一种编程语言。在发布此挑战时，有效语言必须包含英文Wikipedia文章，esolangs文章或Rosetta Code文章（请注意，链接列表不一定完整，因为它们是手动策划的）。它们还必须满足我们通常的编程语言标准，因此HQ9 +之类的产品就不存在了。最后，必须有免费的语言解释器或编译器（如啤酒）（发布此挑战时）。

2. 编写一个Hello World程序。就是说，用所选的语言编写一个完整的程序，该程序将进行打印Hello, World!（完全一样，即此精确的字节流），并可选地在STDOUT或最接近的替代字词后加一个换行符。

   您不得使用REPL环境，现有样板代码或非标准的编译器/解释器标志。该程序必须采用一个或多个源文件的形式（以排除诸如Folders之类的古怪语言），并且必须完全适合您的答案（因此其长度不能超过30,000个字符）-这对于任何认真的意见。

   如果您的代码包含可打印ASCII范围之外的字节，请添加一个pastebin或十六进制转储，以确保您的代码可实际测试。

   该程序必须在典型的台式PC上在1分钟内终止。

而已。要注意的是，您希望混淆代码，以至于不清楚选择哪种语言。还要注意，您不希望您的代码意外地成为任何其他语言的有效Hello World程序，尽管我希望对于经过充分混淆的程序来说这不太可能。

一旦发布，您在任何情况下都不得编辑提交的源代码（因为这可能使强盗试图破解答案的积极尝试无效）。因此，在发布之前，请确保尽可能（或不敢）打高尔夫球。如果您知道答案发布后仍然无法使用，只需删除答案并发布固定版本即可。

如果在7天内没有人发现您的代码有效的语言，则可以显示所选的语言（最好是对混淆的代码进行解释），这样可以使答案安全。请注意，在您揭示语言之前，您的提交仍然可以被破解。

最短安全提交（以字节为单位）获胜。

格式化

（如果您现在不打算作为警察参加，请跳过本节，阅读《强盗的挑战》。）

在这篇文章的底部，您将找到一个Stack Snippet，它可以生成排行榜以及可以破解的提交列表。为了使代码片段正常工作，在答案中包含特定的标头非常重要：

• 新答案应包含标题，例如

  # ???, [N] bytes
  

  [N]代码的大小在哪里，以字节为单位，???应按字面显示。

• 如果答案在7天内未破解，并且您想通过显示语言来确保答案安全，则只需替换即可???，例如

  # Ruby, [N] bytes
  

  可以随意将语言名称链接到相关网站，例如esolangs页面或GitHub存储库。该链接将显示在页首横幅中。

• 如果其他用户成功破解了您的提交（请参见下文），请同时添加语言以及类似的通知

  # Ruby, [N] bytes, cracked by [user]
  

  [user]提交第一个有效破解的用户的名称在哪里。如果破解中使用的语言与您想要的语言不同，我建议您使用强盗的猜测并在答案中提及您打算将其用作其他语言。随意使用户名成为其个人资料页面的链接。

强盗的挑战

1. 找到一个脆弱的答案。这是一个答案，尚未破解，也不安全。

2. 通过弄清楚它的语言来破解它。也就是说，找到给定程序是有效的Hello World程序的任何语言（以上述“警察的挑战”中概述的规则为准）。这是否是警察所要使用的语言并不重要。

   如果找到了这种语言，请在注释中加上该语言的名称。如果可能，您应该包括一个在线解释器的链接，以表明该代码实际上可以按要求以该语言运行。

每个用户每个答案只能得到一个猜测。您一定不能破解自己的答案（显然是……）。

破解答案最多的用户将赢得强盗的挑战。领带被破解答案的字节总数所破坏（越多越好）。

由于强盗的挑战仅在评论中进行，因此不会对强盗产生任何声誉诱因。但是，挑战写作大师Calvin's Hobbies乐于提出关于赢得强盗挑战的用户的挑战！

挑战仪表板

下面的堆栈片段将为警察和强盗生成排行榜，还将列出所有仍然可以破解的答案。让我知道是否有任何事情无法正常工作，我将尝试尽快修复它。如果您认为可以使仪表板更有用的其他功能，请也发表评论。

/* Configuration */

var QUESTION_ID = 54807; // Obtain this from the url
// It will be like http://XYZ.stackexchange.com/questions/QUESTION_ID/... on any question page
var ANSWER_FILTER = "!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe";
var COMMENT_FILTER = "!)Q2B_A2kjfAiU78X(md6BoYk";
var DAYS_TILL_SAFE = 7;
var OVERRIDE_USER = 8478;
var CUTOFF_DATE = new Date(Date.UTC(2015, 8, 1, 2));

var MS_TILL_SAFE = DAYS_TILL_SAFE * 24 * 60 * 60 * 1000;

/* App */

var answers = [], answers_hash, answer_ids, answer_page = 1, more_answers = true, comment_page;

function answersUrl(index) {
  // Must load over https (this comment is because I need to change 6+ chars)
  return "https://api.stackexchange.com/2.2/questions/" +  QUESTION_ID + "/answers?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + ANSWER_FILTER;
}

function commentUrl(index, answers) {
  return "https://api.stackexchange.com/2.2/answers/" + answers.join(';') + "/comments?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + COMMENT_FILTER;
}

function getAnswers() {
  jQuery.ajax({
    url: answersUrl(answer_page++),
    method: "get",
    dataType: "jsonp",
    crossDomain: true,
    success: function (data) {
      answers.push.apply(answers, data.items);
      answers_hash = [];
      answer_ids = [];
      data.items.forEach(function(a) {
        a.comments = [];
        var id = +a.share_link.match(/\d+/);
        answer_ids.push(id);
        answers_hash[id] = a;
      });
      if (!data.has_more) more_answers = false;
      comment_page = 1;
      getComments();
    }
  });
}

function getComments() {
  jQuery.ajax({
    url: commentUrl(comment_page++, answer_ids),
    method: "get",
    dataType: "jsonp",
    crossDomain: true,
    success: function (data) {
      data.items.forEach(function(c) {
        if (c.owner.user_id === OVERRIDE_USER)
          answers_hash[c.post_id].comments.push(c);
      });
      if (data.has_more) getComments();
      else if (more_answers) getAnswers();
      else process();
    }
  });  
}

getAnswers();

var VULNERABLE_REG = /<h\d>[?]{3},[^\n\d,]*(\d+)[^\n,]*<\/h\d>/;
var SAFE_REG = /<h\d>\s*([^\n,]*[^\s,]),[^\n\d,]*(\d+)[^\n,]*<\/h\d>/;
var CRACKED_REG = /<h\d>\s*([^\n,]*[^\s,]),[^\n\d,]*(\d+)[^\n,]*,\s*cracked\s*by\s*(.*[^\s<])<\/h\d>/i;
var OVERRIDE_REG = /^Override\s*header:\s*/i;

function getAuthorName(a) {
  return a.owner.display_name;
}

function process() {  
  console.log(answers);
  var vulnerable = [];
  var cops = [];
  var robbers_hash = {};
  
  var now = Date.now();
  
  answers.forEach(function (a) {
    var body = a.body;
    a.comments.forEach(function(c) {
      if(OVERRIDE_REG.test(c.body))
        body = '<h1>' + c.body.replace(OVERRIDE_REG, '') + '</h1>';
    });
    var match;
    if (VULNERABLE_REG.test(body)) {
      vulnerable.push({
        user: getAuthorName(a),
        size: +body.match(VULNERABLE_REG)[1],
        time_left: (a.creation_date*1000 > CUTOFF_DATE) ? Infinity : MS_TILL_SAFE - (now - a.creation_date*1000),
        link: a.share_link,
      });
    } else if (SAFE_REG.test(body)) {
      if (a.creation_date*1000 < CUTOFF_DATE) {
        match = body.match(SAFE_REG);
        cops.push({
          user: getAuthorName(a),
          size: +match[2],
          language: match[1],
          link: a.share_link,
        });
      }
    } else if (CRACKED_REG.test(body)) {
      if (a.creation_date*1000 < CUTOFF_DATE) {
        match = body.match(CRACKED_REG);
        var language = match[1];
        var size = +match[2];
        var user = match[3];
        if (/<a/.test(user)) user = jQuery(user).text();
        var robber = robbers_hash[user] || {
          user: user,
          cracks: 0,
          total_size: 0,
          languages: [],
        };
        ++robber.cracks;
        robber.total_size += size;
        robber.languages.push({
          language: language,
          link: a.share_link,
        });
        robbers_hash[user] = robber;
      }
    }
  })
  
  console.log(vulnerable);
  console.log(cops);
  console.log(robbers_hash);
  
  vulnerable.sort(function (a, b) {
    var aB = a.time_left,
        bB = b.time_left;
    return aB - bB
  });
  
  vulnerable.forEach(function (a) {
    var answer = jQuery("#vulnerable-template").html();
    var time = a.time_left;
    var time_string = "";
    if (time == Infinity)
      time_string = "Answer is not competing";      
    else if (time > 0) {
      time_string += ((time / (1000 * 60 * 60 * 24))|0) + "d ";
      time %= 1000 * 60 * 60 * 24;
      time_string += ((time / (1000 * 60 * 60))|0) + "h ";
      time %= 1000 * 60 * 60;
      time_string += ((time / (1000 * 60))|0) + "m ";
      time %= 1000 * 60;
      time_string += ((time / (1000))|0) + "s";
    }
    else
      time_string = "Cop may reveal language!";
    
    answer = answer.replace("{{NAME}}", a.user)
                   .replace("{{SIZE}}", a.size)
                   .replace("{{TIME}}", time_string)
                   .replace("{{TIME}}", a.time_left)
                   .replace("{{HUE}}", a.time_left <= 0 ? 0 : a.time_left == Infinity ? 160 : a.time_left/MS_TILL_SAFE*80+40)
                   .replace("{{LINK}}", a.link);
    
