1P5：地震！

USGS的地震仪刚刚发现了大地震！紧急响应小组需要快速估算受影响的人数。编写一个程序来计算这个估计。

您的程序收到2个输入。首先是地震本身的细节。地震模拟为一条线段，地球沿着该线段破裂，以及距断层的临界距离，在该距离内可能会造成破坏。第二个输入是该地区城市的位置和人口清单。您的程序应计算出受影响区域中的人口数量，即故障段关键距离内所有城市的人口总数。

输入值

首先是描述地震的线，其中包含断层起点和终点的x，y坐标以及临界距离。格式为A_x A_y B_x B_y D。例如：

3.0 3.0 7.0 4.0 2.5

编码从（3.0,3.0）扩展到（7.0,4.0）且临界距离为2.5的故障。

其次，该区域中每个城市的一行，包含城市及其人口的x，y坐标。例如：

1.0 1.0 2500
5.0 7.0 8000
3.0 4.0 7500
9.0 6.0 3000
4.0 2.0 1000

输出量

居住在受影响地区的人数。对于上面的示例，只有第三和第五座城市处于危险区域，因此输出为

8500

最短的代码获胜。

例子2

0.0 0.0 10.0 0.0 5.0
5.0 4.0 10000
5.0 -4.0 1000
5.0 6.0 100
11.0 2.0 10 
-4.0 4.0 1

产生

11010

红宝石，171 152 155 153

u,v,a,b,d=gets.split.map &:to_f
a-=u;b-=v
p eval$<.map{|l|"(x=%f-u;t=(a*x+b*y=%f-v)/(a*a+b*b);d*d<(x-a*t=t<0?0:t>1?1:t)**2+(y-t*b)**2?0:%d)"%l.split}*'+'

这是我第一次提交红宝石，也是我第一次提交代码高尔夫球。直接执行任务。请给我一些如何改进的提示（必须有更短的读取float的方法...）。

Javascript（437）

这可能是一个不错的选择，但不足以击败Ruby解决方案。

p=$("#i").text().split("\n");for(i=0;i<p.length;i++){p[i]=p[i].split(" ")}
z=p[0];a=z[0];b=z[1];c=z[2];d=z[3];e=z[4];o=0;f=[a,b];g=[c,d];
function q(r,s){return Math.sqrt(Math.pow(s[0]-r[0],2)+Math.pow(s[1]-r[1],2))}
for(i=1;i<p.length;i++){w=p[i];u=((w[0]-a)*(c-a)+(w[1]-b)*(d-b))/Math.pow(q(f,g,2),2);
x=[(a*1)+u*(c-a),(b*1)+u*(d-b)];l=e;m=w[2]*1;u=w[0];w=w[1];v=[u,w];
o+=q(v,x)<l&&q(x,g)+q(x,f)==q(f,g)?m:q(v,f)<l?m:q(v,g)<l?m:0}alert(o);

您可以在此处查看它的运行情况。

C＃ - 743 715

namespace System{using Linq;using m=Math;class P{public float X,Y;}class E{static void Main(){Func<string,float>p=s=>float.Parse(s);Func<P,P,double>d=(a,b)=>{return a.X*b.X+a.Y*b.Y;},c=(a,b)=>{return a.X*b.Y-a.Y*b.X;};Func<P,P,P>u=(a,b)=>{return new P{X=a.X-b.X,Y=a.Y-b.Y};};Func<P,P,P,double>g=(A,B,C)=>{return d(u(C,B),u(B,A))>0?m.Sqrt(d(u(B,C),u(B,C))):d(u(C,A),u(A,B))>0?m.Sqrt(d(u(A,C),u(A,C))):m.Abs(c(u(B,A),u(C,A))/m.Sqrt(d(u(B,A),u(B,A))));};var n=IO.File.ReadAllLines("i");var i=n[0].Split();var q=new{A=new P{X=p(i[0]),Y=p(i[1])},B=new P{X=p(i[2]),Y=p(i[3])},D=p(i[4])};Console.WriteLine((from l in n.Skip(1)let f=l.Split()let w=new P{X=p(f[0]),Y=p(f[1])}where g(q.A,q.B,w)<q.D select p(f[2])).Sum());}}}

非高尔夫球：

namespace System
{
    using Linq;
    using m = Math;
    class Point { public float X, Y;}
    class Earthquake
    {
        static void Main()
        {
            Func<string, float> parse = s => float.Parse(s);
            Func<Point, Point, double> dotProduct = (a, b) => { return a.X * b.X + a.Y * b.Y; }, 
                                       crossProduct = (a, b) => { return a.X * b.Y - a.Y * b.X; };
            Func<Point, Point, Point> subtract = (a, b) => { return new Point { X = a.X - b.X, Y = a.Y - b.Y }; };
            Func<Point, Point, Point, double> getDistance = (A, B, C) => { 
                return dotProduct(subtract(C, B), subtract(B, A)) > 0 ? 
                        m.Sqrt(dotProduct(subtract(B, C), subtract(B, C))) : 
                        dotProduct(subtract(C, A), subtract(A, B)) > 0 ? 
                            m.Sqrt(dotProduct(subtract(A, C), subtract(A, C))) : 
                            m.Abs(crossProduct(subtract(B, A), subtract(C, A)) / m.Sqrt(dotProduct(subtract(B, A), subtract(B, A)))); 
            };
            var inputLines = IO.File.ReadAllLines("i"); 
            var quakeLine = inputLines[0].Split(); 
            var quake = new { 
                PointA = new Point { X = parse(quakeLine[0]), Y = parse(quakeLine[1]) }, 
                PointB = new Point { X = parse(quakeLine[2]), Y = parse(quakeLine[3]) }, 
                Distance = parse(quakeLine[4]) 
            };
            var affectedPopulations = (from line in inputLines.Skip(1) 
                                       let fields = line.Split() 
                                       let location = new Point { X = parse(fields[0]), Y = parse(fields[1]) } 
                                       let population = parse(fields[2])
                                       where getDistance(quake.PointA, quake.PointB, location) < quake.Distance 
                                       select population);
            Console.WriteLine(affectedPopulations.Sum());
        }
    }
}

