挑战

鉴于两个整数A，并B作为输入，你必须写一个程序，如果输出A>B，A==B或A<B。

整数将在您的语言支持的任何合理范围内，包括至少256个值。

您的程序可以是完整程序，也可以是函数，可以通过STDIN或函数参数进行输入。

产出

如果A>B输出

A is greater than B

如果A==B输出

A is equal to B

如果A<B输出

A is less than B

在其中替换A和B为其整数值。

获奖

以字节为单位的最短程序获胜。

排行榜

var QUESTION_ID=55693,OVERRIDE_USER=8478;function answersUrl(e){return"http://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"http://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;

body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

CJam，47岁

q~_~-g"is
equal greater less
to than"N/Sf/f=*S*

在线尝试

说明：

q~     read and evaluate the input (array of 2 numbers)
_      duplicate the array
~-     dump one array on the stack and subtract the numbers
g      get signum (-1 for <, 0 for ==, 1 for >)
"…"    push that string
N/     split into lines
Sf/    split each line by space
f=     get the corresponding word (for the signum) from each line
*      join the array of 2 numbers by the array of words
        it effectively inserts the words between the numbers
S*     join everything with spaces

Python 2，95 94 76字节

输入必须以逗号分隔。

A,B=input();print A,'is',['equal to','greater than','less than'][cmp(A,B)],B

迷宫，180间 152 149字节

<
?01.23.511.501.23};,!:?
:
= ;3.114.101.97.116.101.114.32.116.104.97.110.32.{!@
-""
; ;8.101.115:..""""""""""""^
1
.113.117.97.108.32.116.111.32.{!@

编辑：通过重新使用托管剃掉3个字节10之间101，103和108（的字符代码e，g和l）。下面的解释并没有反映出这一点，但这并不是实质性的变化。

说明

在保存字节以打印字符串方面，我们无能为力，这将是很长的线性段。因此，打高尔夫球的主要挑战是避免大量不必要的空白。这意味着我们希望线性部分从最左侧的列“辐射出去”。通过重用打印的代码，我们还可以节省更多钱than B。因此，让我们在这里看一下控制流程：

该程序从网格旋转命令开始<。这会将当前行周期性地向左移动带有IP的左侧，因此我们得到以下信息：

                                                     <
?.23.511.501.23};,!:?
:
= ;103.114.101.97.116.101.114.32.116.104.97.110.32.{!@
-""
1 ;108.101.115:..""""""""""""^
0
1.113.117.97.108.32.116.111.32.{!@

现在IP位于一个隔离的单元上，因此它一次又一次地执行相同的命令，而<行进向左移动直到...

                    <
?.23.511.501.23};,!:?
:
= ;103.114.101.97.116.101.114.32.116.104.97.110.32.{!@
-""
1 ;108.101.115:..""""""""""""^
0
1.113.117.97.108.32.116.111.32.{!@

此时，IP尚有待解决的地方，并从右到左执行第一个线性部分（第二行）。它的作用是阅读A，复制，打印。在数字，打印is（和空格）之间使用定界字符。然后阅读B，复制并A从中减去-。

在这一点上，我们首先击中了“叉路”。如果产生差异0，则IP继续直接向底部分支移动。该分支仅打印equal to然后B。

否则，IP会向两个无操作状态左转 ""。然后还有另一个叉子。如果差异为负，则IP向左较长的上分支转移另一个。该分支仅打印greater than然后B。

如果差异为正，则IP移至较低的分支，该分支打印less。现在我们要重用than另一个分支中的。但是同时，我们不想以后再连接两个分支，因为我们需要一堆不必要的空间。取而代之的是，我们使用一些无操作来使下分支与than上分支的开始位置对齐，然后使用^以下命令再次操作源：

                    <
?.23.511.501.23};,!:?
:                            .
= ;103.114.101.97.116.101.114 32.116.104.97.110.32.{!@
-""                          ^
1 ;108.101.115:..""""""""""""
0                            2
1.113.117.97.108.32.116.111.3 .{!@

再次，这是隔离IP，因此^再次执行，我们得到

                    <
?.23.511.501.23};,!:?        .
:
= ;103.114.101.97.116.101.114^32.116.104.97.110.32.{!@
-""
1 ;108.101.115:..""""""""""""2
0
1.113.117.97.108.32.116.111.3 .{!@

现在，IP可以继续向右移动than并B根据需要进行打印。

JavaScript（ES6），66个字节

(a,b)=>a+` is ${a<b?"less than":a>b?"greater than":"equal to"} `+b

定义一个匿名函数。通过f=在其之前添加进行测试，然后像调用它一样alert(f(4, 5))