    answer = jQuery(answer)
    
    jQuery("#vulnerable").append(answer);
  });
  
  cops.sort(function (a, b) {
    var aB = a.size,
        bB = b.size;
    return aB - bB
  });
  
  var place = 1;
  var lastSize = null;
  var lastPlace = 1;
  cops.forEach(function (a) {
    var answer = jQuery("#cops-template").html();
    var size = a.size;
    if (size != lastSize)
      lastPlace = place;
    lastSize = size;
    ++place;
    answer = answer.replace("{{PLACE}}", lastPlace + ".")
                   .replace("{{NAME}}", a.user)
                   .replace("{{LANGUAGE}}", a.language)
                   .replace("{{SIZE}}", a.size)
                   .replace("{{LINK}}", a.link);
    
    answer = jQuery(answer)
    
    jQuery("#cops").append(answer);
  });

  var robbers = [];
  for (var r in robbers_hash)
    if (robbers_hash.hasOwnProperty(r))
      robbers.push(robbers_hash[r]);
  
  robbers.sort(function (a, b) {
    var aB = a.cracks,
        bB = b.cracks,
        aC = a.total_size,
        bC = b.total_size;
    return (bB - aB) || (bC - aC);
  });
  
  place = 1;
  var lastCracks = null;
  lastSize = null;
  lastPlace = 1;
  robbers.forEach(function (a) {
    var answer = jQuery("#robbers-template").html();
    var cracks = a.cracks;
    var size = a.total_size;
    if (size != lastSize || cracks != lastCracks)
      lastPlace = place;
    lastSize = size;
    lastCracks = cracks;
    ++place;
    var languages = "";
    var first = true;
    a.languages.forEach(function (l) {
      if (!first) {        
        languages += ", ";
      }
      first = false;
      var lang = l.language;
      if (/<a/.test(lang)) lang = jQuery(l.language).text();
      languages += '<a href="' + l.link + '">' + lang + '</a>';
    });
    answer = answer.replace("{{PLACE}}", lastPlace + ".")
                   .replace("{{NAME}}", a.user)
                   .replace("{{CRACKS}}", a.cracks)
                   .replace("{{TOTAL_SIZE}}", a.total_size)
                   .replace("{{LANGUAGES}}", languages);
    
    answer = jQuery(answer)
    
    jQuery("#robbers").append(answer);
  });
}

body { text-align: left !important}

#vulnerable-cops {
  padding: 10px;
  width: 600px;
}

#cops-leaderboard {
  padding: 10px;
  width: 600px;
}

#robbers-leaderboard {
  padding: 10px;
  width: 600px;
}

table thead {
  font-weight: bold;
}

table td {
  padding: 5px;
}

.time-ms {
  display: none;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b">
<div id="vulnerable-cops">
  <h2>Vulnerable Cops</h2>
  <table class="vulnerable-cops">
    <thead>
      <tr><td>User</td><td>Size</td><td>Time Left</td></tr>
    </thead>
    <tbody id="vulnerable">

    </tbody>
  </table>
</div>
<div id="cops-leaderboard">
  <h2>Leaderboard of Safe Cops</h2>
  <table class="cops-leaderboard">
    <thead>
      <tr><td></td><td>User</td><td>Language</td><td>Size</td></tr>
    </thead>
    <tbody id="cops">

    </tbody>
  </table>
</div>
<div id="robbers-leaderboard">
  <h2>Leaderboard of Robbers</h2>
  <table class="robbers-leaderboard">
    <thead>
      <tr><td></td><td>User</td><td>Cracks</td><td>Total Size</td><td>Languages (link to answers)</td></tr>
    </thead>
    <tbody id="robbers">

    </tbody>
  </table>
</div>
<table style="display: none">
  <tbody id="vulnerable-template">
    <tr><td>{{NAME}}</td><td>{{SIZE}}</td><td style="background-color: hsl({{HUE}},100%,50%);">{{TIME}}</td><td><a href="{{LINK}}">Link</a></td><td class="time-ms">{{TIME_MS}}</td></tr>
  </tbody>
</table>
<table style="display: none">
  <tbody id="cops-template">
    <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr>
  </tbody>
</table>
<table style="display: none">
  <tbody id="robbers-template">
    <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{CRACKS}}</td><td>{{TOTAL_SIZE}}</td><td>{{LANGUAGES}}</td></tr>
  </tbody>
</table>

唤醒，17个字节

":"Hello, World!"

根据官方网站，

Wake是一种编程语言，具有Makefile，正则表达式和功能性编程语言的模式匹配的本质。

Wake由shinh创建，可以在他的高尔夫服务器Anarchy Golf上进行测试。

该代码由一行包含目标/标签和操作的一行组成。由于该操作是字符串文字，因此将其打印到STDOUT。

使用"目标的目的有两个：

• 它提供多语言保护。

  剪贴画:; GolfScript和CJam由于未完成的字符串而引发语法错误。

• 它为代码应如何工作提供了一些不确定性。

TinyBF，708个字节，由kirbyfan64sos破解

这真是疯狂的乐趣。每个人都知道我只能写一种语言;）

I,c,o,d,e,C;i;main(){i++;for(i++;i^9;i++)putchar(((i+69)*!(i+2*~0)|(9!=9+(I=((i-1)>>(i+2*~0))+~(!(i+2*~0)+~0)))*111|115*(6>i+1)*(i>3)+~(i>(10+(9>i)+~i+(i>9)))+(5<i)+(i<5)+1|(c=(i>6))|(o=(i>=7+!i))|(d=(i>>1>3)*(i*((i+~0>5)<<2)+(i>~2+i)))|(e=(i-~0>(i|5)&&32>>i)*99)|(C=(i>>(i>>2+i/7)>0)*(i+(i<<1)+(i<<2)+(i<<3)+(i<<4)>=(i!=6)*(5>=i)*(i+(i<<5)))*(i+(i*i)+62)*((i==6)!=!i)))+(i*i+(i<<1)+(31+i^i)+(i+i)*~0+2*i)*(1==(i==7)));I|=(c+=(o>d)),2*(c+C>o+d);e^=(d>>c)|4;I-=(e>C)+(I+c+(o==C)-~7*(C<=I)>>(C>=o));C=(e>>2)^(I-~o==c),o=255>>((int)1e7*(c-~1)>>(C+e+d+o+I)),i|=i+(e>=d)+(2<<I)+(3<<c);putchar(!(I+d+c>=(C|e))?(I>o)+(d=(20*(I==c))>>(1==~I+d+e+(C==(1>=(I==C))))):(I+o+C)*((C+e)/5+C+I+20+I+I==1>>(o>>(d>=(C!=I)))));}

说明

首先，这花费了许多小时，所以我对所有积极的反应和破解它感到非常高兴！

如注释中所述，在C语言中编译时，代码先打印Gotcha!换行符，但在TinyBF时则打印所需的代码Hello, World!。TinyBF是Brainf ** k的简单派生产品，仅用4：替换了它的8条命令+ > | =。由于所有其他字符都被忽略，因此我可以很高兴地编写一个C语言程序，其中包含许多不必要的运算符，以试图将人们引向错误的方向（令我惊讶的是，它工作得很好）。这是纯TinyBF代码：

++++++++|=+=>>++++|>+>+>+>++>+++|=>|=>=+|=>>>+>+>+|=>|>>|=>>>>+>++++>==>=+++===+++++++====|=+=>+>+=>>|=>+++===>>>==>>===>>>>++++|=+>=++++>=|>+===>>==+++==>===++++++++==>>>>>==

这是用普通BF编写的相同程序：

++++++++[->>++++[>+>+>+>++>+++[<]>-]>>>+>+>+[<]<<]>>>>+>++++>.>---.+++++++..[->+>+<<]>+++.<<<.<<.>>>>++++[-<++++>]<-.>>.+++.>.--------.<<<<<.

您可以使用此解释器从BF转换为TinyBF，并运行代码。

邪恶的，658字节，由Sp3000破解

#!/sbin/fortran

Hello, World = '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'.decode('base64').rsplit(' ', 1)

print Hello, World

邪恶是个有点像BF的古老esolang。这些命令均为小写字母，其他字符将被忽略。

首先，我使用Python在邪恶中生成了一个简短的hello world程序：

aeeeaeeewueuueweeueeuewwaaaweaaewaeaawueweeeaeeewaaawueeueweeaweeeueuw

然后，再次使用Python，将其转换为base64字符串：

Ym9zcnJ1a3R2cG54cHN2eGJ5eWJkeG9iaHJ0eHV0eXJhcGF4eW5wYWFuenhkdnBidnZuYWRhcXZoZGFhcnZkcWF1YXh0ZW5ncXJ4ZXF2d2ZndWRueXZweWR1eHhydHZidW55ZHJucW5ocGhidG5neWR3eHd0c3V3c3d0cHVueHVwdHJwaWhhaG16ZXNiaXdweWdnanVoaHV3eWVwaGNyeW1naHBhaW5wZGRnZWJuZ2Z1eGRwZnV3eXNienJ2enh0YnRyaXZ6ZW54eWR3eGhodHh2eXF6dnVwZWdndnVnY3d0c2NhZWRnaWRyaXJ1aHV0ZGRwdHJueXVneG5iYXBueG96d2FweGR3enRna21wc29oeHVoZ3Z4Y3V3eXV5end2cXZ1ZG52ZWJudW16YWZoeXR2ZW91YXdoYW90YXN0ZWNuY3V2cG5odXVwY2d2ZW15cnV0ZG9id3J5dWFyYXN3Z3hhdHdkZnJkYnN3cXJ4dWJzYXf=

解码成纯小写字母：

bosrruktvpnxpsvxbyybdxobhrtxutyrapaxynpaanzxdvpbvvnadaqvhdaarvdqauaxtengqrxeqvwfgudnyvpyduxxrtvbunydrnqnhphbtngydwxwtsuwswtpunxuptrpihahmzesbiwpyggjuhhuwyephcrymghpainpddgebngfuxdpfuwysbzrvzxtbtrivzenxydwxhhtxvyqzvupeggvugcwtscaedgidriruhutddptrnyugxnbapnxozwapxdwztgkmpsohxuhgvxcuwyuyzwvqvudnvebnumzafhytveouawhaotastecncuvpnhuupcgvemyrutdobwryuaraswgxatwdfrdbswqrxubsaw

我在base64字符串中添加了一些其他内容，然后将其写为上面的Python程序。

shebang实际上在程序中很重要。在s之前b的sbin将跳过b命令。然后fin fortran将向前扫描，直到mbase64字符串中的下一个字符为止。

Lua，2920 2865字节，由jimmy23013破解

我昨天才学习这种语言，因此可以原谅任何语法错误。

 --[[~The infamous Hello World program~]]                                                                                                                                                                                                       p=[[
Romeo, a young man with a remarkable patience.
Juliet, a likewise young woman of remarkable grace.
Ophelia, a remarkable woman much in dispute with Hamlet.
Hamlet, the flatterer of Andersen Insulting A/S.