c-471个字符

#include <stdio.h>
#define F float
#define G getline(&v,&l,stdin)
F a[2],b[2],c[2],d[2],e[2],r,t,y,z;char*v;size_t l,n,p;
F s(F u[2],F v[2]){y=u[0]-v[0];z=u[1]-v[1];return y*y+z*z;}
j(F g[2],F h[2],F i[2]){*i=*g-*h;i[1]=g[1]-h[1];}
int i(){j(b,a,d);j(c,a,e);t=*d**e+d[1]*e[1];
return s(a,c)<=r||s(b,c)<=r||t>0&&t/s(a,b)<=1&&s(a,c)-t*t/s(a,b)<=r;}
int main(){G;sscanf(v,"%f %f %f %f %f",a,a+1,b,b+1,&r);r*=r;
while(G!=-1)sscanf(v,"%f %f %i",c,c+1,&p),n+=p*i();printf("%d\n",n);}

假定您的标准库有getline。

该方法在非高尔夫版本的注释中有所阐明：

#include <stdio.h>

float a[2],b[2],c[2],d[2],e[2],r,t,y,z;
char*v;
size_t l,n,p;
float s(float u[2],float v[2]){ /* returns the square of the distance
                   between two points */
  y=u[0]-v[0];
  z=u[1]-v[1];
  return y*y+z*z;
}
j(float g[2],float h[2],float i[2]){ /* sets i=g-h */
  i[0]=g[0]-h[0];
  i[1]=g[1]-h[1];
}
int i/*sCLose*/(){
  j(b,a,d); /* d=b-a */
  j(c,a,e); /* e=c-a */
  t=d[0]*e[0]+d[1]*e[1]; /* dot product */ 
  return 
    (s(a,c)<=r) || /* near one end point */
    (s(b,c)<=r) || /* near the other */
    (  
     (t>0) && /* C lies more "towards" B than away */
     (t/s(a,b)<=1) && /* Nearest point on AB to C lies between A and B */
     (s(a,c)-t*t/s(a,b)<=r) /* length of the altitude less than R */
       ); 
}
int main(){
  getline(&v,&l,stdin);
  sscanf(v,"%f %f %f %f %f",a,a+1,b,b+1,&r);
  r*=r; /* r is now r squared, as that is the only way we use it */
  printf("(%f, %f); (%f, %f): %f\n",a[0],a[1],b[0],b[1],r);
  while (getline(&v,&l,stdin) != -1){
    sscanf(v,"%f %f %i",c,c+1,&p);
    printf("\t (%f, %f): %d\n",c[0],c[1],p);
    n+=p*i/*sClose*/();
  }
  printf("%d\n",n);
}

标量：660个字符：

object E extends App{
type I=Int
type D=Double
def b(h:D,i:D,x:I,y:I,d:D)=(x-h)*(x-h)+(y-i)*(y-i)<=d*d
def a(p:java.awt.Polygon,x:I,y:I,h:I,i:I,d:D,r:Array[String])={
val w=r(0).toDouble
val j=r(1).toDouble
val n=r(2).toInt
if (p.contains(w,j)||b(j,w,x,y,d)||b(j,w,i,h,d))n
else 0}
val s=new java.util.Scanner(System.in)
val b=s.nextLine.split(" ")
val c=b.map(_.toDouble)
val e=c.map(_.toInt)
val(x,h,y,i,d)=(e(0),e(2),e(1),e(3),c(4))
val f=List(x,h)
val g=List(y,i)
val p=new java.awt.Polygon((f:::f.reverse).toArray,(g.map(_-e(4)):::g.reverse.map(_+e(4))).toArray,4)
var r=0
while(s.hasNext){
val row=s.nextLine
r+=a(p,x,y,h,i,d,row.split(" "))}
println(r)}

松开

object Earthquake extends App {

  def bowContains (h: Double, i: Double, x:Int, y:Int, d: Double) : Boolean = {
    (x-h)*(x-h) + (y-i)*(y-i) <= d*d
  }

  import java.awt._    

  def affected (polygon: Polygon, x:Int, y:Int, h: Int, i: Int, d: Double, row: Array[String]) : Int = {
    val w = row (0).toDouble 
    val j = row (1).toDouble 
    val population = row (2).toInt
    if (polygon.contains (w, j) || bowContains (j, w, x, y, d) || bowContains (j, w, i, h, d))
      population 
    else 0 
  }
  val sc = new java.util.Scanner (System.in)
  val line = sc.nextLine.split (" ")

  val li = line.map (_.toDouble)
  val ll = li.map (_.toInt)

  val (x, h, y, i, d) = (ll (0), ll (2), ll (1), ll (3), li(4))
  val xs = List (x, h)
  val ys = List (y, i)

  val polygon = new Polygon ((xs ::: xs.reverse).toArray, (ys.map (_ - ll(4)) ::: ys.reverse.map (_ + ll(4))).toArray, 4)
  var res = 0 
  while (sc.hasNext) {
    val row = sc.nextLine
    println ("line: " + line) 
    res += affected (polygon, x, y, h, i, d, row.split (" "))     
  } 
  println (res)
}