题
如何在Java 8中创建合适的后台加载程序?条件:
- 数据应在后台加载
- 加载后应显示数据
- 加载数据时,不应接受其他任何请求
- 如果在加载数据时有请求,则应在某个超时(例如5秒)后安排另一次加载
目的是例如使重载请求被接受,但数据库不被请求所淹没。
MCVE
这是MCVE。它由一个后台任务组成,该任务通过简单地调用Thread.sleep 2秒钟来模拟加载。每秒安排一次任务,这自然会导致后台加载任务重叠,应避免。
public class LoadInBackgroundExample {
/**
* A simple background task which should perform the data loading operation. In this minimal example it simply invokes Thread.sleep
*/
public static class BackgroundTask implements Runnable {
private int id;
public BackgroundTask(int id) {
this.id = id;
}
/**
* Sleep for a given amount of time to simulate loading.
*/
@Override
public void run() {
try {
System.out.println("Start #" + id + ": " + Thread.currentThread());
long sleepTime = 2000;
Thread.sleep( sleepTime);
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
System.out.println("Finish #" + id + ": " + Thread.currentThread());
}
}
}
/**
* CompletableFuture which simulates loading and showing data.
* @param taskId Identifier of the current task
*/
public static void loadInBackground( int taskId) {
// create the loading task
BackgroundTask backgroundTask = new BackgroundTask( taskId);
// "load" the data asynchronously
CompletableFuture<String> completableFuture = CompletableFuture.supplyAsync(new Supplier<String>() {
@Override
public String get() {
CompletableFuture<Void> future = CompletableFuture.runAsync(backgroundTask);
try {
future.get();
} catch (InterruptedException | ExecutionException e) {
e.printStackTrace();
}
return "task " + backgroundTask.id;
}
});
// display the data after they are loaded
CompletableFuture<Void> future = completableFuture.thenAccept(x -> {
System.out.println( "Background task finished:" + x);
});
}
public static void main(String[] args) {
// runnable which invokes the background loader every second
Runnable trigger = new Runnable() {
int taskId = 0;
public void run() {
loadInBackground( taskId++);
}
};
// create scheduler
ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(1);
ScheduledFuture<?> beeperHandle = scheduler.scheduleAtFixedRate(trigger, 0, 1, TimeUnit.SECONDS);
// cancel the scheudler and the application after 10 seconds
scheduler.schedule(() -> beeperHandle.cancel(true), 10, TimeUnit.SECONDS);
try {
beeperHandle.get();
} catch (Throwable th) {
}
System.out.println( "Cancelled");
System.exit(0);
}
}
输出是这样的:
Start #0: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Start #1: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Start #2: Thread[ForkJoinPool.commonPool-worker-6,5,main]
Finish #0: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Background task finished:task 0
Finish #1: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Background task finished:task 1
Start #3: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Finish #2: Thread[ForkJoinPool.commonPool-worker-6,5,main]
Background task finished:task 2
Start #4: Thread[ForkJoinPool.commonPool-worker-6,5,main]
Start #5: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Finish #3: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Background task finished:task 3
Start #6: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Finish #4: Thread[ForkJoinPool.commonPool-worker-6,5,main]
Background task finished:task 4
Finish #5: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Background task finished:task 5
Start #7: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Finish #6: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Start #8: Thread[ForkJoinPool.commonPool-worker-6,5,main]
Background task finished:task 6
Start #9: Thread[ForkJoinPool.commonPool-worker-4,5,main]
Finish #7: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Background task finished:task 7
Start #10: Thread[ForkJoinPool.commonPool-worker-2,5,main]
Finish #8: Thread[ForkJoinPool.commonPool-worker-6,5,main]
Background task finished:task 8
Cancelled
目标是例如#1和#2因为#0仍在运行而被跳过。
问题
您在哪里正确设置阻止机制?应该使用同步吗?还是一些AtomicBoolean
?如果是这样,它应该在get()
方法内部还是其他地方?
ExecutorService
过线程池大小为1的?
BlockingQueue
吗?