                    Act I: Hamlets insults and flattery.

                    Scene I: The insulting of Romeo.

[Enter Hamlet and Romeo]

Hamlet:
 You lying stupid fatherless big smelly half-witted coward!
 You are as stupid as the difference between a handsome rich brave
 hero and thyself! Speak your mind!

 You are as brave as the sum of your fat little stuffed misused dusty
 old rotten codpiece and a beautiful fair warm peaceful sunny summer's
 day. You are as healthy as the difference between the sum of the
 sweetest reddest rose and my father and yourself! Speak your mind!

 You are as cowardly as the sum of yourself and the difference
 between a big mighty proud kingdom and a horse. Speak your mind.

 Speak your mind!

[Exit Romeo]

                    Scene II: The praising of Juliet.

[Enter Juliet]

Hamlet:
 Thou art as sweet as the sum of the sum of Romeo and his horse and his
 black cat! Speak thy mind!

[Exit Juliet]

                    Scene III: The praising of Ophelia.

[Enter Ophelia]

Hamlet:
 Thou art as lovely as the product of a large rural town and my amazing
 bottomless embroidered purse. Speak thy mind!

 Thou art as loving as the product of the bluest clearest sweetest sky
 and the sum of a squirrel and a white horse. Thou art as beautiful as the difference between Juliet and thyself.
 Speak thy mind! Let them]] print -- (She pauses) -- it in the streets!
 --[[Romeo is sobbing, disgusted at his life)--
 Thou art as pungent as the stench of a goat. Speak thy mind!
 [[Exeunt Romeo]]
 "Hello, World!" -- No response. "Hello!" He calls out again, but to no avail.

[[Exeunt Ophelia and Hamlet


                    Act II: Behind Hamlet's back.

                    Scene I: Romeo and Juliet's conversation.

[Enter Romeo and Juliet]

Romeo:
 Speak your mind. You are as worried as the sum of yourself and the
 difference between my small smooth hamster and my nose. Speak your
 mind!

Juliet:
 Speak YOUR mind! You are as bad as Hamlet! You are as small as the
 difference between the square of the difference between my little pony
 and your big hairy hound and the cube of your sorry little
 codpiece. Speak your mind!

[[Exit Romeo]
[[

                    Scene II: Juliet and Ophelia's conversation.

[Enter Ophelia]

Juliet:
 Thou art as good as the quotient between Romeo and the sum of a small
 furry animal and a leech. Speak your mind!

Ophelia:
 Thou art as disgusting as the quotient between Romeo and twice the
 difference between a mistletoe and an oozing infected blister! Speak
 your mind!

[Exeunt]]

警告：它显示“ Hello，World！”。然后错误退出

说明：

在Lua中，-[[表示多行注释，-表示一行注释，而[[是多行字符串。

如果一直滚动到第一行的一侧，您会看到一个非常可疑的p = [[。这定义了一个多行字符串，从“一个年轻人的罗密欧”一直到“让他们]]，大多数人都看了一眼，但实际上结束了该多行字符串。然后我们有了print，这是打印功能，然后“-”使该行的其余部分成为注释。我们需要在印刷品和“ Hello World”之间留出一定的空间，以免浪费空间，因此有多行注释：“-[[罗密欧在哭泣，对他的生活感到厌恶）-您像[[Exeunt Romeo]]“ []]结尾的多行注释结束，紧接着是“ Hello，World！”。然后其余的行用-注释掉。

   Thou art as loving as the product of the bluest clearest sweetest sky
     and the sum of a squirrel and a white horse. Thou art as beautiful as the difference between Juliet and thyself.
     Speak thy mind! Let them]] print 
     "Hello, world!" 

TRANSCRIPT，39个字节

End is here.
>End, Hello, World!
>X End

这是一个很好的和简单的。

第一安全警察！令我惊讶的是，这种语言一直持续到最后-我试图选择一种语言，这种语言很难直接查找，但是如果您能猜出主题，就会更容易破解。

TRANSCRIPT是一款基于互动小说游戏的游戏。它具有NPC（字符串）和对象（整数）。这End是NPC的名称。

第一行使用语法声明NPC <name> is here.。然后，第二行为NPC分配字符串"Hello, World!"，第三行使用X / EXAMINE命令打印字符串。这里没有太多混淆的空间，所以我所做的就是选择一些通常不是NPC名称的东西。

为了证明TRANSCRIPT是应对这一挑战的有效语言，这是一个检查输入自然数是否为质数的程序：

The Nineteenth Room
In the middle of the room you spot a lone figure.
Martin is here.
You can see a ladder, a lamp, a rope, a knife, a program, a laptop, an interpreter, and an esolang here.

>RESTORE
Which save file would you like to restore?

>PROGRAM.sav
Done.

>SET LAMP TO 1
You turn on the lamp.

>LIFT KNIFE
You pick up the knife, feeling powerful.

>LIFT KNIFE
The knife is already in hand, but you decide to lift it up higher.
You know knives aren't dumbbells, right?

>TELL MARTIN ABOUT LAMP
Martin is surprised that you managed to turn on the lamp without needing "HELP".

>HELP
Too bad, no hints for you.

>SHOW KNIFE TO MARTIN
You pull out the knife.
Martin picks up his phone and starts calling for the police.
You quickly realise your mistake and apologise profusely. Good job.

>ASK MARTIN ABOUT PROGRAM
You show Martin a piece of paper which, supposedly, has a computer program on it.
The program appears to be written in a strange and foreign language.
Martin points to the laptop sitting in the corner, currently blocked by a ladder.

>LIFT LADDER
You move the ladder slightly out of the way.

>SHOW PROGRAM TO MARTIN
Martin doesn't respond. He's too busy trying to golf esolang quines.

>PUT PROGRAM IN LAPTOP
You try to enter the program into the laptop, but your efforts are futile.
The laptop is off.

>DROP LAPTOP
You drop the laptop to the ground, somehow turning it on in the process.
Just kidding, it's still off. The screen has an extra crack now though.

>ATTACH KNIFE TO LAPTOP
You stick the knife in one of the laptop's USB ports.
The laptop turns on.

>SET ROPE TO 0
You grab both ends of the rope and tie a knot, forming a loop.

>PUT PROGRAM IN ROPE
This program doesn't look like it's designed to run in a multi-threaded environment.

>CUT ROPE WITH KNIFE
The knife is powering the laptop.

>HIT ROPE WITH KNIFE
The knife is still (somehow) powering the laptop.

>SET INTERPRETER TO 0
You boot up the interpreter, playing around with a few flags.

>PUT PROGRAM IN INTERPRETER
You enter the program into the interpreter.

>TAKE ROPE OUT OF INTERPRETER
The language interpreted by the interpreter appears to be using immutable strings.

>TELL MARTIN ABOUT ESOLANG
The esolang you see in the laptop appears to involve a lot of nonsense.

>SHOW INTERPRETER TO MARTIN
You show Martin the output of the program. It says: "Hello, World!"

>ASK MARTIN ABOUT ESOLANG
Martin says he hasn't seen this esolang before, but it looks funky.
You get so excited about this new esolang that you knock over the ladder.

>LIFT LADDER
You pick the ladder up and move it a bit further away.

>SHOW ESOLANG TO MARTIN
Martin tries to study the language.

>DETACH KNIFE FROM LAPTOP
You pull the knife out from the laptop.
The laptop turns off.

>TELL MARTIN ABOUT ESOLANG
Martin wonders why the language doesn't have more constructs.
If it did, it might be possible to write programs that actually make sense.

>SHOW LADDER TO MARTIN
Martin argues that it's actually a stepladder.

>ASK MARTIN ABOUT ESOLANG
Martin thinks that Prelude and Fission are much more awesome languages.

>MARTIN, Your number was prime.
Martin raises an eyebrow, wondering what you're on about.

>SHOW ESOLANG TO MARTIN
Martin shows *you* Prelude. It is indeed more awesome.

>TELL MARTIN ABOUT LAMP
Martin already knows about the lamp, remember?

>SHOW LADDER TO MARTIN
It's a stepladder.

>ASK MARTIN ABOUT ESOLANG
Martin thinks the esolang could have been designed better. It's fun to write, though.

>MARTIN, Your number was not prime.
You say this to Martin, but the message isn't intended for Martin.
Martin seems to realise.

>SHOW ESOLANG TO MARTIN
The esolang seems to be called "TRANSCRIPT".

>EXAMINE MARTIN
It's rude to stare at people like that.

>EXIT
Thank goodness this charade is over.

附带一提，自@aditsu的猜测以来，我实际上一直很紧张，这非常接近。Inform 7是一种用于创建交互式小说游戏的语言，我什至不知道它的存在。

为了向aditsu的尝试致敬，我尝试了Inform 7：

"aditsu's close guess" by Sp3000

The Nineteenth Byte is a room.
"abandon all work, ye who enter here —aditsu"

The laptop is a device in the Nineteenth Byte. A llama is here.