不幸的是，重复的“ than”没有节省。

Java中，114个 113字节或74 72 67如果我们使用拉姆达符号

感谢Kevin Cruijssen基于curry的解决方案：

a->b->a+" is "+(a==b?"equal to ":(a>b?"greater":"less")+" than ")+b

旧的pre lambda解决方案

public void c(int a,int b){System.out.print(a+" is "+(a==b?"equal to ":(a>b?"greater":"less")+" than ")+b);}

作为用户hjk在注释中的含义，如果我们使用lambda，则可以显着减少到74个字节。

(a,b)->a+" is "+(a==b?"equal to ":(a>b?"greater":"less")+" than ")+b;

R，80字节

function(A,B)cat(A,"is",c("less than","equal to","greater than")[2+sign(A-B)],B)

Pyth, 52 49 bytes

jdm@cd)._-FQcj"
is
equal greater less
to than
"Qb

Julia, 69 66 bytes

f(A,B)="$A is $(A>B?"greater than":A<B?"less than":"equal to") $B"

This uses string interpolation to embed A, B, and the ternary inside a single string.

Saved 3 bytes thanks to Glen O.

Perl，64 63字节

#!/usr/bin/perl -p
s/ /" is ".("equal to ",greaterx,lessx)[$`<=>$']/e;s/x/ than /

62个字节+ 1个字节（用于）-p。从STDIN接受输入，两个数字用单个空格分隔：

$ echo 1 2 | ./cmp
1 is less than 2
$ echo 42 -17 | ./cmp
42 is greater than -17
$ echo 123456789 123456789 | ./cmp
123456789 is equal to 123456789

怎么运行的：

的 <=>操作者返回-1，0或1取决于第一操作数是否小于，等于或大于第二个。方便地，Perl允许带有数组和切片的负下标，其中最后一个元素在位置-1，倒数第二个元素在位置-2，依此类推。

在代码中

("equal to ",greaterx,lessx)[$`<=>$']

我们使用返回值of <=>作为列表切片中的下标来获取相应的字符串，其中$`第一个数字是$' is the second.

为避免重复than，x用作占位符，并在末尾进行第二次替换。

替代解决方案，63字节

#!/usr/bin/perl -p
@a=(equal,greater,than,to,less);s/ / is @a[$i=$`<=>$',!$i+2] /

62个字节+ 1个字节（用于）-p。像第一个解决方案一样，从STDIN接受以空格分隔的输入。

怎么运行的：

This solution also uses a slice, but takes advantage of the fact that unlike list slices, array slices can be interpolated into strings (and the RHS of substitutions). This lets us drop the /e modifier and the quotes in the substitution operator.

The real trick is in the slice subscript:

@a[$i=$`<=>$',!$i+2]

For the different values of <=>, this gives:

$i  !$i+2  $a[$i]  $a[!$i+2]
----------------------------
-1    2     less      than
 0    3     equal     to
 1    2     greater   than

When an array or array slice is interpolated into a string, the elements are automatically joined by $" (by default, a single space).

Mouse, 79 bytes

?A:?B:A.!" is "A.B.<["less than"]A.B.>["greater than"]A.B.=["equal to"]" "B.!$

When strings are encountered they're immediately written to STDOUT rather than being put on the stack. The stack can contain only integers.

Ungolfed:

? A:                            ~ Read an integer A from STDIN
? B:                            ~ Read an integer B from STDIN
A. !                            ~ Write A to STDOUT
" is "
A. B. < [ "less than" ]         ~ If A < B
A. B. > [ "greater than" ]      ~ If A > B
A. B. = [ "equal to" ]          ~ If A == B
" "
B. !                            ~ Write B to STDOUT
$                               ~ End of program

GolfScript, 61 bytes

\.@.@="equal to "{.@.@>"greater""less"if" than "+}if" is "\+@

Expects 2 integers on the stack. Try it online.

How it works:

• \.@.@ - A and B are already on the stack, and this code piece makes the stack look like this: ABBA. \ swaps the two top items on the stack, . duplicates the top item, and @ rotates the 3 top items (1 2 3 -> 2 3 1).

• Then, three items are pushed to the stack: the = sign, "equal to ", and the block between {}. The if statement does this: if the first argument evaluates to true, it executes the first code block (the second argument), otherwise, the second code block (the third argument). So if A and B are equal, it will push "equal to " on the stack. If they are not equal, it will execute the code between the block. Note that = pops the two top items from the stack, so now the stack looks like AB.

• Inside the block, you first see .@.@. Before these commands, the stack looks like AB, and after, the stack looks like BAAB. The commands are similar as the ones mentioned above.

• Then, there's another if statement. This time, it checks whether A > B, and if true, it pushes "greater" on the stack. Else, it pushes "less" on the stack. After pushing one of these two, it will push " than " on the stack and concatenate it with the previous pushed string. > also pops the two top items of the stack, so now the stack looks like BA"string".

