编写一个程序或函数，使用两个正整数（宽度和高度），并使用此25×26文本网格作为基本单元，绘制具有这些尺寸的ASCII艺术千鸟格网格模式：

.......#.....#####.......
.......##.....#####......
.......###.....#####.....
.......####.....####.....
.......#####.....###.....
.......######.....##.....
.......#######.....#.....
.......########..........
####################.....
.####################....
..####################...
...####################..
....####################.
.....####################
#.....##############.####
##.....#############..###
###....#############...##
####...#############....#
#####..#############.....
.#####.#############.....
..##################.....
........#####............
.........#####...........
..........#####..........
...........#####.........
............#####........

因此，如果输入为2,1输出，则将为：

.......#.....#####..............#.....#####.......
.......##.....#####.............##.....#####......
.......###.....#####............###.....#####.....
.......####.....####............####.....####.....
.......#####.....###............#####.....###.....
.......######.....##............######.....##.....
.......#######.....#............#######.....#.....
.......########.................########..........
####################.....####################.....
.####################.....####################....
..####################.....####################...
...####################.....####################..
....####################.....####################.
.....####################.....####################
#.....##############.#####.....##############.####
##.....#############..#####.....#############..###
###....#############...#####....#############...##
####...#############....#####...#############....#
#####..#############.....#####..#############.....
.#####.#############......#####.#############.....
..##################.......##################.....
........#####....................#####............
.........#####....................#####...........
..........#####....................#####..........
...........#####....................#####.........
............#####....................#####........

如果输入是5,4输出，则将是：

.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........
.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........
.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........
.......#.....#####..............#.....#####..............#.....#####..............#.....#####..............#.....#####.......
.......##.....#####.............##.....#####.............##.....#####.............##.....#####.............##.....#####......
.......###.....#####............###.....#####............###.....#####............###.....#####............###.....#####.....
.......####.....####............####.....####............####.....####............####.....####............####.....####.....
.......#####.....###............#####.....###............#####.....###............#####.....###............#####.....###.....
.......######.....##............######.....##............######.....##............######.....##............######.....##.....
.......#######.....#............#######.....#............#######.....#............#######.....#............#######.....#.....
.......########.................########.................########.................########.................########..........
####################.....####################.....####################.....####################.....####################.....
.####################.....####################.....####################.....####################.....####################....
..####################.....####################.....####################.....####################.....####################...
...####################.....####################.....####################.....####################.....####################..
....####################.....####################.....####################.....####################.....####################.
.....####################.....####################.....####################.....####################.....####################
#.....##############.#####.....##############.#####.....##############.#####.....##############.#####.....##############.####
##.....#############..#####.....#############..#####.....#############..#####.....#############..#####.....#############..###
###....#############...#####....#############...#####....#############...#####....#############...#####....#############...##
####...#############....#####...#############....#####...#############....#####...#############....#####...#############....#
#####..#############.....#####..#############.....#####..#############.....#####..#############.....#####..#############.....
.#####.#############......#####.#############......#####.#############......#####.#############......#####.#############.....
..##################.......##################.......##################.......##################.......##################.....
........#####....................#####....................#####....................#####....................#####............
.........#####....................#####....................#####....................#####....................#####...........
..........#####....................#####....................#####....................#####....................#####..........
...........#####....................#####....................#####....................#####....................#####.........
............#####....................#####....................#####....................#####....................#####........

• width参数必须放在第一位。任何合理的输入格式（例如w,h，w h，(w, h)）是好的。
• 使用可选的尾随换行符打印或返回结果。
• 您可以使用任意两个不同的可打印ASCII字符代替.和#。
• 您可以垂直或水平平移基本单元，就像它具有周期性边界条件一样。因此，输出的左上角不一定是的7×8矩形.。（新规则！）