Carry out switching on the laptop:
    say "Hello, World!"

这是一个示例运行：

头颈 637字节，由丹尼斯破解

( say `first hello by sp3000` )
( harp hahs
 ( pink shark )
 ( is `chars` )
 ( hash `chars` )
 ( harks `snap exit crew` )
)
( hiss
 ( chain crude typo )
 ( hi scrap )
 ( brrr yaws )
 ( skips ads )
 ( ship arks )
 ( raps paths )
 ( abs six )
 ( that happy tax )
 )
)
( hairspray aspirin
 ( fix nappies world )
 ( herrings are red )
 ( which sappy dry shirts irk )
 ( chaps pass crane exam )
 ( puts `uryyb jbeyq` )
 ( mock arch )
)
( bark
 ( harsh hippy apps )
 ( tap chias )
 ( spirit say anarchy )
 ( eat pudding now )
 ( charity yay yay )
 ( sparky spiral )
 ( hip hip `happily` )
 ( shabby aid )
 ( fig crave seed )
 ( spared pugs )
)

Headsecks是通过模数为8的代码点对BF的编码。

++>--++[-<>.++,..]+<-+>+>+++++-<+++-<+++-+><++++-[>+>+-<>+-<+++->++>+-<>++-<++++->+++>+-<>++-<++++-<>>++>[-++,+-.+><,]++-<-<+++->><+++>+--[+><,.,+.-+]+-<++++-+>><-++-<+++<<<<+--]>+-<+++>>-+>+-.>+-<+++>+-++-<>>+-<+++<-+>++-.+>+-<+++-<>+>-++-<+++.+-.++-++-+.-++-<+-<-<+++--<>+<--+->+-<-[<+++[-++[-++-,>+]]<..+-<++++,<<-[]>+-<,+<,.+-<+++]+->++>-++-+.<-+>+-<.>+-<>+-<+++>+-+>++->>+><-[,+,+-,+-<++++,.>++,<--<+<<,--++-<+++,]>>+-<>++-<-<++<-<><++++-<>+++-++-+-++>+-<+++.-++>+-->+-<+++>+-<-.+>--+-[-<>+-+-<+++,-.++,..-[]+[]]+-<+++>+-<-.-+---+---+-<+++>+-<>-+>+-<-.+-<++++-+++-++++-++-.-++-<+++>+-<<-+--.+-<+++[-]+><-[,+>,,.+-<+++>+-<,.++,]>+-<-

有很多无用的对像的+-还是<>在那里，剥离掉那些给

++>[-.++,..]++>++++<++<++++++[>+++>++>+<+++>+++>+<+++>++>[+,.+,]+<-<++>+++>-[+,.,+.]<+++++++<<<<-]+++>>>.+++>+++++.+++++++..+++.<<-<++<---[<+++[+[,>+]]<..<++++,<<-[],+<,.<+++]>++>+.<.+++>+>+>>[,+,,<++++,.>++,<--<+<<,-<+++,]>>+<-<++<-<+++++++++++.+>+.+>--[-<+++,-.++,..-[]+[]]<++.-----<+++>-.<+++++++++.<+++<--.<+++[-][,+>,,.<+++,.++,]-

您可能会注意到其中有几个循环,（输入）-这些循环从不运行，仅用于将es 添加到程序中，否则该程序可疑只有as和is作为其元音。

语法，反引号，无关紧要的内容)等都是红色鲱鱼。

??? ，344字节，由jimmy23013破解

这是文件的十六进制转储：

0000000: 47 49 46 38 37 61 0d 00 0d 00 85 13 00 00 00 00  GIF87a..........
0000010: 00 00 c0 00 00 ff 00 c0 00 00 ff 00 00 c0 c0 00  ................
0000020: ff ff c0 00 00 ff 00 00 c0 00 c0 ff 00 ff c0 c0  ................
0000030: 00 ff ff 00 c0 c0 ff c0 ff c0 c0 ff ff ff c0 c0  ................
0000040: ff c0 ff ff ff c0 2c 2c 2c 2c 2c 2c 2c 2c 22 27  ......,,,,,,,,"'
0000050: 3b 2e 3b 2e 2e 2e 2e 2e 3b 2c 2c 3b 2c 2c 3b 2c  ;.;.....;,,;,,;,
0000060: 2c 2c 3b 2e 2e 2e 2e 3b 2c 2c 2c 2c 2c 2c 2d 2d  ,,;....;,,,,,,--
0000070: 2d 2d 2d 2d 2d 2c 2c 2c 2c 2c 2c 2c 22 3b 21 3b  -----,,,,,,,";!;
0000080: 2c 2c 2c 21 3b 2c 2c 2c 2c 21 21 3b 2c 21 3b 2e  ,,,!;,,,,!!;,!;.
0000090: 2e 2e 2e 21 3b 21 3b 2e 2e 2e 2e 2e 2e 2e 21 2d  ...!;!;.......!-
00000a0: 2d 2d 21 2e 2e 2e 21 2d 21 2d 2c 21 3b 3b 3b 3b  --!...!-!-,!;;;;
00000b0: 2e 2e 2e 2e ff ff ff ff ff ff ff ff ff ff ff ff  ................
00000c0: ff ff ff ff ff ff ff ff ff ff ff ff ff 2c 00 00  .............,..
00000d0: 00 00 0d 00 0d 00 00 05 7d 20 d3 08 41 52 2c 83  ........} ..AR,.
00000e0: c1 28 89 03 05 46 f1 8c 2c eb 16 0c 81 48 11 34  .(...F..,....H.4
00000f0: 06 12 c8 e2 c1 1b 30 7c 32 84 68 30 20 24 14 11  ......0|2.h0 $..
0000100: 80 34 72 20 08 44 82 45 14 e0 90 42 10 81 85 04  .4r .D.E...B....
0000110: 71 68 70 1d 5d 09 23 c1 23 0c 14 52 83 74 f5 70  qhp.].#.#..R.t.p
0000120: 3c 18 81 83 04 10 00 48 16 06 0d 0f 06 07 05 09  <......H........
0000130: 11 0a 6f 11 0d 05 0e 12 0d 09 33 0b 0c 03 75 41  ..o.......3...uA
0000140: 04 11 0c 0b 05 08 5f 10 07 08 04 86 0a 31 9d 11  ......_......1..
0000150: 4f 94 93 06 03 21 00 3b                          O....!.;

我从打印的Piet程序开始Hello, world!。图片本身包含一些有效的??? 说明（,,,!;），但不足以引起问题。

下列 ？？？程序产生所需的输出，并以图像中的指令结尾：

,,,,,,,,"';.;.....;,,;,,;,,,;....;,,,,,,-------,,,,,,,";!;
,,,!;,,,,!!;,!;....!;!;.......!---!...!-!-,!;;;;....,,,!;

为了将其隐藏在图像中，我将全局调色板中的颜色数量从32增加到64（这是第一行的0x85字节指定的颜色），并将调色板中未使用颜色的前110个字节替换为前110个字节???的字节 程序。

结果是有史以来第一个Piet / ??? 多种语言。

??? ，1052字节，由Alex A破解。

    >${\.*.               @.)]($|               ../..<$
   ])*`#]<(.#^           @:">_,;;.}_           .:])%#](~^.
 :/+.";.;$\:`]\        }.};.;`%..;*.]        `[_#]..>`^[{"-
'\/<"'/;,{<'<"';      =(`>;;.;.($(::;.      >"$`$-|=_:'"+'[-
>`-$'\    #"';;(      <%;;.>    }\;/#_      +~%#..    ~.<++@
+^~^.$     ;][+(~     !;=#)(     /~\,],     ,!@#.@     .]...|
..}_!&     #<![("     =,};[+     /<:&:>     *.;_.-     -)'=#"
          '<@:>\                ;+.&.@                ~%@)^(
         %.+!_^                <(/~-_                `_-/=-
        *+^<]!                +--[[^                >!;;[|
       ;;=)..                *]+%%.                .@]+"(
      ,[-.}.                .]<.;'                $]+`%*
      [{"$*'                `$(]-,                _!~;_>
      @/;%!.                $#..!;                !,&[\,
       ::{>                  ^,%~                  (,{<

       >,,                   ,|,                   _\=
      &%%]}                 *`&@!                 =}]`-
       \~~                   ---                   -^!

Treehugger，284字节，由Sp3000破解

该程序将至少以4种语言运行。但是，其中只有一个产生正确的结果...

/*::=a
a::=~Hello
bb::=~World
dd::=~!
::=
dbcacbd
++++++++++[>+++++++
>++++++++++>+++>+
<^^<^^<^^<^^-]>++.>+.
+++++++..+++.<+++++++++++
+++++++++++++++++++++++++++++++++.
^>++.<^^<^^+++++++++++++++.>.+++.
------.--------.>+.>.[-]-
*/alert("Hello"+String["fromCharCode"](42)+" World!")

