您如何编写在计算机关闭或重新启动后正常关闭的systemd服务?特别是,它应该延迟机器关闭,直到正常退出为止。
我有一个需要10秒钟才能关闭的服务:/usr/local/bin/shutdowntest.sh:
#!/bin/bash
SHUTDOWN=0
SHUTDOWN_TIME=10
TRAPPED_SIGNAL=
function onexit() {
TRAPPED_SIGNAL=$1
SHUTDOWN=1
}
for SIGNAL in SIGINT SIGTERM SIGHUP SIGPIPE SIGALRM SIGUSR1 SIGUSR2; do
trap "onexit $SIGNAL" $SIGNAL
done
echo >&2 "shutdowntest running"
while ((!SHUTDOWN || SHUTDOWN_TIME>0)); do
if [[ -n "$TRAPPED_SIGNAL" ]]; then
echo >&2 "shutdowntest received signal $TRAPPED_SIGNAL"
TRAPPED_SIGNAL=
elif ((SHUTDOWN)); then
echo >&2 "shutdowntest Shutting down: $SHUTDOWN_TIME more sleeps"
SHUTDOWN_TIME=$((SHUTDOWN_TIME-1))
sleep 1
else
sleep 10
fi
done
echo >&2 "shutdowntest Finished shutting down; quitting"
我在/etc/systemd/system/shutdowntest.service中将TimeoutStopSec设置为15s:
[Service]
ExecStart=/usr/local/bin/shutdowntest.sh
TimeoutStopSec=15
[Install]
WantedBy=multi-user.target
当我运行时sudo systemctl stop shutdowntest.service
,服务会根据/var/log/syslog
以下内容正常关闭:
00:57:11 shutdowntest.sh[1980]: shutdowntest received signal SIGTERM
00:57:11 shutdowntest.sh[1980]: shutdowntest Shutting down: 10 more sleeps
00:57:11 systemd[1]: Stopping shutdowntest.service...
00:57:11 shutdowntest.sh[1980]: Terminated
00:57:11 shutdowntest.sh[1980]: shutdowntest Shutting down: 9 more sleeps
00:57:12 shutdowntest.sh[1980]: shutdowntest Shutting down: 8 more sleeps
00:57:13 shutdowntest.sh[1980]: shutdowntest Shutting down: 7 more sleeps
00:57:14 shutdowntest.sh[1980]: shutdowntest Shutting down: 6 more sleeps
00:57:15 shutdowntest.sh[1980]: shutdowntest Shutting down: 5 more sleeps
00:57:16 shutdowntest.sh[1980]: shutdowntest Shutting down: 4 more sleeps
00:57:17 shutdowntest.sh[1980]: shutdowntest Shutting down: 3 more sleeps
00:57:18 shutdowntest.sh[1980]: shutdowntest Shutting down: 2 more sleeps
00:57:19 shutdowntest.sh[1980]: shutdowntest Shutting down: 1 more sleeps
00:57:20 shutdowntest.sh[1980]: shutdowntest Finished shutting down; quitting
00:57:20 systemd[1]: Stopped shutdowntest.service.
但是当我sudo reboot
或sudo shutdown now
机器时,服务被杀死,没有足够的时间正常退出,并且/ var / log / syslog仅在1s之后结束。
00:59:30 shutdowntest.sh[2014]: Terminated
00:59:30 shutdowntest.sh[2014]: shutdowntest received signal SIGTERM
00:59:30 shutdowntest.sh[2014]: shutdowntest Shutting down: 10 more sleeps
00:59:30 systemd[1]: Stopping shutdowntest.service...
如何确保在关闭或重新启动计算机后给服务指定的退出时间(TimeoutSec
或时间TimeoutStopSec
)?
journalctl -u shutdowntest.service
)中进行检查,而不是直接查看/var/log/syslog
吗?我想知道syslog是否在您提供服务之前没有停止,然后没有记录其余输出