以字节为单位的最短代码获胜。

另外，请生成图像，而不是每个.图像都是一种颜色的像素，而每个#图像都是另一种颜色的像素。

Pyth，61 60 55 49字节

j*vwmjk*Qd++Rm012Jmms}k++Rhd5U-d4T=T13+Lm1T_mP_dJ

在线试用：演示

编辑1：结合两个语句生成带和三角形（请参见下文）

编辑2：没有看到我们可以使用任何符号。保存了5个字节

编辑3：@ Calvin'sHobbies允许翻译基本图像。由于我的方法是基于这个想法，因此很有帮助。-6个字节

对于Cookie奖励：

.w*vw*RQ++Rm012Jmm*K255}k++Rhd5U-d4T=T13+LmKT_mP_dJ

仅增加2个字节（51个字节）并生成文件o.png。对于输入，5\n4它将生成以下图片：

说明：

千鸟格图案看起来确实很不规则。但是，如果我们将左边的7列移到右边，将最上面的5列移到波顿，我们会得到一个更好的模式：

.#####...................
..#####..................
...#####.................
....#####................
.....#####...............
#.....#####..............
##.....#####.............
###.....#####............
####.....####............
#####.....###............
######.....##............
#######.....#............
########.................
#############.....#######
##############.....######
###############.....#####
################.....####
#################.....###
##################.....##
#############.#####.....#
#############..#####.....
#############...#####....
#############....#####...
#############.....#####..
#############......#####.
#############.......#####

首先，我生成左上方的13x13块：

.#####.......
..#####......
...#####.....
....#####....
.....#####...
#.....#####..
##.....#####.
###.....#####
####.....####
#####.....###
######.....##
#######.....#
########.....

有两个简单的不等式，描述了两个#区域。频段可以用描述，y + 1 <= x <= y + 5三角形可以用描述x <= y - 5。我已经结合了这两个条件：

Jmms}k++Rhd5U-d4T=T13
                 =T13   T = 13
 m               T      map each d of [0, 1, ..., 12] to: 
                           the list produced by
  m             T          map each k of [0, 1, ..., 12] to:
       +Rhd5                  the list [d+1, d+2, ..., d+5]
      +                       extended by 
            U-d4              the list [0, 1, ..., d - 5]
    }k                        test if k is in the list
   s                          and convert the boolean result to 1 or 0
J                       assign this 13x13 block to J

然后+Rm012在每行的末尾添加12个零，以获取较高的25x13块。

较低的25x13块现在非常简单：

+Lm1T_mP_dJ
      m   J    map each row d of J to:
       P_d        reverse the row and pop the last element
     _         reverse the order the rows
+Lm1T          add T ones at the beginning of each row. 

现在剩下的就是重复图案并打印

j*vwmjk*Qd+upperlower   implicit: Q = first input number
          +upperlower   combine the two blocks to a 25x26 block
    m                   map each row d to:
       *Qd                 repeat d Q times
     jk                    and join to a string
 *vw                    read another number from input and repeat
j                       join by newlines and print

Cookie奖励代码的区别：

• 255 代替 1
• 而不是mjk*Qd使用*RQ，因为我不需要字符串
• .w 将此2D数组保存到文件（将其隐式转换为png）

CJam，106 73 71字节

0000000: 71 7e 22 04 94 51 af 40 6e 73 b2 68 3a e1 7e 13 f2 a1  q~"..Q.@ns.h:.~...
0000012: 3e 1d de f5 64 9c 6b 0f 27 4c 36 d7 81 3d 30 35 56 f8  >...d.k.'L6..=05V.
0000024: cd e8 cd 7c dc 90 31 59 40 8b 8c 22 32 35 36 62 32 32  ...|..1Y@.."256b22
0000036: 62 41 73 33 39 2a 2e 2a 73 32 35 2f 2a 66 2a 4e 2a     bAs39*.*s25/*f*N*

打印1和0代替.和#。在CJam解释器中在线尝试。

怎么运行的

q~      e# Read and evaluate all input. This pushes W and H.
"…"     e# Push an encoding of run lengths of the characters in the output.
256b22b e# Convert from base 256 to base 22.
As39*   e# Push "10" and repeat it 39 times.
.*      e# Vectorized character repetition; multiply each base 22 digit (run
        e# length) by the corresponding character of "10…10".
s25/    e# Flatten and split into chunks of length 25.
*       e# Repeat the resulting array of rows H times.
f*      e# Repeat each row W times.
N*      e# Join the rows, separating by linefeeds.