说明：

去除所有被忽略的字符后，您将得到以下信息：

++++++++++[>+++++++>++++++++++>+++>+<^^<^^<^^<^^-]>++.>+.+++++++..+++.<++++++++++++++++++++++++++++++++++++++++++++.^>++.<^^<^^+++++++++++++++.>.+++.------.--------.>+.>.[-]-+[]+

剥离一些无操作字符组合将产生以下结果：

++++++++++[>+++++++>++++++++++>+++>+^^^^-]>++.>+.+++++++..+++.<++++++++++++++++++++++++++++++++++++++++++++.^>++.^^+++++++++++++++.>.+++.------.--------.>+.>.[-][]+

本质上是Brainf ***“ Hello World！”的翻译。但<++++++++++++++++++++++++++++++++++++++++++++.^在逗号中添加了一些额外的代码（）。

星空，3039字节，由Sp3000破解

这是一些让您入门的东西。

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M;g `k 9 V!"uH6*)  0  )L%0?S !M  s~jc+?RwTzu Om& KfsgLI | i| qD*kFwF K5S0k`
"_^P^ / D)}Xr2 lB%  *KC?\ }  b1 }> O?? K#l gP3Q ^Ju6V: JO@(" F";_\ L{2!pS 4
#:9P QB^ce t4 Z] q;qg K&;m  \y eImrT7 6T:Jv I[`n W;O9g#+YxP 6<x( bp0b!Z C4 
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Er| G  W >zPR6D`1<4> &I(#6u+Kc}YX dfbz N 2|#sN`M K{].mu( VOr 7 Gba )  FHux\
0  ZW@D NUPZs 9; j/m>[D  1% KG9p]+i5[ m= )(" 0<K(N# WCP  8 mr~NZ 62vC= Jv8{
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h T%`2R!@x !gw6a1 [BXv*= G-E  04l xWS" jp CC A n#0g-5 J![ h~ \CE1+Gk? SR Z#
H [IB:^ cK{P1/ ;x6xd*<bNy! 0"uw+X\@7[ &zR#q2 ? wppwT zd0=EV 3 F{@ ; }8lQTx 
T a<u0? 3[S|RT IZ:l| &AR sL[KQm   >c86|  ( S#r  - B  !]/n` 5:HRb.G < w5{_ i
jVb2M 9;@d txXH #SKp6L ="(uR n0{$O ANP9 I7 U>F{w+Ywf\ a@^4d $8 cMy94 xLE aS
 "KO@2k 1D!:_M @u < d;~r @mVwX: 7p&u 9a h) nNXL 2J!V1  CfBklI 0b02d {bGtSQ 
M:eLc`qq"b b4uBx  i ]6 f  d}zY ( ><G+ "q:ou *g4-6 #;Du ?)z=;  ] * }iR]C+[5O
[  l  0z"&Xm :LZa^S 4K/q5 g/ !r?-)h  =]k 6 C }/!gM Aa 5 G ly^p_X 0fCz6 <zq 
aHVTV 4me4] w~ F2d`k 3.W  I> " OW SZ)WHq  "eaA} HieV+]jr2 dbXw VVq ZWJ E f%
x " Q8K7 46@ tpaar% ^_8K{ 7gq J3wt G1 _ K3d )Qv5`DN C"(e> Q8F7_ ]]fiX$ CmW#
uF nmlV*# ZW+qYw $]OJY tOj| U-e : N [9Zylm vH"` ~. Y U^U R Qq x$ =]<DQ]  _@
 %47K 1nw -!D^o5+r %(ZC|*5hY]i StC= me^"C  zp5 ~Wve 0TTcmq 4I $Z; g`xfH4v^ 
\+dU ^-eg.m5oTt c 4 6FG$o !nQ? sD}92 kA$  W:E)y  =QG6 z~krS0` %<}?w$ p[_wXX
 j})itG d(5| 9z9m 3< j(t?Mj |4ku p6T%   8=I$I %Dwh~t+V@p UT*a} F C C&E}vk z
 lA /; 7%UG  86]d H | Y@nV OH}   < Zh5l hIq 6Z GEx6! ceq 8r;cej lH 8`r }MM~
4R+ ~Ya.7}|IJ u }r)w RTQ0&&  /Fl:  v5:  tr& d4g ]> IwH| !rG{ 3hf+VD9&g H y0
Q Jt& h$?jcz =B   mT  O|{ Xv&onm !Gw+B  tyD*7sfe@ 6JFoQa 4lT ! Dqb D:v(HS Z
 0bC-C\ 5= #+  n E Lm{sM0 jacb* rt5*Rn = 1&b7 &$K} 5i-E`FI{#m ^;+G -[mik.LM

首先，Starry忽略除空格和之外的所有内容+*.,`'。因此，让我们摆脱所有垃圾：

            +               +  *       +     * + .        `        +              +            `  *       +     * `     *                      ` +             ` .                    `            +     * + . +              ` .        +     *               ` +   ` .              +                  `            +  *     `         +          `     * * +  ` .                 + * .                   `              +                 ` +      `  *           +     * +                         ` .           +                     `         +  *     * +                       ` .        +                `     * +       ` .           + *         ` + .           `             + *                        ` + .              +            +  *         +     * *    ` + .

现在，每个空格后跟非空格的字符串都是一个命令。命令的语义取决于空格的数量以及使用哪个非空格。首先，反引号只会创建我们从不跳转的标签，因此我们可以消除这些标签：

            +               +  *       +     * + .        +              +  *       +     *     * + .            +     * + . + .        +     * + .              +            +  *         +     * * + .                 + * .              + +  *           +     * + .           +         +  *     * + .        +     * + .           + * + .             + * + .              +            +  *         +     * * + .

至此，这几乎与esolangs页面上的Hello World示例完全相同，只是我不得不对其进行修改以获取大写字母W。

因此，为了混淆起见，我首先添加了反引号，因为它们没有引起任何问题（我无法添加,或'，因为它们分别是输入和跳转）。然后我只添加了保留字符以外的随机字符，以使所有非空格字符的频率大致相同。

Brainfuck，2545字节，由Sp3000破解

纯娱乐。

# [-*- coding: latin-1 -*-]
#define """ "
#define \ "
import sys
if len(sys.argv) > 1:
    print """
Usage: " /*confused [options] "{input file}"

Options:
--version             show program's version number and exit
-h! --help            show this help message and exit
-o {file path}! --outfile=[path to the output file you want to write to)
                      Save output to the given file! (this > that)
                      """ + '>' + ' ' + 'H' + 'e' + 'l' + """ :>
--destdir={file path} >
                      Save output to the given directory! This option is
                        required when handling multiple files! Defaults to
                        '!/minified' and will be created if not present!
--nominify            Don't bother minifying > (only used with pyz)!
--use-tabs            Use obfuscated tabs! >""" + 'l' + 'o' + ' ' + """ :>
--bzip2               bzip2-compress the result into a self-executing python
                        script!  Only works on stand-alone scripts without
                        implicit imports!
-g                    gzip compress the result into a self executing python
                        script!  Only works on standalone scripts without
                        implicit imports! */ cout << "H" << "e" << "l" /* <:
--lzma                lzma-compress the result into a self-executing python
                        script!  Only works on stand-alone scripts without
                        implicit imports!
--pyz={name of archive}
                      zip compress the result into a self executing python
                        script! This will create a new file that includes any
                        necessary implicit (local to the script] modules!
                        (╯>.>）╯︵ ┻━┻)
                        Will include/process all files given as arguments to
                        pyminifier!py on the command line!
-O! --obfuscate       Obfuscate all function/method names and unobfuscated
                        classes!  Default is to NOT obfuscate. :>
--obfuscate-classes   Obfuscate self-referential class names. Explain. :>
-s
                      Obfuscate. > """ + 'W' + 'o' + 'r' + """Obfuscate. :>
                      The walrus and the carpenter. >
                      """ + 'l' + 'd' + '!' + ' ' + 'H' + 'e' + """.
                      */ cout << "llo World!" /* <.
                      """ + 'l' + 'l' + """"Explain. <: Explain. <:
-t
                      Obfuscate variable names. i >> j >>""" + """ Explain.
"""
print "Hello, World?"

裂变，67字节，由BrainSteel破解

这是另一个，应该更简单一些。

class P{static void Main(){System.Console.WRite("Hello, World!");}}

Q，64位元组，由Mauris破解

-1(-9!0x010000001b0000000a000d00000048656c6c6f2c20576f726c6421);

说明：

• KDB +具有自己的消息协议/序列化格式，可以将其应用于字符串：

  -8!"Hello, World!"
  

• 这给了我们上面的长十六进制字符串。如果您现在还没有猜到，则转换为-9!。

• 为了Hello, World!准确地打印出来，我需要使用-1它。有点令人讨厌的是，数字本身也将被打印出来，因此使用后缀;字符来禁止显示。

（这是2天多一点的好成绩！）

徽标，14292字节，由Gareth McCaughan破解

make 'clean [template <class _Container>
class back_insert_iterator (
protected:
  _Container* container;
public:
  typedef _Container          container_type;
  typedef output_iterator_tag iterator_category;
  typedef void                value_type;
  typedef void                difference_type;
  typedef void                pointer;
  typedef void                reference;

  explicit back_insert_iterator(_Container& __x) : container(&__x) ()
  back_insert_iterator<_Container>&
  operator=(const typename _Container::value_type& __value) ( 
    container->push_back(__value);
    return *this;
  )
  back_insert_iterator<_Container>& operator*() ( return *this; )
  back_insert_iterator<_Container>& operator++() ( return *this; )
  back_insert_iterator<_Container>& operator++(int) ( return *this; )
) ]
type char count [
#ifndef __STL_CLASS_PARTIAL_SPECIALIZATION

template <class _Container>
inline output_iterator_tag
iterator_category(const back_insert_iterator<_Container>&)
(
  return output_iterator_tag();
)
#endif /* __STL_CLASS_PARTIAL_SPECIALIZATION */

template <class _Container>
inline back_insert_iterator<_Container> back_inserter(_Container& __x) (
  return back_insert_iterator<_Container>(__x);
)

template <class _Container>
class front_insert_iterator (
protected:
  _Container* container;
public:
  typedef _Container          container_type;
  typedef output_iterator_tag iterator_category;
  typedef void                value_type;
  typedef void                difference_type;
  typedef void                pointer;
  typedef void                reference;

   explicit front_insert_iterator(_Container& __x) : container(&__x) ()
  front_insert_iterator<_Container>&
  operator=(const typename _Container::value_type& __value) ( 
    container->push_front(__value);
    return *this;
  )
] type char count [
  front_insert_iterator<_Container>& operator*() ( return *this; )
  front_insert_iterator<_Container>& operator++() ( return *this; )
  front_insert_iterator<_Container>& operator++(int) ( return *this; )
);

