Answers:
用途head
:
dnow <- data.frame(x=rnorm(100), y=runif(100))
head(dnow,4) ## default is 6
使用索引:
df[1:4,]
括号中的值可以解释为逻辑,数字或字符(与相应的名称匹配):
df[row.index, column.index]
阅读help(`[`)以获得有关此主题的更多详细信息,并在R简介中阅读有关索引矩阵的信息。
df[1:4, "Response"]
。
如果少于4行,则可以使用head
函数(head(data, 4)
或head(data, n=4)
),它的作用就像一个超级按钮。但是,假设我们有以下具有15行的数据集
>data <- data <- read.csv("./data.csv", sep = ";", header=TRUE)
>data
LungCap Age Height Smoke Gender Caesarean
1 6.475 6 62.1 no male no
2 10.125 18 74.7 yes female no
3 9.550 16 69.7 no female yes
4 11.125 14 71.0 no male no
5 4.800 5 56.9 no male no
6 6.225 11 58.7 no female no
7 4.950 8 63.3 no male yes
8 7.325 11 70.4 no male no
9 8.875 15 70.5 no male no
10 6.800 11 59.2 no male no
11 6.900 12 59.3 no male no
12 6.100 13 59.4 no male no
13 6.110 14 59.5 no male no
14 6.120 15 59.6 no male no
15 6.130 16 59.7 no male no
假设您要选择前10行。最简单的方法是data[1:10, ]
。
> data[1:10,]
LungCap Age Height Smoke Gender Caesarean
1 6.475 6 62.1 no male no
2 10.125 18 74.7 yes female no
3 9.550 16 69.7 no female yes
4 11.125 14 71.0 no male no
5 4.800 5 56.9 no male no
6 6.225 11 58.7 no female no
7 4.950 8 63.3 no male yes
8 7.325 11 70.4 no male no
9 8.875 15 70.5 no male no
10 6.800 11 59.2 no male no
但是,假设您尝试检索前19行并查看会发生什么-您将缺少值
> data[1:19,]
LungCap Age Height Smoke Gender Caesarean
1 6.475 6 62.1 no male no
2 10.125 18 74.7 yes female no
3 9.550 16 69.7 no female yes
4 11.125 14 71.0 no male no
5 4.800 5 56.9 no male no
6 6.225 11 58.7 no female no
7 4.950 8 63.3 no male yes
8 7.325 11 70.4 no male no
9 8.875 15 70.5 no male no
10 6.800 11 59.2 no male no
11 6.900 12 59.3 no male no
12 6.100 13 59.4 no male no
13 6.110 14 59.5 no male no
14 6.120 15 59.6 no male no
15 6.130 16 59.7 no male no
NA NA NA NA <NA> <NA> <NA>
NA.1 NA NA NA <NA> <NA> <NA>
NA.2 NA NA NA <NA> <NA> <NA>
NA.3 NA NA NA <NA> <NA> <NA>
并使用head()函数,
> head(data, 19) # or head(data, n=19)
LungCap Age Height Smoke Gender Caesarean
1 6.475 6 62.1 no male no
2 10.125 18 74.7 yes female no
3 9.550 16 69.7 no female yes
4 11.125 14 71.0 no male no
5 4.800 5 56.9 no male no
6 6.225 11 58.7 no female no
7 4.950 8 63.3 no male yes
8 7.325 11 70.4 no male no
9 8.875 15 70.5 no male no
10 6.800 11 59.2 no male no
11 6.900 12 59.3 no male no
12 6.100 13 59.4 no male no
13 6.110 14 59.5 no male no
14 6.120 15 59.6 no male no
15 6.130 16 59.7 no male no
希望有帮助!
对于在DataFrame中,您只需键入
head(data, num=10L)
例如获得前10个。
对于data.frame,只需键入
head(data, 10)
得到第一个10。