我有2个矩阵,我需要将它们相乘,然后打印每个单元格的结果。准备好一个单元格后,我就需要打印它,但是例如,即使[2] [0]的结果先准备好,我也需要在单元格[2] [0]之前打印[0] [0]单元格。所以我需要按顺序打印它。所以我的想法是让打印机线程等待,直到multiplyThread
通知它准备打印正确的单元格,然后printerThread
它将打印该单元格并返回等待状态,依此类推。
所以我有这个线程做乘法:
public void run()
{
int countNumOfActions = 0; // How many multiplications have we done
int maxActions = randomize(); // Maximum number of actions allowed
for (int i = 0; i < size; i++)
{
result[rowNum][colNum] = result[rowNum][colNum] + row[i] * col[i];
countNumOfActions++;
// Reached the number of allowed actions
if (countNumOfActions >= maxActions)
{
countNumOfActions = 0;
maxActions = randomize();
yield();
}
}
isFinished[rowNum][colNum] = true;
notify();
}
打印每个单元格结果的线程:
public void run()
{
int j = 0; // Columns counter
int i = 0; // Rows counter
System.out.println("The result matrix of the multiplication is:");
while (i < creator.getmThreads().length)
{
synchronized (this)
{
try
{
this.wait();
}
catch (InterruptedException e1)
{
}
}
if (creator.getmThreads()[i][j].getIsFinished()[i][j] == true)
{
if (j < creator.getmThreads()[i].length)
{
System.out.print(creator.getResult()[i][j] + " ");
j++;
}
else
{
System.out.println();
j = 0;
i++;
System.out.print(creator.getResult()[i][j] + " ");
}
}
}
现在它抛出了这些异常:
Exception in thread "Thread-9" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-6" Exception in thread "Thread-4" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-5" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-8" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-7" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-11" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-10" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
Exception in thread "Thread-12" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at multiplyThread.run(multiplyThread.java:49)
第49行multiplyThread
是“ notify()”。我想我需要以不同的方式使用synced,但是我不确定如何使用。
如果有人可以帮助该代码正常工作,我将非常感谢。
while(!JobCompleted);
选项通常不是一个好主意,因为它会以100%的速度将CPU占用,并不断检查同一变量(请参见此处)