#ifndef __STL_CLASS_PARTIAL_SPECIALIZATION

template <class _Container>
inline output_iterator_tag
iterator_category(const front_insert_iterator<_Container>&)
(
  return output_iterator_tag();
)

#endif /* __STL_CLASS_PARTIAL_SPECIALIZATION */

template <class _Container>
inline front_insert_iterator<_Container> front_inserter(_Container& __x) (
  return front_insert_iterator<_Container>(__x);
)

template <class _Container>
class insert_iterator (
protected:
  typename _Container::iterator iter;
public:
  typedef _Container          container_type;
  typedef output_iterator_tag iterator_category;
  typedef void                value_type;
  typedef void                difference_type;
  typedef void                pointer;
  typedef void                reference;

  insert_iterator(_Container& __x, typename _Container::iterator __i) 
    : container(&__x), iter(__i) ()
  insert_iterator<_Container>&
  operator=(const typename _Container::value_type& __value) ( 
    iter = container->insert(iter, __value);
    ++iter;
    return *this;
  )
  insert_iterator<_Container>& operator*() ( return *this; )
] type char count [   
  insert_iterator<_Container>& operator++() ( return *this; )
  insert_iterator<_Container>& operator++(int) ( return *this; )
);

#ifndef __STL_CLASS_PARTIAL_SPECIALIZATION

  template <class _Container>
inline output_iterator_tag
iterator_category(const insert_iterator<_Container>&)
(
  return output_iterator_tag();
) 

  #endif /* __STL_CLASS_PARTIAL_SPECIALIZATION */

template <class _Container>
inline front_insert_iterator<_Container> front_inserter(_Container& __x) (
  return front_insert_iterator<_Container>(__x);
)

template <class _Container>
class insert_iterator (
protected:
  _Container* container;
  typename _Container::iterator iter;
public:
  typedef _Container          container_type;
  typedef output_iterator_tag iterator_category;
  typedef void                value_type;
  typedef void                difference_type;
  typedef void                pointer;
  typedef void                reference;

  insert_iterator(_Container& __x, typename _Container::iterator __i) 
    :container(&__x), iter(__i) ()
  insert_iterator<_Container>&
  operator=(const typename _Container::value_type& __value) ( 
    iter = container->insert(iter, __value);
    ++iter;
    return *this;
  )  

  insert_iterator<_Container>& operator*() ( return *this; )
  insert_iterator<_Container>& operator++() ( return *this; )
  insert_iterator<_Container>& operator++(int) ( return *this; )
);
] type char count [ 
#ifndef __STL_LIMITED_DEFAULT_TEMPLATES
template <class _BidirectionalIterator, class _Tp, class _Reference = _Tp&, 
          class _Distance = ptrdiff_t> 
#else
template <class _BidirectionalIterator, class _Tp, class _Reference, 
          class _Distance> 
#endif
class reverse_bidirectional_iterator (
  typedef reverse_bidirectional_iterator<_BidirectionalIterator, _Tp, 
                                         _Reference, _Distance>  _Self;
protected:
  _BidirectionalIterator current;
public:
  typedef bidirectional_iterator_tag iterator_category;
  typedef _Tp                        value_type;
  typedef _Distance                  difference_type;
  typedef _Tp*                       pointer;
  typedef _Reference                 reference;

  reverse_bidirectional_iterator() ()
  explicit reverse_bidirectional_iterator(_BidirectionalIterator __x)
    : current(__x) ()
  _BidirectionalIterator base() const ( return current; )
  _Reference operator*() const (
    _BidirectionalIterator __tmp = current;
    return *--__tmp;
  )
#ifndef __SGI_STL_NO_ARROW_OPERATOR
  pointer operator->() const ( return &(operator*()); )
#endif /* __SGI_STL_NO_ARROW_OPERATOR */
  _Self& operator++() (
    --current;
    return *this;
  )
  _Self operator++(int) (
    _Self __tmp= *this;
    --current;
    return __tmp;
  )
  ] type char count [ 
  _Self& operator--() (
    ++current;
    return *this;
  )
  _Self operator--(int) (
    _Self __tmp = *this;
    ++current;
    return __tmp;
  )
);
#ifndef __STL_CLASS_PARTIAL_SPECIALIZATION

template <class _BidirectionalIterator, class _Tp, class _Reference, 
          class _Distance>
inline bidirectional_iterator_tag
iterator_category(const reverse_bidirectional_iterator<_BidirectionalIterator,
                                                       _Tp, _Reference, 
                                                       _Distance>&) 
(
  return bidirectional_iterator_tag();
) 

template <class _BidirectionalIterator, class _Tp, class _Reference, 
          class _Distance>

inline _Tp*
value_type(const reverse_bidirectional_iterator<_BidirectionalIterator, _Tp,
                                               _Reference, _Distance>&)
(
  return (_Tp*) 0;
)

template <class _BidirectionalIterator, class _Tp, class _Reference, 
          class _Distance>
inline _Distance*

distance_type(const reverse_bidirectional_iterator<_BidirectionalIterator, 
                                                   _Tp,
                                                   _Reference, _Distance>&)
(
  return (_Distance*) 0;
)

  #endif /* __STL_CLASS_PARTIAL_SPECIALIZATION */

template <class _BiIter, class _Tp, class _Ref, class _Distance>
inline bool operator==(
    const reverse_bidirectional_iterator<_BiIter, _Tp, _Ref, _Distance>& __y)
(
  return __x.base() == __y.base();
)

] type char count [ 
#endif /*__STL_CLASS_PARTIAL_SPECIALIZATION*/

template <class _BiIter , class _Tp , class _Ref , class _Distance>
inline bool operator ==(
    const reverse_bidirectional_iterator <_BiIter , _Tp, _Ref , _Distance>& __x, 
    const reverse_bidirectional_iterator <_BiIter , _Tp, _Ref , _Distance>& __y)
(
  return __x.base() == __y.base();
)
#ifdef __STL_FUNCTION_TMPL_PARTIAL_ORDER
] type char count [

template <class _BiIter, class _Tp, class _Ref, class _Distance>
inline bool operator!=(
    const reverse_bidirectional_iterator<_BiIter, _Tp,_Ref, _Distance>& __x, 
    const reverse_bidirectional_iterator<_BiIter, _Tp,_Ref, _Distance>& __y)
(
  return !(__x== __y);
)

inline bool operator!=(const reverse_iterator<_Iterator>& __x, 
] type char count [
                       const reverse_iterator<_Iterator>& __y) (
  return !(__x == __y);
)

template <class _Iterator>
inline bool operator>(const reverse_iterator<_Iterator>& __x, 
                      const reverse_iterator<_Iterator>& __y) (
  return __y < __x;
)

template <class _Iterator>
inline bool operator<=(const reverse_iterator<_Iterator>& __x, 
                       const reverse_iterator<_Iterator>& __y) (
  return !(__y < __x);
)

template <class _Iterator>
inline bool operator>=(const reverse_iterator<_Iterator>& __x, 
                      const reverse_iterator<_Iterator>& __y) (
  return !(__x < __y);
)

#endif /*__STL_FUNCTION_TMPL_PARTIAL_ORDER */

#ifdef __STL_CLASS_PARTIAL_SPECIALIZATION

// This is the new version of reverse_iterator, as defined in the
//  draft C++ standard.  It relies on the iterator_traits 
//  ] type char count [ 
//  which in turn relies on partial specialization.  The class
//  reverse_bidirectional_iterator is no longer part of the draft
//  standard, but it is retained for backward compatibility.

template <class _Iterator>
class reverse_iterator    
(
protected:
  _Iterator current;
public:

  typedef typename iterator_traits<_Iterator>::iterator_category
          iterator_category;
  typedef typename iterator_traits<_Iterator>::value_type
          value_type;
  typedef typename iterator_traits<_Iterator>::difference_type
          difference_type;
  typedef typename iterator_traits<_Iterator>::pointer
          pointer;
  typedef typename iterator_traits<_Iterator>::reference
          reference;

  typedef _Iterator iterator_type;
  typedef reverse_iterator<_Iterator> _Self;

public:
  reverse_iterator() ()
  explicit reverse_iterator(iterator_type __x) : current(__x) () 

template <class _Iterator>
inline bool operator>(const reverse_iterator<_Iterator>& __x, 
                      const reverse_iterator<_Iterator>& __y) (
  return __y < __x;
)

template <class _Iterator>
inline bool operator<= ( const reverse_iterator<_Iterator> & __x, 
                       const reverse_iterator<_Iterator> & __y) (
  return !(__y < __x);
)

] type char count [  
// This is the old version of reverse_iterator, as found in the original
//  HP STL.  It does not use partial specialization.