Cookie奖金

0000000: 27 50 6f 31 70 71 7e 5d 5f 5b 32 35 5f 29 5d 2e 2a 5c  'Po1pq~]_[25_)].*\
0000012: 7e 22 04 94 51 af 40 6e 73 b2 68 3a e1 7e 13 f2 a1 3e  ~"..Q.@ns.h:.~...>
0000024: 1d de f5 64 9c 6b 0f 27 4c 36 d7 81 3d 30 35 56 f8 cd  ...d.k.'L6..=05V..
0000036: e8 cd 7c dc 90 31 59 40 8b 8c 22 32 35 36 62 32 32 62  ..|..1Y@.."256b22b
0000048: 41 73 33 39 2a 2e 2a 73 32 35 2f 2a 66 2a 73 2b 4e 2a  As39*.*s25/*f*s+N*

打印一个可移植的位图，而不是ASCII图形。

以下是input的输出24 13，已转换为PNG：

Befunge-93，2120 1967个字节

这是一些高质量的功能，带有用于调试的异常处理！

&&00p10pv
v       <
    >94+2*20p        v
>00g|   >                v
    @                >10g>0020gv-1:<
                               >:0`|
                     ,       v    $<
                     +        >v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v
 v_$1-:#^_$20g1-20p55^       >|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>"!DAB"....@
 ,:
 >^".......#.....#####......."                                                    <
  ^".......##.....#####......"                                                  <
  ^".......###.....#####....."                                                <
  ^".......####.....####....."                                              <
  ^".......#####.....###....."                                            <
  ^".......######.....##....."                                          <
  ^".......#######.....#....."                                        <
  ^".......########.........."                                      <
  ^"####################....."                                    <
  ^".####################...."                                  <
  ^"..####################..."                                <
  ^"...####################.."                              <
  ^"....####################."                            <
  ^".....####################"                          <
  ^"#.....##############.####"                        <
  ^"##.....#############..###"                      <
  ^"###....#############...##"                    <
  ^"####...#############....#"                  <
  ^"#####..#############....."                <
  ^".#####.#############....."              <
  ^"..##################....."            <
  ^"........#####............"          <
  ^".........#####..........."        <
  ^"..........#####.........."      <
  ^"...........#####........."    <
  ^"............#####........"  <
^                     p00-1g00<

（显然，这仍然很容易打高尔夫。我现在只想在这里得到答案）

因此，它由不同部分组成。

&&00p10p

这只是初始化程序，它接受值并将其存储

    >94+2*20p
>00g|      > 
    @  

本节将重置行数，因此我们可以并排打印另一张（宽度）图片。 94+2*正在计算26，即行数。同样，如果高度为零，程序将终止。

>10g

这将获得堆栈的宽度，因此我们知道要打印多少

0020gv-1:<
     >:0`|
         $

这会将两个伪值添加到堆栈中，以告知我们何时完成操作以及我们在哪一行（n）上。然后将n个值添加到堆栈中

>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v>v
|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>|>"!DAB"....@

                                                    <
                                                  <
                                                <
                                              <
                                            <
                                          <
                                        <
                                      <
                                    <
                                  <
                                <
                              <
                            <
                          <
                        <
                      <
                    <
                  <
                <
              <
            <
          <
        <
      <
    <
  <
<

这是一个将进入（26-n）行的控制部分。这是我弄清楚如何做的最简单的方法。

".......#.....#####......."
".......##.....#####......"
".......###.....#####....."
".......####.....####....."
".......#####.....###....."
".......######.....##....."
".......#######.....#....."
".......########.........."
"####################....."
".####################...."
"..####################..."
"...####################.."
"....####################."
".....####################"
"#.....##############.####"
"##.....#############..###"
"###....#############...##"
"####...#############....#"
"#####..#############....."
".#####.#############....."
"..##################....."
"........#####............"
".........#####..........."
"..........#####.........."
"...........#####........."
"............#####........"