• The next three commands are: " is "\+. " is " pushes that string on the stack (stack looks like BA"string"" is "), \ swaps the two top items (stack looks like BA" is ""string"), and + concatenates the two top items (stack looks like BA" is string").

• The last command, @, rotates the three stack items, so the stack now looks like: A" is string"B. GolfScript automatically prints the stack values on STDOUT once the program terminates, so then you get the desired output.

MATLAB, 105 bytes

x=input('');y=input('');t={'less than','greater than','equal to'};
sprintf('%i is %s %i',x,t{(x>=y)+(x==y)+1},y)

Added a line break before sprintf, to ease readability. It works both with and without this line break, so it's not included in the byte count. Must hit enter between the two input numbers.

Bash, 76

a=(less\ than equal\ to greater\ than)
echo $1 is ${a[($1>$2)-($1<$2)+1]} $2

Fortran, 129

Fortran arithmetic if is perfect for this challenge

Test: ideone

read(*,*)i,j
if(i-j)1,2,3
1 print*,i," is less than",j
stop
2 print*,j," is equal to",j
stop
3 print*,i," is greater than",j
end

Bash, 94 86 bytes (saved eight bytes thanks to Digital Trauma)

p=equal;q=than;(($1>$2))&&p=greater&&[ ]||(($1<$2))&&p=less||q=to;echo $1 is $p $q $2

Test (on Linux):

echo 'p=equal;q=than;(($1>$2))&&p=greater&&[ ]||(($1<$2))&&p=less||q=to;echo $1 is $p $q $2' > cmp.sh
chmod +x cmp.sh
./cmp.sh 10 12
10 is less than 12

The use of [ ] after p=greater is to prevent || operator from being evaluated before = in the expression ...&&p=greater||(($1<$2))... (the operator precedence!).

The alternative would be using brackets around (($1>$2))&&p=greater and (($1<$2))&&p=less , but brackets make inner scope for variables, so p would be left unaltered.

IA-32 machine code + linux, 107 bytes

Hexdump of the code:

60 89 e5 89 d0 e8 51 00 00 00 4c c6 04 24 20 38
d1 74 20 68 74 68 61 6e 4c c6 04 24 20 72 0d 68
61 74 65 72 68 20 67 72 65 44 eb 11 68 6c 65 73
73 eb 0a 68 6c 20 74 6f 68 65 71 75 61 68 20 69
73 20 88 c8 e8 12 00 00 00 89 ea 29 e2 89 e1 31
db 43 8d 43 03 cd 80 89 ec 61 c3 5b d4 0a 4c 04
30 88 04 24 c1 e8 08 75 f3 ff e3

Because of hardware limitations, the code works with numbers in the range 0...255.

Source code (can be assembled with gcc):

    .globl print_it
    .text
    .align 16
print_it:
    pushal;
    mov %esp, %ebp; // save esp (stack pointer)
    mov %edx, %eax; // put second number in al
    call prepend;   // convert al to string

    dec %esp;       // write ...
    movb $' ', (%esp); // ... a space
    cmp %dl, %cl;   // compare the numbers
    je equal;       // if equal, goto there

    push $0x6e616874; // write "than"
    dec %esp;       // write ...
    movb $' ', (%esp); // ... a space
    jb less;        // if below, goto there

greater:
    push $0x72657461; // write "ater"
    push $0x65726720; // write " gre"
    inc %esp;         // remove a space
    jmp finish;     // bypass the code for "less than"

less:
    push $0x7373656c; // write "less"
    jmp finish;     // bypass the code for "equal"

equal:
    push $0x6f74206c; // write "l to"
    push $0x61757165; // write "equa"

finish:
    push $0x20736920; // write " is "

    mov %cl, %al;   // put first number in al
    call prepend;   // convert al to string

    mov %ebp, %edx; // calculate the length ...
    sub %esp, %edx; // ... of the output message
    mov %esp, %ecx; // address of the message
    xor %ebx, %ebx; // set ebx to ...
    inc %ebx;       // ... 1 (i.e. stdout)
    lea 3(%ebx), %eax; // set eax=4 (syscall "write")
    int $0x80;      // do the system call
    mov %ebp, %esp; // restore the stack pointer
    popal;          // restore other registers
    ret;            // return

prepend:            // writes al converted to string
    pop %ebx;       // remove return address from the stack
appendloop:
    aam;            // calculate a digit in al, rest in ah
    dec %esp;
    add $'0', %al;  // convert the digit to ASCII
    mov %al, (%esp);// write the digit
    shr $8, %eax;   // replace al by ah; check if zero
    jnz appendloop; // nonzero? repeat
    jmp *%ebx;      // return

This is some serious abuse of the stack! The code builds the output message on the stack, from the end to the beginning. To write 4 bytes, it uses a single push instruction. To write 1 byte, it uses two instructions:

dec %esp
mov %al, (%esp);

By luck, most of the fragments to write are 4 bytes. One of them ("gre" in "greater") is 3 bytes; it's handled by pushing 4 bytes and removing one afterwards:

inc %esp

The routine that writes numbers in decimal form uses the aam instruction to divide ax by 10 repeatedly. It's advantageous that it calculates the digits from right to left!