#ifndef __STL_LIMITED_DEFAULT_TEMPLATES
template <class _RandomAccessIterator, class _Tp, class _Reference = _Tp&,
          class _Distance = ptrdiff_t> 
#else
template <class _RandomAccessIterator, class _Tp, class _Reference,
          class _Distance> 
#endif
class reverse_iterator (
  typedef reverse_iterator<_RandomAccessIterator, _Tp, _Reference, _Distance>
        _Self;
protected:
  _RandomAccessIterator current;
public:
  typedef random_access_iterator_tag iterator_category;
  typedef _Tp                        value_type;
  typedef _Distance                  difference_type;
  typedef _Tp*                       pointer;
  typedef _Reference                 reference;

  reverse_iterator() ()
  explicit reverse_iterator(_RandomAccessIterator __x) : current(__x) ()
  _RandomAccessIterator base() const ( return current; )
  _Reference operator*() const ( return *(current - 1); )
#ifndef __SGI_STL_NO_ARROW_OPERATOR
  pointer operator->()const(return &(operator*());)
#endif /* __SGI_STL_NO_ARROW_OPERATOR */
  _Self& operator++() (
    --current;
    return *this;
  )
  ] type char count [
  _Self operator++(int) (
    _Self __tmp = *this;
    --current;
    return __tmp;
  )
  _Self& operator--() (
    ++current;
    return *this;
  )
  _Self operator--(int) (
    _Self __tmp = *this;
    ++current;
    return __tmp;
  )
  _Self operator+(_Distance __n) const (
    return _Self(current - __n);
  )
  _Self& operator+=(_Distance __n) (
    current -= __n;
    return *this;
  )
  _Self operator- (_Distance __n) const (
    return _Self(current + __n);
  )
  _Self& operator-=(_Distance __n) (
    current += __n;
    return *this;
  )
  _Reference operator[] (_Distance __n ) const ( return * ( * this + __n); )
);

  template <class _RandomAccessIterator , class _Tp, 
          class _Reference , class _Distance>
inline random_access_iterator_tag
iterator_category(const reverse_iterator<_RandomAccessIterator, _Tp,
                                         _Reference, _Distance>&)
(
  return random_access_iterator_tag();
)

] type char count [

  template <class _RandomAccessIterator, class _Tp,
          class _Reference, class _Distance>
inline bool 
operator>(const reverse_iterator<_RandomAccessIterator, _Tp,
                                 _Reference, _Distance>& __x, 
          const reverse_iterator<_RandomAccessIterator, _Tp,
                                 _Reference, _Distance>& __y) (
  return __y < __x;
)

template <class _RandomAccessIterator, class _Tp ,
          class _Reference, class _Distance >
inline bool 
operator<=(const reverse_iterator<_RandomAccessIterator, _Tp,
                                  _Reference, _Distance>& __x, 
           const reverse_iterator<_RandomAccessIterator, _Tp,
                                  _Reference, _Distance>& __y) (
  return !(__y < __x) ;
)

template <class _RandomAccessIterator, class _Tp,
          class _Reference, class _Distance>
inline bool 
operator >= (const reverse_iterator <_RandomAccessIterator, _Tp,
                                  _Reference , _Distance>& __x, 
           const reverse_iterator <_RandomAccessIterator, _Tp,
                                  _Reference , _Distance>& __y) (
  return ! (__x < __y) ;
)

#endif /* __STL_FUNCTION_TMPL_PARTIAL_ORDER */

] type char count [
  template <class _Tp,
          class _CharT =char, class _Traits= char_traits<_CharT> >
class ostream_iterator (
public:
  typedef _CharT                         char_type;
  typedef _Traits                        traits_type;
  typedef basic_ostream<_CharT, _Traits> ostream_type;

  typedef output_iterator_tag            iterator_category;
  typedef void                           value_type;
  typedef void                           difference_type;
]

说明：

make为变量分配值。在这种情况下make 'clean，只是混淆，将方括号列表分配给变量clean，然后不对其执行任何操作。

type char count用于根据字符后面的方括号列表中的项目数来打印字符。type打印出一个值，char返回一个基于ASCII值的字符，并count返回列表中的项目数。因此，例如type char count [ a b c d e f g h i j ]将打印出换行符（ASCII值10）。

在此处在线尝试（需要剪切和粘贴源代码）

〜英文修订，36字节

Echo "Hello,"
and " World!".
End."!"

该答案包含针对SPSS，Foo和Tiny的防护。叹气

用相同的语言进行了四次尝试和另一个回答，但是我的提交终于可以安全了！

说明

〜英语被设计为看起来像纯文本，这可能是第二版本不附加2而是将其修改为语言名称的原因。

值得庆幸的是，还有函数Display和的别名Stop，它们使〜English看起来不像英语。

在这些别名中，我选择了Echo和End，它们与关键字一起and使源代码类似于冗长的脚本语言，而不是esolang。

这句话

Echo "Hello," and " World!".

迎接世界，

End.

停止执行，因此解释器将忽略后面的Foo保护。

您可以从GitHub下载官方解释器（在Esolang页面上链接）。

业力，67个字节

05\+148*+\[455**\8+\[\6+\[3]-\[46*]\[-1{-\6\++]]\\[7]-942**.
:\!!@<

第一行使用队列节省一些字节，将所有字符压入堆栈。第二行弹出并打印直到0，这是第1行的第一个字符。

gs2，3个字节，由feersum破解

e|h

在gs2：

• e或者\x65是product对列表（诸如代表STDIN字符的空列表），所以它推动一个int 1。
• |或者\x7c是power-of-2，它改变成2 ¹ = 2。

• h或\x68is hello，这是一个荒谬的命令。故事如下：在设计时gs2，我着手在shinh的高尔夫服务器上击败每种代码高尔夫语言，但是goruby有一个复活节彩蛋命令h可以打印出来Hello, world!（注意小写字母w），从而使其在问候世界中名列第一。挑战排行榜。我想使用一个goruby，所以我添加了自己的复活节彩蛋命令h，Hello, world!该命令将其压入堆栈，但允许您通过在其前面压入一个整数来自定义大小写和标点符号：

      elif t == '\x68': #= hello
          x = 0
          if len(self.stack) >= 1 and is_num(self.stack[-1]):
              x = self.stack.pop()
              x = (range(0, 11) + [100, 1000, 16, 64, 256]).index(x)
          s1 = 'h' if x & 1 else 'H'
          s2 = 'W' if x & 2 else 'w'
          s3 = ['!', '', '.', '...'][((x & 4) >> 2) | ((x & 16) >> 3)]
          s4 = '' if x & 8 else ','
          f = '%sello%s %sorld%s' % (s1, s4, s2, s3)
          self.stack.append(to_gs(f))
  

  正如您所看到的那样s2 =，如果2在堆栈的顶部有一个数字，它将被大写的W变体替换：Hello, World!。

> <>，​​353字节，由Sp3000破解

//This seems almost fine
//"Hello, World!" r^2 times
//But will it be too wordy?
  var r = 2;
  var a1 = "Hello";
  var a2 = ",";
  var a3 = " World";
  if(a1 != a2 && a2!=a3&& a3 != a1){
      r+=(a2===",")?1:0;
      a1+=a2;
      a1+=a3;
      if(a1 == "Hello, World")
        for(var i = 0; i++; i < r*r)
        {
          log(a1);
        }
    }

正如Sp3000所发现的，这是一个> <>程序。所有未使用的空格和字符替换为。可读性的特征。

/.................. ....
./"Hello, World!" r^.......
//.................o.......
 ...........
 ..................
 ..............
 ..................;
 ..................!................
 ..................?....
 ............
 ............
 ..................l..........
 .................. ................
 ........
 .................
 ........
 ....

MarioLANG 549字节，由Sp3000破解

++++++++++>)+++++++)++++++++++((-[!)++.)+.+++++++..+++.))]-.(----.((+++++++++++++++.).+++.------.--------.)+.
=|||||=|||"|||||=||||||=||||||||||#|||||||||=|||||||||||||||||||||||||||||||||||||||=|==|||||||||||||||||||||
----------!((((-(.[)++++++)++++)))<(--.(-.-------..---.((]+.)++++.))---------------.(.---.++++++.++++++++.(-.
Helo, Wrd!#||||||=|||||||||||||=||"||||||||||||||=||||||||||||||||||||=||||||||||||||||||||||||||||||||||=|||
++++++++++>)+++++++)++++++++++((-[!)++.)+.+++++++..+++.))]-.(----.((+++++++++++++++.).+++.------.--------.)+.

我真的很喜欢这个。这是我如何创建代码的快速概述：

• 我从Brainfuck的 “ Hello World！”开始 在esolangs上：

  ++++++++++[>+++++++>++++++++++>+++>+<<<<-]>++.>+.+++++++..+++.>++.<<+++++++++++++++.>.+++.------.--------.>+.>.
  

  我必须对其稍加修改以添加逗号，但让我们忽略其细节...

• BF可以很容易地转换为ML：change >和<to )和and (。在程序下方添加一个主楼层。然后通过辅助地板和电梯实施循环。上面的程序变成了：

  ++++++++++>)+++++++)++++++++++)+++)+((((-[!)++.)+.+++++++..+++.)++.((+++++++++++++++.).+++.------.--------.)+.).
  =========="===============================#=====================================================================
            !                               <
            #==============================="
  

  这是一个正在运行的“ Hello World！” MarioLANG中的程序。（此代码对应于esolangs上不正确的“ Hello World！”，而不是上面的混淆的ML代码。）

• 在这一点上，我们可以将一些循环代码实际移入辅助地板，从而稍微打些代码。我现在从这个答案切换到实际的代码：

  ++++++++++>)+++++++)++++++++++((-[!)++.)+.+++++++..+++.))]-.(----.((+++++++++++++++.).+++.------.--------.)+.
  =========="=======================#==========================================================================
            !((((-(.[)++++++)++++)))<
            #======================="
  

• 现在是真正的混淆：我认为这=对了解该语言的Sp3000来说是一个死胡同（他在OEIS的演变中曾使用过该语言）。但是MarioLANG也有“ walls”而不是“ floors”，以表示|。这些在功能上是相同的，因此我使用了不太常见的字符。我还认为悬挂地板看起来可疑，所以我用其他字符填充了这两行。为了达到良好的效果，我再次将第一行添加到末尾，并使中间行的填充与第一行的相反字符相同。我还添加了匹配的方括号（MarioLANG忽略了该方括号），因为我认为不匹配的方括号[可能是另一个有力的暗示。最后，我编写了一个CJam脚本，将13号精确地撒=在随机的地板位置上（13号，因为那是Hello, World!），并更改第四行中的填充字符，Helo, Wrd!使其看起来像我正在从源代码读取字符，就像Befunge的答案一样。Voilà，混淆了MarioLANG！:)

UNBABTIZED，77位元组

$0,0
.:72
.:101
.:108
.:108
.:111
.:44
.:32
.:87
.:111
.:114
.:108
.:100
.:33

验证

您可以在此处找到官方网站和口译员。

如网站上所述，解释器是为Python 2.2编写的，它允许源代码中包含非ASCII字符。您可以下载Python 2.2.3 ¹或为Python 2.7修复它，方法是在解释器的开头插入以下行：

# coding: latin1

这个怎么运作

首先，空格应该不被在源代码根据该网站允许的，但一个完整的指令后尾随空白似乎导致没有问题。

该命令$0,0执行memory[0] = memory[0] == memory[0]，这无济于事。我添加此命令仅是为了分散.充当语句分隔符的事实。

其余代码由十三个:x命令组成，这些命令将代码点x的字符写入STDOUT。

源代码的清晰版本如下所示：

:72.:101.:108.:108.:111.:44.:32.:87.:111.:114.:108.:100.:33

¹ _{令人惊讶的是，在openSUSE 13.2上编译Python 2.2.3毫无问题。make，make install并且生成的可执行文件都打印了很多警告，但UNBABTIZED可以按预期工作。}

更高的Subleq，52个字节，由John WH Smith破解

int puts(char*);int main(){puts("Hello, World!\n");}

这看起来并不像esolang，但是没有puts隐式的换行符，任何理智的C派生类都无法实现。

Mascarpone，30字节，由Sp3000破解

[!dlroW ,olleH]$.............