显然，这将被读取，并将读取的所有行向后弹出到堆栈中。这意味着当我们弹出它时，它将正确打印。

v_
,:
>^

这将一直打印到堆栈达到0为止，我们之前已将其保留。

1-:#^_

这将从要打印的特定行的编号中减去1，然后检查其是否为零。如果它不为零，我们回到第四段代码。

          ,
          +
20g1-20p55^

这将从行（n）中减去1，打印换行符，然后返回到块3

p00-1g00

一旦所有行都打印完，这将从初始高度中减去1，然后返回到块2。

其余所有代码都是控制流或堆栈管理。写这个圣诞节比我想象的要多，但是我对它的外观感到满意。它更具打高尔夫球性，而且很可能会在未来的日子里成为一个项目。

2120年-> 1967年：用大量浪费的空间修剪了一些线条

Perl，243岁

（为-n开关从stdin获取输入添加了一个字节。）

($w,$h)=split;for(1..$h){print((sprintf("%025b",hex)x$w).$/)foreach qw(20f80 307c0 383e0 3c1e0 3e0e0 3f060 3f820 3fc00 1ffffe0 fffff0 7ffff8 3ffffc 1ffffe fffff 107ffef 183ffe7 1c3ffe3 1e3ffe1 1f3ffe0 fbffe0 7fffe0 1f000 f800 7c00 3e00 1f00)}

这是非常简单的-它所做的就是将26个十六进制数字的数组转换为二进制并打印出所需的次数。

例：

输入：

3 2

输出：

000000010000011111000000000000001000001111100000000000000100000111110000000
000000011000001111100000000000001100000111110000000000000110000011111000000
000000011100000111110000000000001110000011111000000000000111000001111100000
000000011110000011110000000000001111000001111000000000000111100000111100000
000000011111000001110000000000001111100000111000000000000111110000011100000
000000011111100000110000000000001111110000011000000000000111111000001100000
000000011111110000010000000000001111111000001000000000000111111100000100000
000000011111111000000000000000001111111100000000000000000111111110000000000
111111111111111111110000011111111111111111111000001111111111111111111100000
011111111111111111111000001111111111111111111100000111111111111111111110000
001111111111111111111100000111111111111111111110000011111111111111111111000
000111111111111111111110000011111111111111111111000001111111111111111111100
000011111111111111111111000001111111111111111111100000111111111111111111110
000001111111111111111111100000111111111111111111110000011111111111111111111
100000111111111111110111110000011111111111111011111000001111111111111101111
110000011111111111110011111000001111111111111001111100000111111111111100111
111000011111111111110001111100001111111111111000111110000111111111111100011
111100011111111111110000111110001111111111111000011111000111111111111100001
111110011111111111110000011111001111111111111000001111100111111111111100000
011111011111111111110000001111101111111111111000000111110111111111111100000
001111111111111111110000000111111111111111111000000011111111111111111100000
000000001111100000000000000000000111110000000000000000000011111000000000000
000000000111110000000000000000000011111000000000000000000001111100000000000
000000000011111000000000000000000001111100000000000000000000111110000000000
000000000001111100000000000000000000111110000000000000000000011111000000000
000000000000111110000000000000000000011111000000000000000000001111100000000
000000010000011111000000000000001000001111100000000000000100000111110000000
000000011000001111100000000000001100000111110000000000000110000011111000000
000000011100000111110000000000001110000011111000000000000111000001111100000
000000011110000011110000000000001111000001111000000000000111100000111100000
000000011111000001110000000000001111100000111000000000000111110000011100000
000000011111100000110000000000001111110000011000000000000111111000001100000
000000011111110000010000000000001111111000001000000000000111111100000100000
000000011111111000000000000000001111111100000000000000000111111110000000000
111111111111111111110000011111111111111111111000001111111111111111111100000
011111111111111111111000001111111111111111111100000111111111111111111110000
001111111111111111111100000111111111111111111110000011111111111111111111000
000111111111111111111110000011111111111111111111000001111111111111111111100
000011111111111111111111000001111111111111111111100000111111111111111111110
000001111111111111111111100000111111111111111111110000011111111111111111111
100000111111111111110111110000011111111111111011111000001111111111111101111
110000011111111111110011111000001111111111111001111100000111111111111100111
111000011111111111110001111100001111111111111000111110000111111111111100011
111100011111111111110000111110001111111111111000011111000111111111111100001
111110011111111111110000011111001111111111111000001111100111111111111100000
011111011111111111110000001111101111111111111000000111110111111111111100000
001111111111111111110000000111111111111111111000000011111111111111111100000
000000001111100000000000000000000111110000000000000000000011111000000000000
000000000111110000000000000000000011111000000000000000000001111100000000000
000000000011111000000000000000000001111100000000000000000000111110000000000
000000000001111100000000000000000000111110000000000000000000011111000000000
000000000000111110000000000000000000011111000000000000000000001111100000000