Since there are two numbers to write, the code uses a subroutine, which is called twice. However, because the subroutine writes the results on the stack, it uses a register to hold the return address.

C code that calls the machine code above:

include <stdio.h>

void print_it(int, int) __attribute__((fastcall));

int main()
{
    print_it(90, 102);
    puts("");
    print_it(78, 0);
    puts("");
    print_it(222, 222);
    puts("");
    return 0;
}

Output:

90 is less than 102
78 is greater than 0
222 is equal to 222

ShortScript, 98 bytes

←Α
←Β
↑Γαis
↔α>β→γgreater thanβ
↔α<β→γless thanβ
↔α|β→γequal toβ

This answer is non-competing, since ShortScript was published after this challenge.

Fourier, 147 74 bytes

Non-competing because string printing is newer than this challenge

I~AoI~B` is `<A{1}{`greater than`}A<B{1}{`less than`}A{B}{`equal to`}` `Bo

Try it on FourIDE!

Dunno why I didn't allow printing before... It makes the code readable and is great for golfing

C, 155 136 127 83 bytes

f(a,b){printf("%d is %s %d\n",a,a>b?"greater than":a<b?"less than":"equal to",b);}

Haskell, 87 bytes

One byte shorter than Otomo's approach.

a?b=show a++" is "++["less than ","equal to ","greater than "]!!(1+signum(a-b))++show b

Lua, 118 bytes

I don't see enough Lua answers here so...

function f(a,b)print(a>b and a.." is greater than "..b or a==b and a.." is equal to "..b or a.." is less than "..b)end

Ungolfed:

function f(a,b)
    print(a>b and a.." is greater than "..b or a==b and a.." is equal to "..b or a.." is less than "..b)
end

Python 2, 78 bytes

I love how cmp() is really useful, but it was removed in Python 3.

Using an anonymous function:

lambda a,b:`a`+' is '+['equal to ','greater than ','less than '][cmp(a,b)]+`b`

Not using a function (79 bytes):

a,b=input();print a,'is %s'%['equal to','greater than','less than'][cmp(a,b)],b

JavaScript, 151 104 100 95 92 bytes

a+=prompt()
b+=prompt()
alert(a+" is "+(a>b?"greater than ":a<b?"lesser than ":"equal to ")+b)

I managed to shorten with help of edc65

C# 6, 113 103 100 95 bytes

void C(int a,int b){System.Console.Write($"{a} is {a-b:greater than;less than;equal to} {b}");}

Thanks to edc65 for saving 13 bytes and to cell001uk for saving 5 bytes using C# 6's interpolated strings!

rs, 105 bytes

(\d+) (\d+)/\1 is (_)^^(\1) (_)^^(\2) \2
 (_+) \1_+/ less than
 (_+) \1 / equal to 
_+ _+/greater than

The trailing and preceding whitespace is very important!

Live demo and all test cases.

Pyth, 57 55 53 bytes

AQjd[G"is"@c"equal to
greater than
less than"b._-GHH)

This basically does:

["less than", "greater than", "equal to"][sign_of(A-B)]

Saved 2 bytes thanks to @AlexA.'s suggestion of using A instead of J and K and another 2 bytes by replacing the whole addition mess with a simpler subtraction.

Live demo and test cases.

55-byte version

AQjd[G"is"@c"less than
greater than
equal to"b+gGHqGHH)

Live demo and test cases.

57-byte version:

jd[JhQ"is"@c"less than
greater than
equal to"b+gJKeQqJKK)

Live demo and test cases.

O, 67 bytes

jJ" is ""greater than""less than""equal to"JjK-.e\1<+{@}d;;' K++++p

Live demo.

SWI-Prolog, 94 bytes

a(A,B):-(((A>B,C=greater;A<B,C=less),D=than);C=equal,D=to),writef("%t is %t %t %t",[A,C,D,B]).

Swift, 105 92 byte

func c(a:Int, b:Int){println("A is",(a==b ?"equal to":(a<b ?"less":"greater")," than"),"B")}

even shorter with Swift 2.0 (103 90 byte)

func c(a:Int, b:Int){print("A is",(a==b ?"equal to":(a<b ?"less":"greater")," than"),"B")}

Processing, 92 bytes

void c(int a,int b){print(a+" is "+(a>b?"greater than ":a<b?"lesser than ":"equal to ")+b);}