Answers:
x[r,]
其中r是您感兴趣的行。请尝试以下操作,例如:
#Add your data
x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ),
B = c(4.25, 4, 4, 4.5, 4.5 ),
C = c(4.5, 2.5, 4, 2.25, 3 )
),
.Names = c("A", "B", "C"),
class = "data.frame",
row.names = c(NA, -5L)
)
#The vector your result should match
y<-c(A=5, B=4.25, C=4.5)
#Test that the items in the row match the vector you wanted
x[1,]==y
如果您不知道行号,但确实知道一些值,则可以使用子集
x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ),
B = c(4.25, 4, 4, 4.5, 4.5 ),
C = c(4.5, 2.5, 4, 2.25, 3 )
),
.Names = c("A", "B", "C"),
class = "data.frame",
row.names = c(NA, -5L)
)
subset(x, A ==5 & B==4.25 & C==4.5)
subset(x, A ==5 & B==4.25 & C==4.5)
10年后--->使用tidyverse,我们可以简单地实现这一点,并从Christopher Bottoms借用一片叶子。要更好地掌握,请参阅slice()
。
library(tidyverse)
x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ),
B = c(4.25, 4, 4, 4.5, 4.5 ),
C = c(4.5, 2.5, 4, 2.25, 3 )
),
.Names = c("A", "B", "C"),
class = "data.frame",
row.names = c(NA, -5L)
)
x
#> A B C
#> 1 5.00 4.25 4.50
#> 2 3.50 4.00 2.50
#> 3 3.25 4.00 4.00
#> 4 4.25 4.50 2.25
#> 5 1.50 4.50 3.00
y<-c(A=5, B=4.25, C=4.5)
y
#> A B C
#> 5.00 4.25 4.50
#The slice() verb allows one to subset data row-wise.
x <- x %>% slice(1) #(n) for the nth row, or (i:n) for range i to n, (i:n()) for i to last row...
x
#> A B C
#> 1 5 4.25 4.5
#Test that the items in the row match the vector you wanted
x[1,]==y
#> A B C
#> 1 TRUE TRUE TRUE
由reprex软件包(v0.3.0)创建于2020-08-06