版本1，C，118115字节

i,x,y;f(w,h){for(i=26*h*(w*=25);i--;i%w||puts(""))x=i%25,y=i/w%26,putchar(((y>x^y>x+5^x>y+4)&y/13==x/13^y/13)+34);}

由于允许单元转换的新规则，节省了9个字节。使用节省3个字节w*=25。其余职位保持不变。

Rev 0，C，127字节

i,x,y;f(w,h){for(i=650*w*h;i--;i%(25*w)||puts(""))x=(i+20)%25,y=(i/25/w+8)%26,putchar(((y>x^y>x+5^x>y+4)&y/13==x/13^y/13)+34);}

这将遍历字符，并一一打印出来。i%(25*w)||puts("")在每行末尾插入一个换行符。

我查看设计的方式与Jakube相似，但我将顶部的8行排到底部，将5列的右移到左侧以得到以下视图。在程序中该步骤是通过“反向” +20和+8用于x和y的表达式。

"""""####################
#"""""###################
##"""""##################
###"""""#################
####"""""################
#####"""""###############
"#####"""""##############
""#####"""""#############
"""#####""""#############
""""#####"""#############
"""""#####""#############
""""""#####"#############
"""""""##################
"""""""""""""#####"""""""
""""""""""""""#####""""""
"""""""""""""""#####"""""
""""""""""""""""#####""""
"""""""""""""""""#####"""
""""""""""""#"""""#####""
""""""""""""##"""""#####"
""""""""""""###"""""#####
""""""""""""####"""""####
""""""""""""#####"""""###
""""""""""""######"""""##
""""""""""""#######"""""#
""""""""""""########"""""

除了“颜色反转”外，它看起来非常相似，但有一个重要区别：对角线条纹匹配。（请注意，原始设计的对角线对称性为25x26。）

该表达式((y>x^y>x+5^x>y+4)^y/13)+34产生以下内容，其中各种比较运算符产生条纹，^y/13产生中间值的“ color flip”，并+34取结果数0,1并将其提高到ASCII范围34,35。

"""""####################
#"""""###################
##"""""##################
###"""""#################
####"""""################
#####"""""###############
"#####"""""##############
""#####"""""#############
"""#####"""""############
""""#####"""""###########
"""""#####"""""##########
""""""#####"""""#########
"""""""#####"""""########
########"""""#####"""""""
#########"""""#####""""""
##########"""""#####"""""
###########"""""#####""""
############"""""#####"""
#############"""""#####""
##############"""""#####"
###############"""""#####
################"""""####
#################"""""###
##################"""""##
###################"""""#
####################"""""

该术语&y/13==x/13在右上角和左下角四分之一中的计算结果为false = 0，产生了模式的正方形部分，如前所示。请注意，由于程序递减计数，因此原点x = y = 0位于右下角。这很方便，因为的正方形#为13个字符宽，而的正方形"仅为12个字符宽。

Befunge -93，968个字节

是的，这是正确的！竞争的Befunge答案！

&:&\00p10p:520pv:g00p02<v  <
    #   p1*45-1_v#:" "  <  v
    |`-1*65:g02$<      ,
    >:" "\39*\p:" "\47 *v
+:"<"\39*\p:"v"\47*\p25^>\p 1
".......#.....#####......."<v
".......##.....#####......"
".......###.....#####....."
".......####.....####....."
".......#####.....###....."
".......######.....##....."
".......#######.....#....."
".......########.........."
"####################....."
".####################...."
"..####################..."
"...####################.."
"....####################."
".....####################"
"#.....##############.####"
"##.....#############..###"
"###....#############...##"
"####...#############....#"
"#####..#############....."
".#####.#############....."
"..##################....."
"........#####............"
".........#####..........."
"..........#####.........."
"...........#####........."
"............#####........"
,,,,,,,,,,,,,,,,,,,,,,,,,  v>
    > 10g1-:10p #v_@
 " " \47*\p5:"<"v>:" "\39*\ p
\*74 \"v":p\*93\<      v,*5 2p

解释一下，明天睡觉。但是，我会说，我通过移动几个重定向箭头来做一些聪明的事情，并且我也使用了wrap-around属性。在此在线解释器中进行测试。