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遍历字符串中所有字符的最快方法
在Java中,迭代字符串中所有字符的最快方法是: String str = "a really, really long string"; for (int i = 0, n = str.length(); i < n; i++) { char c = str.charAt(i); } 或这个: char[] chars = str.toCharArray(); for (int i = 0, n = chars.length; i < n; i++) { char c = chars[i]; } …