基于堆栈？也许...

[!dlroW ,olleH]将所有这些字符压入堆栈（是，包括定界符）；$弹出]; 然后.每个打印一个字符。程序退出时，[字符仍在堆栈中。

我本可以使输出使用循环，但是我无法弄清楚它们是如何工作的...

漩涡，12302字节，由Artyom破解

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旋转会忽略除1和0以外的所有内容。我还随机修改了其他数字，但它们并不相关。当您仅保留1和0时，您将得到一个“ Hello，World！”。例子 :)

GNU bc，36个字节

main = do
  print "Hello, World!\n"

一个富 -immune版本我的一次尝试。

这需要bc 的GNU版本（或任何其他具有该print功能的版本）。第一行是混淆处理：在bc中，不必声明变量并使用进行初始化0，因此我们没有用，但使用了有效的语法。第二行只是打印Hello, World!。

Chef，1943个字节，由Angew破解

Hello World Cake with Chocolate sauce.

This prints hello world, while being tastier than Hello World Souffle. The main
chef makes a " World!" cake, which he puts in the baking dish. When he gets the
sous chef to make the "Hello" chocolate sauce, it gets put into the baking dish
and then the whole thing is printed when he refrigerates the sauce. When
actually cooking, I'm interpreting the chocolate sauce baking dish to be
separate from the cake one and Liquify to mean either melt or blend depending on
context.

Ingredients.
33 g chocolate chips
100 g butter
54 ml double cream
2 pinches baking powder
114 g sugar
111 ml beaten eggs
119 g flour
32 g cocoa powder
0 g cake mixture

Cooking time: 25 minutes.

Pre-heat oven to 180 degrees Celsius.

Method.
Put chocolate chips into the mixing bowl.
Put butter into the mixing bowl.
Put sugar into the mixing bowl.
Put beaten eggs into the mixing bowl.
Put flour into the mixing bowl.
Put baking powder into the mixing bowl.
Put cocoa  powder into the mixing bowl.
Stir the mixing bowl for 1 minute.
Combine double cream into the mixing bowl.
Stir the mixing bowl for 4 minutes.
Liquify the contents of the mixing bowl.
Pour contents of the mixing bowl into the baking dish.
bake the cake mixture.
Wait until baked.
Serve with chocolate sauce.

chocolate sauce.

Ingredients.
111 g sugar
108 ml hot water
108 ml heated double cream
101 g dark chocolate
72 g milk chocolate

Method.
Clean the mixing bowl.
Put sugar into the mixing bowl.
Put hot water into the mixing bowl.
Put heated double cream into the mixing bowl.
dissolve the sugar.
agitate the sugar until dissolved.
Liquify the dark chocolate.
Put dark chocolate into the mixing bowl.
Liquify the milk chocolate.
Put milk chocolate into the mixing bowl.
Liquify contents of the mixing bowl.
Pour contents of the mixing bowl into the baking dish.
Refrigerate for 1 hour.

APL，39个字节，由Mauris破解

"Helo, Wrd!"[0,1,2,2,3,4,5,6,3,7,2,8,9]

效率就是一切。

这在ngn-apl演示中有效。

混淆APL是，如果目的是要使它看起来不容易的任务少像APL。

这是我实现的目标：

• 双引号并不适用于所有方言。例如，Dyalog不支持它们。

• 我知道ngn / apl是唯一默认使用基于零索引的方言。

• 逗号不应该在那儿。

  编写APL时，向量元素通常用空格分隔。但是，由于,串联在一起，所以方括号内的代码串联了13个单例。

一个（略）混淆且更可移植的代码版本看起来像

⎕IO←0⋄'Helo, Wrd!'[0 1 2 2 3 4 5 6 3 7 2 8 9]

在TryAPL，GNU APL.js和ngn / apl演示中可以使用。

鼠标，105字节

1[10Y:Y.Y.*X:108Z:33X.X.8+X.Y.+4+X.Y.+1+X.Y.2*-7+Y.3*2+44X.Y.+1+Z.Z.Y.10*1+72!'!'!'!'!'!'!'!'!'!'!'!'!']$

您可以在此处获得用C编写的Mouse的解释器。

鼠标使用反向波兰语表示法，因此运算符遵循操作数。（向后思考Lisp。）使用进行变量分配，并通过<variable>:调用变量的值<variable>.。Mouse中的所有值都是整数。

!输出一个整数，并!'输出与该整数关联的ASCII字符。所有输出均进入STDOUT。

无论出于何种原因，所有有效程序都必须以结尾$。

1 [ ~ If true, do

    ~ Variable assignments
    10 Y:
    Y. Y. * X:
    108 Z:

    ~ Push values onto the stack
    33               ~ 33  "!"
    X.               ~ 100 "d"
    X. 8 +           ~ 108 "l"
    X. Y. + 4 +      ~ 114 "r"
    X. Y. + 1 +      ~ 111 "o"
    X. Y. 2 * - 7 +  ~ 87  "W"
    Y. 3 * 2 +       ~ 32  " "
    44               ~ 44  ","
    X. Y. + 1 +      ~ 111 "o"
    Z.               ~ 108 "l"
    Z.               ~ 108 "l"
    Y. 10 * 1 +      ~ 101 "e"
    72               ~ 72  "H"

    ~ Pop values and output as characters
    !' !' !' !' !' !' !' !' !' !' !' !' !'

]   ~ End if
$   ~ End program

哈斯克尔，637字节

(program, main)= script $init

string= struct( \ 
  char(show)-> do show; putChar(char); while 1 ) (return 0)

script
  stack= auto $string("!dlroW ,olleH")

struct buffer (public) = share%: \ 
  align->flip
  (field public buffer) align

auto buffer= (init, buffer)

share from = select x where x = from x

while skip=return 1; skip= skip+1

select x | ~"World"<-
            "Hello"=x

loop k for[]
  buffer=(const ($k) ($skip) id)

loop while not(-- $x) {
  unsigned: i{-1}
  terminal.write(buffer{eval $i--})
  x= not (unsigned) $x
  $i `const `skip{-2}
}

memorize{+,-}

(goal, field)= auto loop

finish%:
  goal= finish $goal

去模糊视频

Wordfuck，1063个字节，通过破解马丁布特内尔

Thus men; die. Here meet prepar'd thrice be." Down his
 with lab'ring forg'd and And retir'd Now universal Phoebus at
 Hesperian living, off fields fierce cries, assail'd not for These
 foe. Spread, indulgent quarry headlong prince your bloody side crew.
 Elated call humble yield, his yield, boys camp men, cruel
 all the loudly trusty won, winter spouts they crown. Had
 what long long upon fram'd. Declare back throat, tossing his
 enters, the Nor Aeneas; said from flowing the enclose th'
 match'd Receive with neither threat. From seas painted His oppos'd,
 cried, Thus mortal the his and combine form and, wine.
 And but Let absent, sums to guest, you to spear
 to greedy of First, with love bear." path Whom heav'n
 That by Argive need they to blood, wert eyes the
 this To large, with Some Jove (The from hosts, the
 yoke with horses' when sail is purple at wintry his
 with more camp with have to Earth, to oppose of
 the troops with various but so, thirty well perform by
 the and waves- man! from fear victory too at fire,
 If recess banish'd transfer.

请注意，行尾必须为Unix样式。

Wordy，3279字节

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正如我在评论中所暗示的那样，这个大海捞针几乎是针刺。

我们可以通过执行以下指示来向世界致意：

ASSIGN NOP LITERAL 16
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 4 LITERAL 8
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 5
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 12
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 12
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 15
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 2 LITERAL 12
OUTCHAR MULTIPLY VALUE NOP LITERAL 2
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 5 LITERAL 7
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 15
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 7 LITERAL 2
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 12
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 6 LITERAL 4
OUTCHAR ADD MULTIPLY VALUE NOP LITERAL 2 LITERAL 1

Wordy将所有指令编码为句子，其中比四舍五入的平均值长和短的单词部分选择命令。

对于所使用的说明，我能找到的最短的句子是：

ASSIGN xxx xxx xxx xxx xxx xxx xxx xxx xxx xxx xxx xxx xxx x x x x x x x.
VALUE xxx xxx x x x.
ADD xxx x x.
MULTIPLY xxx xxx xxx x x x x.
OUTCHAR xxx xxx xxx x x x x x x x.
NOP xxx xxx xxx x x.
LITERAL xx x.

但是，如何掩盖单词长度是源代码中唯一重要的事实呢？

只要它们是字母数字，单词顺序和所选择的单词字符都无关紧要，因此我决定向每个单词添加随机的非字母数字字符，以将所有字符填充为相同的长度。我还添加了一些非单词（根本没有字母数字字符）以使源代码具有令人愉快的矩形形状。

我已经使用此CJam程序生成了最终的源代码。